### Analyzing Motion of a Remote Controlled Toy CarA remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)**Snapshot Positions:**- At \( t = 0 \) s: Position = \( 0 \) m- At \( t = 0.5 \) s: Position = \( 0.1 \) m- At \( t = 1.0 \) s: Position = \( 0.4 \) m- At \( t = 1.5 \) s: Position = \( 0.9 \) m- At \( t = 2.0 \) s: Position = \( 1.6 \) m ### Questions and Solutions#### (a) What is the car's average velocity in the interval between \( t = 0.5 \) s to \( t = 1.0 \) s?**Answer:** \( 0.6 \) m/s ✔**Explanation:**To find the average velocity, we use:\[ \text{Average velocity} = \frac{\text{Change in position}}{\text{Change in time}} \]From \( t = 0.5 \) s to \( t = 1.0 \) s:\[ \text{Change in position} = 0.4 \, \text{m} - 0.1 \, \text{m} = 0.3 \, \text{m} \]\[ \text{Change in time} = 1.0 \, \text{s} - 0.5 \, \text{s} = 0.5 \, \text{s} \]\[ \text{Average velocity} = \frac{0.3 \, \text{m}}{0.5 \, \text{s}} = 0.6 \, \text{m/s} \]#### (b) Using data from \( t = 0.5 \) s to \( t = 1.5 \) s, what is the car's acceleration at \( t = 1.0 \) s?**Answer:** \(

Answered: Image /qna-images/answer/30d55adf-a91e-491e-beec-23d33848aa81.jpg

A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.) 1=0s 1=0.5 s 1= 1.0 s 1= 1.5 s 1=2.0 s 0m 0,1 m 0.4 m 0.9 m 1,6 m (a) What is the car's average velocity in the interval between t = 0,5 s to t= 1.0 s? 0.6 m/s (b) Using data from t = 0.5 s to t = 1.5 s, what is the car's acceleration at t = 1.0 s? 1.4 Recall that the definition of average acceleration is the change in velocity divided by the change in time. What is the initial velocity? What is the final velocity? Be careful about the change in time as well-if you measure velocities at "midpoints" within two separate intervals, what is the separation between those midpoints? m/s? (c) Is the car's speed increasing or decreastng with time? O increasing O decreasing O constant O not enough information

A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.) 1=0s 1=0.5 s 1= 1.0 s 1= 1.5 s 1=2.0 s 0m 0,1 m 0.4 m 0.9 m 1,6 m (a) What is the car's average velocity in the interval between t = 0,5 s to t= 1.0 s? 0.6 m/s (b) Using data from t = 0.5 s to t = 1.5 s, what is the car's acceleration at t = 1.0 s? 1.4 Recall that the definition of average acceleration is the change in velocity divided by the change in time. What is the initial velocity? What is the final velocity? Be careful about the change in time as well-if you measure velocities at "midpoints" within two separate intervals, what is the separation between those midpoints? m/s? (c) Is the car's speed increasing or decreastng with time? O increasing O decreasing O constant O not enough information

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter3: Accelerated Motion

Section3.2: Motion With Constant Acceleration

Problem 22PP

See similar textbooks

Related questions

Q: A police car waits in hiding slightly off the highway. A speeding car is spotted by the police car…

A: A police car waits in hiding slightly off the highway. A speeding car is spotted by the police car…

Q: A horse canters away from its trainer in a straight line, moving 45 m away in 8.7 s. It then turns…

Q: Examine the position vs. time graph below. What is the speed of the object at t = 3.0 s? position vs…

A: The speed of the object at a certain instant of time is known as the instantaneous speed. The slope…

Q: elocity decreases linearly from 45 m/s to 0 m/s. 101 m 225 m 150 m 112 m

Q: The data represented in the velocity vs. time graph below is from a car traveling along a flat…

Q: An astronaut has left an orbiting space shuttle to test a new personal maneuvering unit. As she…

Q: A ball moves and its motion is represented by following equation: x=30+ 40t+ 60t^2+40t^3 a) Find…

A: SOlution: Given that position equation x=30+ 40t+ 60t^2+40t^3

Q: A race car starts from rest and travels east along a straight and level track. The eastward…

A: Given data - initial velocity of race car = 0 m/s (along east)…

Q: Bartholomew jogs from home at 3.50 m/s north for 1380 seconds. Then, he turns around and jogs 2.40…

A: Given: The jogger jogs from home at 3.50 m/s north for 1380 seconds. The jogger then turns around…

Q: Starting from a pillar, you run 400 m east (+x direction) at an average speed of 4 m/s, and then run…

Q: An elevator in a high-rise building goes up and down at the same speed. Starting at the ground…

Q: The kinematical graphs of a person riding her bicycle are shown below. Time is measured in second,…

A: Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: Your favorite car goes zero to 60.0 mph in 5.00 seconds. Assuming it accelerates uniformly, sketch a…

A: Assume car to be travelling in straight line. Let u be the car’s initial velocity, v be the car’s…

Q: A block falls from rest off a building that is y = 185 m tall

A: y=185 mUsing Newton's Law of motion initial velocity μ=0y=ut+12gt2185=0+129.8t2to=6.14 second

Q: At a stop light, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels…

Q: A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure…

A: Average velocity is the ratio of total distance traveled to the total time taken v¯=sT=s2-s1t2-t1…

Q: Bob is cruising leisurely on his bike at 2.4 m/s when Jim passes him, traveling at a constant 10.2…

Q: Bob is cruising leisurely on his bike at 2 m/s when Jim passe immediately begins accelerating at 2.2…

Q: A particle moves along a straight line with an acceleration described by the equation, a = 3t2 + 2t…

A: Given,acceleration of the particle, a = 3t2 + 2t + 4velocity of the particle at, t = 4 sec, v(4) =…

Q: A plot of velocity versus time for a car for the first 15 seconds of motion is shown in the diagram…

Q: The graph at right shows velocity vs. time. The particle at t=0 was positioned at Xo = 15. What is…

Q: The figure below is a plot of velocity versus time for a particle that travels along a straight line…

A: To calculate the Acceleration of the particle at t=10 s

Q: The diagram below presents the position and elapsed time of a motorbike that starts from rest and…

Q: The velocity-time graph of an object's motion is shown in this graph. At 10 s, what is the object's…

A: Displacement d=∫vdt Thus, the displacement of the is same as the area under the curve. Area of a…

Q: A car accelerates from rest at 5 m/s2 for 5 seconds. It moves with a constant velocity for some time…

Q: time(s) position (cm) 0 49.0 5 38.0 10 43.0 15 40.0 20 60.0 A. What is the…

A: Tofind: From the data given in the table, we are required to calculate displacement, average…

Q: An object is moving to the right with a constant speed of 21 m/s for 5.0 s. What is the acceleration…

A: acceleration is the rate of change of velocity

Q: honda civic is driven at 20 m/s for 12 mins, then 40 m/s for 20 min, and finally at 50 m/s for 8…

A: Average speed = total distance / total time taken

Q: This graph shows an object’s velocity versus time as it is moving along the x-axis. Its initial…

A: This graph shows an object’s velocity versus time as it is moving along the x-axis. Its initial…

Q: At t=0 an object has a velocity of 35 m/s and a steady acceleration of -10 m/s2. Make a sketch…

A: (a) velocity vs time graph

Q: A police car waits in hiding slightly off the highway. A speeding car is spotted by the police car…

A: We are aware that a police vehicle is lurking just off the road.The police car travelling at 40 m/s…

Concept explainers

Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

Question

### Analyzing Motion of a Remote Controlled Toy Car

A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)

**Snapshot Positions:**
- At \( t = 0 \) s: Position = \( 0 \) m
- At \( t = 0.5 \) s: Position = \( 0.1 \) m
- At \( t = 1.0 \) s: Position = \( 0.4 \) m
- At \( t = 1.5 \) s: Position = \( 0.9 \) m
- At \( t = 2.0 \) s: Position = \( 1.6 \) m

### Questions and Solutions

#### (a) What is the car's average velocity in the interval between \( t = 0.5 \) s to \( t = 1.0 \) s?
**Answer:** \( 0.6 \) m/s ✔

**Explanation:**
To find the average velocity, we use:
\[ \text{Average velocity} = \frac{\text{Change in position}}{\text{Change in time}} \]
From \( t = 0.5 \) s to \( t = 1.0 \) s:
\[ \text{Change in position} = 0.4 \, \text{m} - 0.1 \, \text{m} = 0.3 \, \text{m} \]
\[ \text{Change in time} = 1.0 \, \text{s} - 0.5 \, \text{s} = 0.5 \, \text{s} \]
\[ \text{Average velocity} = \frac{0.3 \, \text{m}}{0.5 \, \text{s}} = 0.6 \, \text{m/s} \]

#### (b) Using data from \( t = 0.5 \) s to \( t = 1.5 \) s, what is the car's acceleration at \( t = 1.0 \) s?
**Answer:** \(

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Data & Diagram :

VIEW

Calculation & Result :

VIEW

Conclusion :

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Two cars are moving in the same direction in parallel lanes along a highway. At some instant, the velocity of car A exceeds the velocity of car B. Does that mean that the acceleration of A is greater than that of B at that instant? Explain.
Two cars are moving in the same direction in parallel lanes along a highway. At some instant, the velocity of car A exceeds the velocity of car B. Does that mean that the acceleration of car A is greater than that of car B? Explain.
Case Study Crall and Whipple attached a fan to a cart placed on a level track and then released the cart. They made a position-versus-time graph (Fig. P2.54) and fit a curve to these data such that x=0.036m+(0.0080m/s)t+(0.10m/s2)t2 a. Find and graph the velocity as a function of time. b. What is the shape of the velocity-versus-time graph? What do you expect the acceleration-versus-time graph to look like? Explain. c. Find and graph the acceleration as a function of time.
PROBLEM A race car starting from rest accelerates at a constant rate of 5.00 m/s2, (a) What is the velocity of the car after it has traveled 1.00 102 ft? (b) How much time has elapsed? (c) Calculate the average velocity two different ways. STRATEGY Weve read the problem, drawn the diagram in Figure 2.16, and chosen a coordinate system (steps 1 and 2). We'd like to find the velocity v after a certain known displacement x. The acceleration a is also known, as is the initial velocity v0 (step 3, labeling, is complete), so the third equation in Table 2.4 looks most useful for solving part (a). Given the velocity, the first equation in Table 2.4 can then be used to find the time in part (b). Part (c) requires substitution into Equations 2.2 and 2.7, respectively. Figure 2.16 (Example 2.4) SOLUTION (a) Convert units of x to SI, using the information in the inside front cover. Write the kinematics equation for v2 (step 4): Solve for v, taking the positive square root because the car moves to the right (step 5): Substitute v0 = 0, a = 5.00 m/s2, and x = 30.5 m: 1.00 102ft = (1.00 102 ft) v2 = v02 + 2a x v = v02+2ax v = v02+2ax = (0)2+2(5.00m/s2)(30.5m)= 17.5 m/s (b) Find the trooper's speed at that time. Substitute the time into the troopers velocity equation: vtrooper = v0 + atrooper t = 0 + (3.00m/s2)(16.9s) = 50.7 m/s Solve Example 2.5, Car Chase, by a graphical method. On the same graph, plot position versus time for the car and the trooper. From the intersection of the two curves, read the time at which the trooper overtakes the car.
Acceleration is the change in velocity over time. Given this information, is acceleration a vector or a scalar quantity? Explain.
A speedboat travels in a straight line and increases in speed uniformly from i = 20.0 m/s to f = 30.0 m/s in displacement x of 200 m. We wish to find the time interval required for the boat to move through this displacement, (a) Draw a coordinate system for this situation, (b) What analysis model is most appropriate for describing this situation? (c) From the analysis model, what equation is most appropriate for finding the acceleration of the speedboat? (d) Solve the equation selected in part (c) symbolically for the boats acceleration in terms of i, f, and x. (e) Substitute numerical values lo obtain the acceleration numerically. (f) Find the time interval mentioned above.
A bicycle racer sprints at the end of a race to clinch a victory. The racer has an initial velocity of 11.5 m/s and accelerates at the rate of 0.500 m/s2 for 7.00 s. (a) What is his final velocity? (b) The racer continues at this velocity to the finish line. If he was 300 m from the finish line when he started to accelerate, how much time did he save? (c) One other racer was 5.00 m ahead when the winner started to accelerate, but he was unable to accelerate, and traveled at 11.8 m/s until the finish line. How far ahead of him (in meters and in seconds) did the winner finish?
A ball rolls in a straight line along the horizontal direction. Using motion diagrams (or multi flash photo-graphs), describe the velocity and acceleration of the ball for each of the following situations: (a) The ball moves to the right at a constant speed, (b) The ball moves from right to left and continually slows down, (c) The ball moves from right to left and continually speeds up. (d) The ball moves to the right, first speeding up at a constant rate and then slowing down at a constant rate.
A glider on an air track carries a flag of length through a stationary photogate, which measures the time interval td during which the flag blocks a beam of infrared light passing across the photogate. The ratio vd = /td is the average velocity of the glider over this part of its motion. Suppose the glider moves with constant acceleration, (a) Is vd necessarily equal to the instantaneous velocity of the glider when it is halfway through the photogate in space? Explain. (b) Is vd equal to the instantaneous velocity of the glider when it is halfway through the photogate in time? Explain.
An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station is 210 m long. (a) How long is the nose of the train in the station? (b) How fast is it going when the nose leaves the station? (c) If the train is 130 m long, when does the end of the train leave the station? (d) What is the velocity of the end of the train as it leaves?
O 2/m/s/s A bicyclist accelerates at 0.89 m/s^2 duringa 5s interval. If she started at 2.3m/s, what was the final speed of the bicyclist?* ) 10.61m/s O6.75m/s 4.45m/s 2.15m/s Which d/t graph matches the following v/t graph?*
10) Graph interpretation & conversion: The v-t (velocity vs. time) graph for the motion of a car is shown. The car starts at the origin at the instant the motion begins (t = 0). Carefully draw the following two additional graphs below the given graph, making sure that the time axes use the same scale. a) Acceleration vs. time b) Position vs. time (Be very careful to depict whether the graph is linear, concave up, or concave down.) t₁ N܂ T3 t