A reaction is made up in the following way: 19 mL of 4.8 M acetone + 14 mL of 1.4 M HCI + 18 mL of 0.0057 M I2 + 17 mL of water. It takes 373 seconds for the I2 color to disappear from the reaction mixture. What was the rate of reaction? Express your answer as a decimal number (no exponents). Include proper (abbreviated) units.

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### Reaction Rate Calculation

A reaction is made up in the following way:

- 19 mL of 4.8 M acetone
- 14 mL of 1.4 M HCl
- 18 mL of 0.0057 M I₂
- 17 mL of water

It takes 373 seconds for the I₂ color to disappear from the reaction mixture. What was the rate of reaction?

**Solution:**

To calculate the rate of reaction, we need to determine how fast the concentration of I₂ changes over time. The rate can be expressed as the change in concentration of I₂ per unit time.

**Step-by-Step Calculation:**

1. **Determine the initial moles of I₂:**
   \[ \text{Initial moles of I₂} = \text{Volume (L)} \times \text{Concentration (M)} \]
   \[ = 0.018 \, \text{L} \times 0.0057 \, \text{M} \]
   \[ = 0.0001026 \, \text{mol} \]

2. **Determine the total volume of the solution:**
   \[ \text{Total volume} = 19 \, \text{mL} + 14 \, \text{mL} + 18 \, \text{mL} + 17 \, \text{mL} \]
   \[ = 68 \, \text{mL} = 0.068 \, \text{L} \]

3. **Calculate the initial concentration of I₂ in the reaction mixture:**
   \[ \text{Initial concentration of I₂} = \frac{\text{Initial moles of I₂}}{\text{Total volume}} \]
   \[ = \frac{0.0001026 \, \text{mol}}{0.068 \, \text{L}} \]
   \[ \approx 0.001509 \, \text{M} \]

4. **Rate of reaction:** The color disappearance indicates that the concentration of I₂ changes from the initial concentration to zero over the given time.
   \[ \text{Rate of reaction} = \frac{\text{Change in concentration}}{\text{Time}} \]
   \[ = \frac{0.001509 \,
Transcribed Image Text:### Reaction Rate Calculation A reaction is made up in the following way: - 19 mL of 4.8 M acetone - 14 mL of 1.4 M HCl - 18 mL of 0.0057 M I₂ - 17 mL of water It takes 373 seconds for the I₂ color to disappear from the reaction mixture. What was the rate of reaction? **Solution:** To calculate the rate of reaction, we need to determine how fast the concentration of I₂ changes over time. The rate can be expressed as the change in concentration of I₂ per unit time. **Step-by-Step Calculation:** 1. **Determine the initial moles of I₂:** \[ \text{Initial moles of I₂} = \text{Volume (L)} \times \text{Concentration (M)} \] \[ = 0.018 \, \text{L} \times 0.0057 \, \text{M} \] \[ = 0.0001026 \, \text{mol} \] 2. **Determine the total volume of the solution:** \[ \text{Total volume} = 19 \, \text{mL} + 14 \, \text{mL} + 18 \, \text{mL} + 17 \, \text{mL} \] \[ = 68 \, \text{mL} = 0.068 \, \text{L} \] 3. **Calculate the initial concentration of I₂ in the reaction mixture:** \[ \text{Initial concentration of I₂} = \frac{\text{Initial moles of I₂}}{\text{Total volume}} \] \[ = \frac{0.0001026 \, \text{mol}}{0.068 \, \text{L}} \] \[ \approx 0.001509 \, \text{M} \] 4. **Rate of reaction:** The color disappearance indicates that the concentration of I₂ changes from the initial concentration to zero over the given time. \[ \text{Rate of reaction} = \frac{\text{Change in concentration}}{\text{Time}} \] \[ = \frac{0.001509 \,
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