A researcher compares the effectiveness of two different instructional methods for teaching pharmacology. A sample of 63 students using Method 1 produces a testing average of 52.2. A sample of 93 students using Method 2 produces a testing average of 72.3. Assume that the population standard deviation for Method 1 is 15.92, while the population standard deviation for Method 2 is 17.96. Determine the 95% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 3 of 3 :   Construct the 95% confidence interval. Round your answers to one decimal place.

Q: A gardener is testing a new type of carrot. From a sample of 15 carrots, she calculates a mean…

A: Given n=sample size=15 X=mean=7.2 s=standard deviation=1.23

Q: Step 5 of 6:  Identify the level of significance for the hypothesis test.

A: Given that  The population standard deviation is known to be 1.9

Q: Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two…

A: x¯1=69, s1=19, n1=38x¯2=32, s2=14, n2=37

Q: Random and independent samples of 90 recent prime time airings from each of two major networks have…

A: The sample size for first network is 90, sample mean is 109.2, population standard deviation is 5.1…

Q: In a transportation study of 27 large cities it was found that the number of motor vehicles per…

A: Given : Sample size (n) = 27 Sample mean (X¯) = one.34 i.e 1.34 Sample SD (S) = 0.46 Confidence…

Q: A sample of 22 households uses an average of 346.2 gallons of water per day, with a sample standard…

A: The sample size is 22, sample mean is 346.2 and sample standard deviation is 50.5.

Q: Give the best point estimate for the population and construct a 99% confidence interval for the true…

A: Let μ be the population mean score for students. Given that, x¯= 3.4Sample size (n) = 26Sample…

Q: The concentration of benzene was measured in units of milligrams per liter for a simple random…

A: Given the data as   Sample size Sample Mean Sample SD untreated wastewater 7 7.7 1.3 treated…

Q: The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT)…

A: Since, the population variances are unknown the Student's t-test will be applied. The variances are…

Q: A researcher compares the effectiveness of two different instructional methods for teaching anatomy.…

A:

Q: sample standard deviation of $74.50. a. Develop a  95% confidence interval estimate of the mean…

A: The sample size, i.e., the sampled number of families, n=64.The sample average spent amount(in $)…

Q: Random and independent samples of 90 recent prime time airings from each of two major networks have…

A:

Q: in a test of the effectiveness of garlic for Lauren cholesterol, 48 subjects were treated with…

A: From the provided information, Sample size (n) = 48 Sample mean (x̅) = 5.4 Sample standard deviation…

Q: A 30 month study is conducted to determine the difference in rates of accidents per month between…

A: Given:x1=12.3s1=3.5n1=12                    and                    x2=7.6s2=3.4n2=9   Since, the…

Q: The Weston Rescue Service and the Mid-Valley Ambulance Service are tested for response times. A…

A: Provided information is, the Weston Rescue Service and the Mid-Valley Ambulance Service are tested…

Q: A 2016 study reported in Science magazine stated that college math teachers scored a mean of 3.4…

A:

Q: Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two…

A: Consider µD is the mean ALT levels for individuals who drink alcohol and the µND is the mean ALT…

Q: Twelve dieters lost an average of 7.1 pounds in 6 weeks when given a special diet plus a  herbal…

A: Given,To, construct a 95% confidence interval for the difference of the means.

Q: In a test of physical fitness, a fitness trainer for a group of men ages 65 and older from a local…

A: The population mean is known to be 20. Based on the sample evidence you have to test whether the…

Q: A survey conducted by the American Automobile Association (AAA) showed that a family of four spends…

A: Given that: Population mean, μ=215.60 n = 64 x¯=252.45 s = 74.50

Q: A paper manufacturer has a production process that operates continuously throughout an entire…

A:

Q: Researchers from a certain country were interested in how characteristics of the spleen of residents…

A: Males Sample size, n1=93 Sample mean, x¯1=11.2 Sample sd, s1=0.8   Females Sample size, n2=107…

Q: In a study on college dropout rates, researchers found one factor that influenced the decision to…

A: We have given that,  Sample mean (x̄) = 3.11, standard deviation (s) = 0.66 and sample size (n) =…

Q: in a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…

A: From the provided information, Sample size (n) = 50 Sample mean (x̄) = 3.7 Sample standard deviation…

Q: A sample of 22 public high school students spent an average of 6.5 hours studying per week. Assuming…

A: Given: Sample Sizen=22Sample MeanX=6.5Standard Deviationσ=2.3 The z value corresponding to…

Q: A popular weight loss program claims users will lose weight each month. Linda samples 25 dieters and…

A: We have given that,  Sample mean (x̄) = 10 pounds, standard deviation (s) = 2 pounds and sample size…

Q: The International Air Transport Association surveys business travelers to develop quality ratings…

A: Givensample size(n)=50Mean(x)=3.34standard deviation(s)=2.163confidence interval = 95%

Q: A NAPA Auto Parts supplier wants information about how long car owners plan to keep their cars. A…

A: From the provided information, Sample size (n) = 41 Sample mean (x̅) = 7 Sample standard deviation…

Q: company manufactures a certain over-the-counter drug. The company samples 80 pills and finds that…

A: We have given that  Sample size n = 80 Sample mean = 325.5 Standard deviation s=10.3 90%confidence…

Q: A survey conducted by the AAA showed that a family of four spends on average $215.60 per day while…

A: It is given that sample mean is 252.45 and the standard deviation is 74.50.

Q: Random and independent samples of 80 recent prime time airings from each of two major networks have…

A:

Q: A small business wanted to estimate the mean income from their customers. They took a sample of 256…

A: We have to find  the 90% confidence interval estimate for the population mean income of their…

Q: Random and independent samples of 80 recent prime time airings from each of two major networks have…

A: Given n1=n2=80 S1=4.9 S1=4.6

Q: The average expenditure on Valentine's Day was expected to be $100.89. The average expenditure in a…

A: Obtain the 99% confidence interval for the difference between the two population means. The 99%…

Q: Intellectual development (Perry) scores were determined for 21 students in a first-year,…

A: Given data :  n = 21 Average  students  = 3.27 SD = 0.40 9% of CI