A ray of monochromatic light of frequency 5.09×10 hertz is traveling from water into medium X. The angle of incidence in water is 45°and the angle of refraction in medium X is 38.83 degrees Calculate the absolute index of refraction of X. Show all work, including the equation and substitution with units B iU AA E O AA- E E A:
Ray Optics
Optics is the study of light in the field of physics. It refers to the study and properties of light. Optical phenomena can be classified into three categories: ray optics, wave optics, and quantum optics. Geometrical optics, also known as ray optics, is an optics model that explains light propagation using rays. In an optical device, a ray is a direction along which light energy is transmitted from one point to another. Geometric optics assumes that waves (rays) move in straight lines before they reach a surface. When a ray collides with a surface, it can bounce back (reflect) or bend (refract), but it continues in a straight line. The laws of reflection and refraction are the fundamental laws of geometrical optics. Light is an electromagnetic wave with a wavelength that falls within the visible spectrum.
Converging Lens
Converging lens, also known as a convex lens, is thinner at the upper and lower edges and thicker at the center. The edges are curved outwards. This lens can converge a beam of parallel rays of light that is coming from outside and focus it on a point on the other side of the lens.
Plano-Convex Lens
To understand the topic well we will first break down the name of the topic, ‘Plano Convex lens’ into three separate words and look at them individually.
Lateral Magnification
In very simple terms, the same object can be viewed in enlarged versions of itself, which we call magnification. To rephrase, magnification is the ability to enlarge the image of an object without physically altering its dimensions and structure. This process is mainly done to get an even more detailed view of the object by scaling up the image. A lot of daily life examples for this can be the use of magnifying glasses, projectors, and microscopes in laboratories. This plays a vital role in the fields of research and development and to some extent even our daily lives; our daily activity of magnifying images and texts on our mobile screen for a better look is nothing other than magnification.
![### Determining the Material Composition of Medium X Based on Calculations
**Question:**
(b) Based on your calculation, what material could Medium X possibly be made of?
**Answer:**
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### Explanation of Interface Elements:
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This setup can be typically seen in an educational setting where students are required to provide detailed explanations or answers based on prior calculations or research. The formatting tools enhance the readability and presentation of the submitted answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F666a7050-d460-4d4f-9624-d4bdba52f50b%2Fd52b5ddc-ee09-495d-84d1-d54e24e6271a%2F26fsmdf_processed.jpeg&w=3840&q=75)
![### Question 4
#### (a)
A ray of monochromatic light of frequency \(5.09 \times 10^{14}\) hertz is traveling from water into medium X. The angle of incidence in water is \(45^\circ\) and the angle of refraction in medium X is \(38.83^\circ\).
**Calculate the absolute index of refraction of X. Show all work, including the equation and substitution with units.**
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To solve this problem, we'll use Snell's law, which states:
\[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \]
where:
- \( n_1 \) is the index of refraction for the initial medium (water).
- \(\theta_1\) is the angle of incidence.
- \( n_2\) is the index of refraction for the second medium (X).
- \(\theta_2\) is the angle of refraction.
Given:
- \( \theta_1 = 45^\circ \)
- \( \theta_2 = 38.83^\circ \)
- The refractive index of water \( n_1 = 1.33 \) (standard value)
We need to find \( n_2 \):
Rearranging Snell's law to solve for \( n_2 \):
\[ n_2 = \frac{n_1 \sin(\theta_1)}{\sin(\theta_2)} \]
Substituting the given values:
\[ n_2 = \frac{1.33 \sin(45^\circ)}{\sin(38.83^\circ)} \]
Using sine values:
\[ \sin(45^\circ) = 0.7071 \]
\[ \sin(38.83^\circ) = 0.6275 \]
So we get:
\[ n_2 = \frac{1.33 \times 0.7071}{0.6275} \]
\[ n_2 \approx \frac{0.9405}{0.6275} \]
\[ n_2 \approx 1.50 \]
Therefore, the absolute index of refraction of medium X is approximately 1.50.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F666a7050-d460-4d4f-9624-d4bdba52f50b%2Fd52b5ddc-ee09-495d-84d1-d54e24e6271a%2Fusp8nu_processed.jpeg&w=3840&q=75)
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