A researcher was analyzing a data set from an initial rate experiment for the reaction of baking soda and vinegar at 25°C. NaHCO3 + HC2H02 CO2 + H2O+ NaC2H3O2 Experiment [NaHCO3]. M[HC2H302). Mrate (M/s) 1 3.000 0.0360 0.0180 0.0090 0.400 1.500 0.400 3 0.750 0.400 The researcher suggested the following rate law based on these results: rate = k[NaHCO3], with a k 0.012 s. Do you agree with the researchers conclusion, why or why not. © CHEM1212
A researcher was analyzing a data set from an initial rate experiment for the reaction of baking soda and vinegar at 25°C. NaHCO3 + HC2H02 CO2 + H2O+ NaC2H3O2 Experiment [NaHCO3]. M[HC2H302). Mrate (M/s) 1 3.000 0.0360 0.0180 0.0090 0.400 1.500 0.400 3 0.750 0.400 The researcher suggested the following rate law based on these results: rate = k[NaHCO3], with a k 0.012 s. Do you agree with the researchers conclusion, why or why not. © CHEM1212
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A researcher was analyzing a data set from an initial rate experiment for the reaction
of baking soda and vinegar at 25°C.
NaHCO3 + HC2H3O2
CO2 + H20 + NaC2H3O2
Experiment [NaHCOgl. M[HC2H3O2), Mrate (M/s)
3.000
1.500
0.750
0.400
0.400
0.0360
0.0180
3
0.400
0.0090
The researcher suggested the following rate law based on these results: rate =
k[NaHCO), with a k 0.012 s. Do you agree with the researchers conclusion, why
or why not. O CHEM1212](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9097f05f-c15b-4224-8e03-ab5923cec1a5%2Ff02465d1-e9b3-4b7c-9706-ecc06ecf6419%2F9bwqzaq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A researcher was analyzing a data set from an initial rate experiment for the reaction
of baking soda and vinegar at 25°C.
NaHCO3 + HC2H3O2
CO2 + H20 + NaC2H3O2
Experiment [NaHCOgl. M[HC2H3O2), Mrate (M/s)
3.000
1.500
0.750
0.400
0.400
0.0360
0.0180
3
0.400
0.0090
The researcher suggested the following rate law based on these results: rate =
k[NaHCO), with a k 0.012 s. Do you agree with the researchers conclusion, why
or why not. O CHEM1212
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