A man holds a 167-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force M, which is applied perpendicular to the forearm. The forearm weighs 19.5 N and has a center of gravity as indicated. Find (a) the magnitude of M and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to the forearm at the elbow joint.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Problem Description

A man holds a 167-N ball in his hand, with the forearm horizontal. He can support the ball in this position because of the flexor muscle force \( \vec{M} \), which is applied perpendicular to the forearm. The forearm weighs 19.5 N and has a center of gravity as indicated. 

**Objective:**  
Find the magnitude of \( \vec{M} \) and:
- (a) The magnitude of \( \vec{M} \),
- (b) The magnitude, 
- (c) The direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to the forearm at the elbow joint.

### Diagram Explanation

The diagram shows a forearm in a horizontal position with the following components labeled:

- **Upper Arm Bone:** The part that connects with the elbow joint.
- **Flexor Muscle:** The muscle responsible for applying the force \( \vec{M} \).
- **Elbow Joint:** The pivot point for the forearm.
- **Center of Gravity (CG):** The point where the forearm’s weight of 19.5 N acts, located 0.0890 m from the elbow joint.

**Distances:**
- From the elbow joint to the center of gravity (CG) of the forearm: 0.0890 m.
- From the elbow joint to where the flexor muscle force \( \vec{M} \) is applied: 0.0510 m.
- From the elbow joint to where the ball is held: 0.330 m.

### Answer Fields

- **(a) **\[ \text{Number}\] \[ \text{Units}\]
- **(b) **\[ \text{Number}\] \[ \text{Units}\]
- **(c) **\[ \text{Number}\] \[ \text{Units}\] 

These fields allow for inputting the calculated magnitude and direction of the forces in appropriate units.
Transcribed Image Text:### Problem Description A man holds a 167-N ball in his hand, with the forearm horizontal. He can support the ball in this position because of the flexor muscle force \( \vec{M} \), which is applied perpendicular to the forearm. The forearm weighs 19.5 N and has a center of gravity as indicated. **Objective:** Find the magnitude of \( \vec{M} \) and: - (a) The magnitude of \( \vec{M} \), - (b) The magnitude, - (c) The direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to the forearm at the elbow joint. ### Diagram Explanation The diagram shows a forearm in a horizontal position with the following components labeled: - **Upper Arm Bone:** The part that connects with the elbow joint. - **Flexor Muscle:** The muscle responsible for applying the force \( \vec{M} \). - **Elbow Joint:** The pivot point for the forearm. - **Center of Gravity (CG):** The point where the forearm’s weight of 19.5 N acts, located 0.0890 m from the elbow joint. **Distances:** - From the elbow joint to the center of gravity (CG) of the forearm: 0.0890 m. - From the elbow joint to where the flexor muscle force \( \vec{M} \) is applied: 0.0510 m. - From the elbow joint to where the ball is held: 0.330 m. ### Answer Fields - **(a) **\[ \text{Number}\] \[ \text{Units}\] - **(b) **\[ \text{Number}\] \[ \text{Units}\] - **(c) **\[ \text{Number}\] \[ \text{Units}\] These fields allow for inputting the calculated magnitude and direction of the forces in appropriate units.
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