A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 students using Method 1 produces a testing average of 61. A sample of 156 students using Method 2 produces a testing average of 64.6. Assume that the population standard deviation for Method 1 is 18.53, while the population standard deviation for Method 2 is 13.43. Determine the 98 % confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 1 of 3: Find the point estimate for the true difference between the population means.

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 students using Method 1 produces a testing average of 61. A sample of 156 students using Method 2 produces a testing average of 64.6. Assume that the population standard deviation for Method 1 is 18.53, while the population standard deviation for Method 2 is 13.43. Determine the 98 % confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 1 of 3: Find the point estimate for the true difference between the population means.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter4: Equations Of Linear Functions

Section: Chapter Questions

Problem 8SGR

See similar textbooks

Related questions

Q: Q3. A city planner wants to estimate the average monthly residential water usage in the city. He…

A: Given,sample size(n)=40sample mean(x¯)=3415.70standard…

Q: An Army official wants to estimate the mean weight of a particular type of weapon. He takes a…

A: Given that, Mean = 48.1 Standard deviation = 0.12 Sample size = 100 98% confidence level

Q: A sample of 45 customers who drive luxury cars showed that their average distance driven between oil…

A: Given: n1=45, x1=3187, s1=42.4n2=40, x1=3214, s2=50.7

Q: A researcher compares the effectiveness of two different instructional methods for teaching…

A: Given n1=138 X1bar=61 Standard deviation s1=18.53 n2=156 X2bar=64.6 Standard deviation s2=13.43…

Q: A sample of 20 items provides a sample standard deviation of 5. a. Compute the 90% confidence…

A: We have given that Sample size n=20 , sample standard deviation s= 5 Degree of freedom = n -1

Q: A study found the temperature of 125 randomly selected healthy adults averaged 98.25 F with a…

A: It is given that sample mean is 98.25 and standard deviation is 0.733.

Q: A medical researcher wishes to see whether the pulse rates of smokers are higher than the pulse…

A: There are two independent samples which are smokers and non smokers. We have to construct 99%…

Q: The president of a large university wishes to estimate the average age of the students presently…

A: Here we need to estimate a 95% confidence interval for the average age of students presently…

Q: A study found that the average time it took a person to find their dream home was 5.9 months. If a…

A: From the provided information, Sample size (n) = 36 Sample mean (x̅) = 5.9 months Population…

Q: For a random sample of 65 overweight men, the mean of number of pounds that they were overweight was…

A: Given, Sample size = 65 Sample mean = 32 Population standard deviation = 3.8 Since the population…

Q: A fast food executive wishes to know how many fast food meals adults eat each week. They want to…

A: The Critical values table for normal distribution

Q: A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean…

Q: In a randoms sample of six people, the mean driving distance to work was 19.7 miles and the standard…

A: Given, sample mean (x̄) = 19.7 sample standard deviation (s) = 6.1 sample size (n) = 6 significance…

Q: sample mean of 59 years old and sample standard deviation of 5 years. The margin of error for a…

A: Given: Mean=59 The margin of error for a 95% confidence interval estimate for the population mean…

Q: Find the 90% confidence interval for the variance and standard deviation of the ages of students at…

A: Confidence interval: The (1-α) % confidence interval for population standard deviation is given by:

Q: The average gold content from an ore sample in 36 different locations is found to be 2.6 grams per…

Q: A survey of 30 adults found that the mean age of a person's vehicle is 3.6 years. Assuming the…

A: We have given that, Sample mean (x̄) = 3.6, population standard deviation (σ) = 2 and sample size…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 students using Method 1 produces a testing
average of 61. A sample of 156 students using Method 2 produces a testing average of 64.6. Assume that the population standard deviation for Method 1 is 18.53,
while the population standard deviation for Method 2 is 13.43. Determine the 98 % confidence interval for the true difference between testing averages for students
using Method 1 and students using Method 2.
Step 1 of 3: Find the point estimate for the true difference between the population means.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 189 students using Method 1 produces a testing average of 71.9. A sample of 141 students using Method 2 produces a testing average of 78.3. Assume the standard deviation is known to be 11.07 for Method 1 and 11.9 for Method 2. Determine the 98 % confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 2 of 2: Construct the 98% confidence interval. Round your answers to one decimal place. Answer How to enter your answer (opens in new window) Lower endpoint: Upper endpoint: Tables Keypad Keyboard Shortcuts Previous Step Answers
A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 189 students using Method 1 produces a testing average of 71.9. A sample of 141 students using Method 2 produces a testing average of 78.3. Assume the standard deviation is known to be 11.07 for Method 1 and 11.9 for Method 2. Determine the 98 % confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Answer How to enter your answer (opens in new window) Tables Keypad Keyboard Shortcuts
A researcher compares the effectiveness of two different instructional methods for teaching anatomy. A sample of 201 students using Method 1 produces a testing average of 76.5. A sample of 244 students using Method 2 produces a testing average of 81.2. Assume that the population standard deviation for Method 1 is 18.88 while the population standard deviation for Method 2 is 15.43. Determine the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 2 of 2: Calculate the margin of error of a confidence interval for the difference between the two population means. Round your answer to six decimal places.
A researcher compares the effectiveness of two different instructional methods for teaching anatomy. A sample of 218 students using Method 1 produces a testing average of 58.7. A sample of 243 students using Method 2 produces a testing average of 54.7. Assume that the population standard deviation for Method 1 is 18.63, while the population standard deviation for Method 2 is 16.17. Determine the 95% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 1. Find the point estimate for the true difference between the population means. Answer: _points Step 2. Calculate the margin of error of a confidence interval for the difference between the two population means. Round your answer to six decimal places. points Answer: Step 3. Construct the 95% confidence interval. Round your answers to one decimal place. Answer: Lower endpoint: Upper endpoint:
A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 229 students using Method 1 produces a testing average of 72.9. A sample of 192 students using Method 2 produces a testing average of 72. Assume that the population standard deviation for Method 1 is 6.68, while the population standard deviation for Method 2 is 14.51. Determine the 95% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Round your answer to one decimal place. Lower endpoint = Upper endpoint =
A researcher compares the effectiveness of two different instructional methods for teaching anatomy. A sample of 131 students using Method 1 produces a testing average of 88.1. A sample of 142 students using Method 2 produces a testing average of 87.1. Assume that the population standard deviation for Method 1 is 11.46, while the population standard deviation for Method 2 is 9.78. Determine the 95% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 2 of 2: Construct the 95% confidence interval. Round your answers to one decimal place.
A researcher compares the effectiveness of two different instructional methods for teaching anatomy. A sample of 131 students using Method 1 produces a testing average of 88.1. A sample of 142 students using Method 2 produces a testing average of 87.1. Assume that the population standard deviation for Method 1 is 11.46, while the population standard deviation for Method 2 is 9.78. Determine the 95% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 1 of 2: Find the critical value that should be used in constructing the confidence interval.
A researcher compares the effectiveness of two different instructional methods for teaching anatomy. A sample of 66 students using Method 1 produces a testing average of 54.9. A sample of 110 students using Method 2 produces a testing average of 85.9. Assume that the population standard deviation for Method 1 is 6.04, while the population standard deviation for Method 2 is 16.44. Determine the 99 % confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 1 of 3: Find the point estimate for the true difference between the population means.
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 students using Method 1 produces a testing average of 61. A sample of 156 students using Method 2 produces a testing average of 64.6. Assume that the population standard deviation for Method 1 is 18.53, while the population standard deviation for Method 2 is 13.43. Determine the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Round your answer to one decimal place. Lower endpoint = Upper endpoint =
A researcher compares the effectiveness of two different instructional methods for teaching pharmacology. A sample of 63 students using Method 1 produces a testing average of 52.2. A sample of 93 students using Method 2 produces a testing average of 72.3. Assume that the population standard deviation for Method 1 is 15.92, while the population standard deviation for Method 2 is 17.96. Determine the 95% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 3 of 3 : Construct the 95% confidence interval. Round your answers to one decimal place.
It is hard to persuade consumers to abandon a product with which they are familiar. One experiment gave consumers free samples of new laundry detergent and also a standard detergent. After some time, ask the subjects which detergent they prefer. Here are the data. User Nonuser Prefer new product 19 31 Prefer standard product 29 27 a. Calculate a 90% confidence interval for the difference in proportions between nonusers and users of the standard detergent that prefer the new detergent. b. Based on the confidence interval in (a), can we conclude that a significant difference exists between the proportion of nonusers of the standard detergent who prefer the new detergent and the proportion of users of the standard detergent who prefer the new detergent? Explain.
A study found the temperature of 125 randomly selected healthy adults averaged 98.25 F with a standard deviation of 0.733. Find and interpret a 95% confidence interval for the average temperature of a group represented by this sample. State which method you use here.