A reaction is made up in the following way: 19 mL of 4.8 M acetone + 14 mL of 1.4 M HCI + 18 mL of 0.0057 M I2 + 17 mL of water. It takes 373 seconds for the I2 color to disappear from the reaction mixture. What was the rate of reaction? Express your answer as a decimal number (no exponents). Include proper (abbreviated) units.
A reaction is made up in the following way: 19 mL of 4.8 M acetone + 14 mL of 1.4 M HCI + 18 mL of 0.0057 M I2 + 17 mL of water. It takes 373 seconds for the I2 color to disappear from the reaction mixture. What was the rate of reaction? Express your answer as a decimal number (no exponents). Include proper (abbreviated) units.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![### Reaction Rate Calculation
A reaction is made up in the following way:
- 19 mL of 4.8 M acetone
- 14 mL of 1.4 M HCl
- 18 mL of 0.0057 M I₂
- 17 mL of water
It takes 373 seconds for the I₂ color to disappear from the reaction mixture. What was the rate of reaction?
**Solution:**
To calculate the rate of reaction, we need to determine how fast the concentration of I₂ changes over time. The rate can be expressed as the change in concentration of I₂ per unit time.
**Step-by-Step Calculation:**
1. **Determine the initial moles of I₂:**
\[ \text{Initial moles of I₂} = \text{Volume (L)} \times \text{Concentration (M)} \]
\[ = 0.018 \, \text{L} \times 0.0057 \, \text{M} \]
\[ = 0.0001026 \, \text{mol} \]
2. **Determine the total volume of the solution:**
\[ \text{Total volume} = 19 \, \text{mL} + 14 \, \text{mL} + 18 \, \text{mL} + 17 \, \text{mL} \]
\[ = 68 \, \text{mL} = 0.068 \, \text{L} \]
3. **Calculate the initial concentration of I₂ in the reaction mixture:**
\[ \text{Initial concentration of I₂} = \frac{\text{Initial moles of I₂}}{\text{Total volume}} \]
\[ = \frac{0.0001026 \, \text{mol}}{0.068 \, \text{L}} \]
\[ \approx 0.001509 \, \text{M} \]
4. **Rate of reaction:** The color disappearance indicates that the concentration of I₂ changes from the initial concentration to zero over the given time.
\[ \text{Rate of reaction} = \frac{\text{Change in concentration}}{\text{Time}} \]
\[ = \frac{0.001509 \,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8c8d8a42-8de4-4466-9c46-ae253053e314%2Fdf3ed42f-61cc-42ac-b807-b47c7c934db2%2Fpx7b6rb.png&w=3840&q=75)
Transcribed Image Text:### Reaction Rate Calculation
A reaction is made up in the following way:
- 19 mL of 4.8 M acetone
- 14 mL of 1.4 M HCl
- 18 mL of 0.0057 M I₂
- 17 mL of water
It takes 373 seconds for the I₂ color to disappear from the reaction mixture. What was the rate of reaction?
**Solution:**
To calculate the rate of reaction, we need to determine how fast the concentration of I₂ changes over time. The rate can be expressed as the change in concentration of I₂ per unit time.
**Step-by-Step Calculation:**
1. **Determine the initial moles of I₂:**
\[ \text{Initial moles of I₂} = \text{Volume (L)} \times \text{Concentration (M)} \]
\[ = 0.018 \, \text{L} \times 0.0057 \, \text{M} \]
\[ = 0.0001026 \, \text{mol} \]
2. **Determine the total volume of the solution:**
\[ \text{Total volume} = 19 \, \text{mL} + 14 \, \text{mL} + 18 \, \text{mL} + 17 \, \text{mL} \]
\[ = 68 \, \text{mL} = 0.068 \, \text{L} \]
3. **Calculate the initial concentration of I₂ in the reaction mixture:**
\[ \text{Initial concentration of I₂} = \frac{\text{Initial moles of I₂}}{\text{Total volume}} \]
\[ = \frac{0.0001026 \, \text{mol}}{0.068 \, \text{L}} \]
\[ \approx 0.001509 \, \text{M} \]
4. **Rate of reaction:** The color disappearance indicates that the concentration of I₂ changes from the initial concentration to zero over the given time.
\[ \text{Rate of reaction} = \frac{\text{Change in concentration}}{\text{Time}} \]
\[ = \frac{0.001509 \,
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