Reaction Conc. Na2S203 Conc. HCI A Abs. A Time (s) Rate (A Abs./BA Time) 1.007568 0.300349 0.01870913 1 0.10 M .30 M 1.3686611 1.358380874 2 0.10 M .15 M 1.5360817 5.114311671 3 0.050 M .30 M 1.2267196 65.56796601 4 0.025 M .30 M 0.9563164 0.02870913 11.3085840 POSTLAB QUESTIONS 2. Compare the rates of reactions 1 and 2. What is effect on the reaction rate of halving the acid concentration? What is the order of the reaction in hydrochloric acid?

Reaction Conc. Na2S203 Conc. HCI A Abs. A Time (s) Rate (A Abs./BA Time) 1.007568 0.300349 0.01870913 1 0.10 M .30 M 1.3686611 1.358380874 2 0.10 M .15 M 1.5360817 5.114311671 3 0.050 M .30 M 1.2267196 65.56796601 4 0.025 M .30 M 0.9563164 0.02870913 11.3085840 POSTLAB QUESTIONS 2. Compare the rates of reactions 1 and 2. What is effect on the reaction rate of halving the acid concentration? What is the order of the reaction in hydrochloric acid?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

ス3 45 Mass of Cu(NO,),.3H;O 2.3366 Volume of Deionized H,0 57.0 Concentration of Cu* Solution Moles Cu* TRIAL # Initial Temperature Final Temperature qreaction reaction- 23.25 AH. .14 24.96 24.14 24.96 とL'Sで 25.72 25.70 ○L'Sで 24.99 24.98 24.98 25.14 .14 24.98 8. 9. 10 Average Bond Energy Coordination Number of Cu²*
The instantaneous rate of a chemical reaction is independent of time. True False
At 40^0c, H202 (aq) will decompose according to the foll. reaction: 2 H202 (aq) ----2H20(l) +02 (g) The foll. data were collected for the concentration of h202 at various times. Time. [H202] (mol/L) 0. 1.600 3.10*10^4 0.592 6.20*10^4. 0.219 (a) Calculate the average rate of decomposition in H202 between0 and 3.10 * 10^4 s. use this rate to calculate the average rate of production 02 (g) over the same time period. (b) What are these rates for the time period 3.10*10^4 s. to 6.20 *10^4 s.? Rate of H202 decomposition Rate of O2 Production
I need to calculate the average value of K. Could you please show all the steps.
For the following reaction 5 experiments have been run and the data collected is in the following table: 4 HBr(g) + O2(g)--->2 Br2(g) + 2 H2O(g) Experiment [HBr], M [O2 ], M Rate, M/s (aka mol/L.s) 1 0.120 0.490 0.0267 2 0.142 0.120 0.00190 3 0.120 0.630 0.0442 4 0.230 0.630 0.0846 5 0.630 0.863 0.435 a)Write the rate expression. b) Calculate the rate constant, k c) If the concentration of HBr and O2 are 1.5 x 10-3 M and 3.25 x 10-3 respectively, what is the rate of the reaction?
3) Which of the following is NOT true about a catalyst? A.It may be homogeneous B. It speeds up the reverse reaction C. It is consumed D. It speeds up the forward reaction E. it may be heterogeneous
6. Three different sets of data of [A] versus time are given in the table below for the reaction A → products. Answer the following questions using the information given in the table. Time,s 0 25 50 75 100 125 200 250 [A], M 1.00 0.78 0.61 0.47 0.37 0.22 0.14 0.08 Time,s 0 25 50 75 100 || [A], M 1.00 0.75 0.50 0.25 0.00 c) What is the approximate half-life of the first order reaction? Time,s 0 25 50 75 100 125 200 250 d) What is the approximate initial rate of the second order reaction? ||| [A], M 1.00 0.80 0.67 0.57 0.50 0.40 0.33 0.29 6.3
Reaction Conc. Na2S½O3 Conc. HCI A Abs. A Time (s) Rate (A Abs./ga Time) 1.007568 0.300349 0.01870913 0.02870913 1 0.10 M .30 М 1.3686611 1.358380874 0.10 M .15 M 1.5360817 5.114311671 3 0.050 M .30 M 1.2267196 65.56796601 4 0.025 M .30 M 0.9563164 11.3085840 4. Use experimental data and the rate law to calculate a rate constant for each reaction 1, 2, 3, 4. How do the rate constants compare? Should they be the same or different? Discuss in your conclusions. Report the average value of your calculations. Be sure to include units in your rate constant. The rate law of the reaction is shown below: Rate = [Na2S2O3]-2