A rehabilitation patient is doing arm curl exercises by lifting a 90N dumbbell (W), as shown, to strengthen their biceps muscle.The dumbbell is located 33 cm from the axis of rotation of theelbow joint. The arm is flexed as shown. The biceps muscleinserts 3 cm from the axis of rotation of the elbow joint and isoriented at an angle of 50° with respect to the arm. The motionis performed slowly enough that we can assume (quasi) staticequilibrium.a) Determine the magnitude of the vertical joint reaction forceRy (shown) that the humerus exerts on the radius at theelbow joint.b) An equal and opposite compressive force then acts on thehumerus. If we assume the humerus is a circular hollowcylinder with inner and outer radii of r;= 18 mm and ro. = 23mm respectively, determine the resultant stress in thehumerus.c) If the elastic modulus of bone is 15 GPa, determine theresultant strain in the humerus.d) If their humerus is initially 33 cm long, how much does itchange in length (Al) as a result of this compressive load?Does your answer seem reasonable? Why or why not?RxRy[11550%3 cm.FB30 cmW = 90 N

To find : Reaction force Ry Stress in the humerus Strain in the humerus Change in length ∆l

Answered: A rehabilitation patient is doing arm…

Similar questions

A uniform rod AB of weight 500 N and length 4.0 m is supported at two points P and Q as shown below. AP = QB = 0.80 m. A man of weight 800 N is walking from Q to B. Find the maximum %3D %3D distance x from Q the man can walk before the rod topples about Q. P Q A 1 -| × |- O 0.4 m O 0.8 m O 0.75 m O 0.6 m
A 45.5‑kg box with the dimensions a×b (the width a = 0.6 m and height b = 1.3 m) is standing on a rough horizontal floor (μs = 1.3). A Professor wants to tip the box over, she pushes on the right side of the box with a horizontal force F = 140 N at a distance h = 1.04 m above the floor as shown in the picture below. The other forces acting on the box are the gravity force (applied to the CoM of the box), the static friction force Fs and the normal force N (both applied to the lower right corner of the box, point Q). Calculate the magnitude and direction of the torques produced by the forces acting on the box relative to the lower right corner (point Q). Assume uniform mass distribution. 1. The torque due to the external force, τQ(due to F) = 2. The torque due to the weight of the box, τQ(due to mg) = 3. The torque due to the friction force, τQ(due to Fs) = 4. The torque due to the normal force, τQ(due to N) =
A hungry bear weighing 85.0 kg walks out on a beam in an attempt to retrieve a basket of food hanging at the end of the beam. The beam is uniform, has a mass of 20.0 kg, is 8.00 m long, and pivoted at the wall; the basket weighs 10.0 kg. If the wire can withstand a maximum tension of 900 N, what is the maximum distance that the bear can walk before the wire breaks? ←x 60.0⁰ Goodies
Suppose a 905-kg car is on the bridge in the figure with its center of mass halfway between the hinges and the cable attachment. (The bridge is supported by the cable and hinges only.) The mass of the bridge is 2500 kg. Find the tension, in newtons, in the cable.
A student gets his car stuck in a snow drift. Not at a loss, having studied physics, he attaches one end of a stout rope to the vehide and the other end to the trunk of a nearby tree, allowing for a small amount of slack. The student then exerts a force F on the center of the rope in the direction perpendicular to the car-tree line, as shown in the figure below. If the rope is inextensible and if the magnitude of the applied force is 504 N, what is the force on the car? (Assume equilibrium conditions.) KN 12 m Tree 0.50 m
The center of gravity of Kelly's outstretched arm is located 21 cm from the axis of rotation in her shoulder. Her arm has a mass of 4.2 kg and is 56 cm long. Assuming the deltoid's force is horizontal, what is the magnitude of the force her deltoid muscle must exert on Kelly's upper arm so she can hold a 6.0 kg mass stationary 15 degree above the horizontal as shown? Her deltoid muscle attaches to her upper arm at a point 18 cm from her shoulder joint. 6 kg 15° 21 cm Fdeltiod
The forearm shown below is positioned at an angle with respect to the upper arm, and a 5.6 kg mass is held in the hand. The total mass of the forearm and hand is 2.1 kg, and their center of mass is 16.1 cm from the elbow. (Assume the biceps muscle exerts a force on the forearm that acts vertically.) 5.6 kg B 37.5 cm 4.0 cm (a) What is the magnitude of the force (in N) that the biceps muscle exerts on the forearm for 0-60%7 N (b) What is the magnitude of the force on the elbow joint (in N) for the same angle? N (c) How do these forces depend on the angle 07 The force that the biceps muscle exerts increases and the force on the elbow joint decreases as increases. They both decrease as @ increases. They both increase as increases. They do not depend on 0. The force that the biceps muscle exerts decreases and the force on the elbow joint increases as increases.
A man holds a 179-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force , which is applied perpendicular to the forearm. The forearm weighs 20.3 N and has a center of gravity as indicated. Find (a) the magnitude of M and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to the forearm at the elbow joint. Upper arm bone Flexor muscle M Elbow joint 0.0510 mt 0.0890 m -0.330 m- (a) Number Units (b) Number Units (c) Number Units
The arm in the figure below weighs 37.7 N. The force of gravity acting on the arm acts through point A. Determine the magnitudes of the tension force in the deltoid muscle and the force F S exerted by the shoulder on the humerus (upper-arm bone) to hold the arm in the position shown. (Enter your answers to at least the nearest newton.) N Ft Fs N √12⁰ 0 F 0.080 m -0.290 m TE