A voltage divider consists of two 1.0-kΩ resistors connected in series across a 160-V emf. If a 10-kΩ resistor is connected across one of the 1.0-kΩ resistors, what will be the voltage across it?
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A voltage divider consists of two 1.0-kΩ resistors connected in series across a 160-V emf. If a 10-kΩ resistor is connected across one of the 1.0-kΩ resistors, what will be the voltage across it?
The given circuit can be drawn as,
Now the voltage across the 10 k resistor will be the same as the voltage between the combination of 10 k and 1 k resistor.
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- The figure displays two circuits with a charged capacitor that is to be discharged through a resistor when a switch is closed. In figure (a) below, R₁ = 21.7 Q and C₁ = 5.08 µF. In figure (b) below, R₂ = 10.5 Q and C₂ = 8.00 μF. The ratio of the initial charges on the two capacitors is 902/901 = 1.82. At time t = 0, both switches are closed. At what time t do the two capacitors have the same charge? Number i 0.188 Units 00 ms (a) (b)The current in a 65-Ω resistor is 0.15 A. This resistor is in series with a 24-Ω resistor, and the series combination is connected across a battery. What is the battery voltage?Three resistors are connected as shown to a battery. The value of the resistors are: R1 = 1.25KΩ R2 = 1.5kΩ and R3 = 3kΩ. The battery voltage is measured to be 45V. (i) What is the equivalent resistance for the circuit? (ii) What is the voltage drop over R2?
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