A ray of light is incident on a pool with three layers of liquid in it at an angle of 75.0°. The top layer is 20.0m deep and has an index of refraction of 1.33. The middle layer is also 20.0m deep and has an index of refraction of 2.00. The bottom layer is 25.0m deep and has an index of refraction of 2.50. At the bottom of the pool there is a mirror that reflects the light back towards the surface. Calculate the time that the ray of light is in the pool, in other words the time taken between points A nd B. Use the speed of light in a vacuum c = 3 * 108 m/s. n₁ = 1.00 n2 = 1.33 n3 = 2.00 75.0⁰ A B 12 = 20.0m 13 = 20.0m
A ray of light is incident on a pool with three layers of liquid in it at an angle of 75.0°. The top layer is 20.0m deep and has an index of refraction of 1.33. The middle layer is also 20.0m deep and has an index of refraction of 2.00. The bottom layer is 25.0m deep and has an index of refraction of 2.50. At the bottom of the pool there is a mirror that reflects the light back towards the surface. Calculate the time that the ray of light is in the pool, in other words the time taken between points A nd B. Use the speed of light in a vacuum c = 3 * 108 m/s. n₁ = 1.00 n2 = 1.33 n3 = 2.00 75.0⁰ A B 12 = 20.0m 13 = 20.0m
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Question
![A ray of light is incident on a pool with three layers of liquid in it at an angle of 75.0°. The top layer is
20.0m deep and has an index of refraction of 1.33. The middle layer is also 20.0m deep and has an
index of refraction of 2.00. The bottom layer is 25.0m deep and has an index of refraction of 2.50. At
the bottom of the pool there is a mirror that reflects the light back towards the surface.
Calculate the time that the ray of light is in the pool, in other words the time taken between points A
and B. Use the speed of light in a vacuum c = 3 * 108 m/s.
Question 2: Waves
n₁ = 1.00
N₂ =
N22
1.33
n3 = 2.00
75.0°
LA
n4 = 2.50
mirror
B
12 = 20.0m
13 = 20.0m
14 = 25.0m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fefc0e927-4815-4e2f-82d9-9b6b5f419d74%2Fce8cf5ca-4bb3-4dd1-8393-3cb14be8c63e%2Fa0syaag_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A ray of light is incident on a pool with three layers of liquid in it at an angle of 75.0°. The top layer is
20.0m deep and has an index of refraction of 1.33. The middle layer is also 20.0m deep and has an
index of refraction of 2.00. The bottom layer is 25.0m deep and has an index of refraction of 2.50. At
the bottom of the pool there is a mirror that reflects the light back towards the surface.
Calculate the time that the ray of light is in the pool, in other words the time taken between points A
and B. Use the speed of light in a vacuum c = 3 * 108 m/s.
Question 2: Waves
n₁ = 1.00
N₂ =
N22
1.33
n3 = 2.00
75.0°
LA
n4 = 2.50
mirror
B
12 = 20.0m
13 = 20.0m
14 = 25.0m
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
To determine: The total time taken between point A and B
Use the Snell's law at air-water interface
where is the incident angle, and is the angle of refraction at water interface.
From the figure,
The index of refraction is
The velocity is ratio of length and time
Step by step
Solved in 2 steps
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