A real battery is not just an emf. We can model a real 1.5 V battery as a 1.5 V emf in series with a resistor known as the "internal resistance", as shown in the figure(Figure 1). A typical battery has 1.0 N internal resistance due to imperfections that limit current through the battery. When there's no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V, the value of the emf. Suppose the terminals of this battery are connected to a 3.0 resistor. Part A What is the potential difference between the terminals of the battery? Express your answer in volts. ? V = V Submit Request Answer Part B What fraction of the battery's power is dissipated by the internal resistance? Express your answer in percent. Vα ΑΣφ ? ΔΡ P % Submit Request Answer Figure < 1 of 1> 1.0 N 1.5 V

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A real battery is not just an emf. We can model a real 1.5 V battery as
a 1.5 V emf in series with a resistor known as the "internal
resistance", as shown in the figure(Figure 1). A typical battery has 1.0
N internal resistance due to imperfections that limit current through the
battery. When there's no current through the battery, and thus no
voltage drop across the internal resistance, the potential difference
between its terminals is 1.5 V, the value of the emf. Suppose the
terminals of this battery are connected to a 3.0 N resistor.
Part A
What is the potential difference between the terminals of the battery?
Express your answer in volts.
?
V =
V
Submit
Request Answer
Part B
What fraction of the battery's power is dissipated by the internal resistance?
Express your answer in percent.
?
ΔΡ
=
Submit
Request Answer
Figure
< 1 of 1 >
1.0 2
1.5 V
圓
Transcribed Image Text:A real battery is not just an emf. We can model a real 1.5 V battery as a 1.5 V emf in series with a resistor known as the "internal resistance", as shown in the figure(Figure 1). A typical battery has 1.0 N internal resistance due to imperfections that limit current through the battery. When there's no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V, the value of the emf. Suppose the terminals of this battery are connected to a 3.0 N resistor. Part A What is the potential difference between the terminals of the battery? Express your answer in volts. ? V = V Submit Request Answer Part B What fraction of the battery's power is dissipated by the internal resistance? Express your answer in percent. ? ΔΡ = Submit Request Answer Figure < 1 of 1 > 1.0 2 1.5 V 圓
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