A randomized trial was conducted to determine if a medication was effective for depression. At total of 33 peopleparticipated in the study: 16 people in the medication group and 17 in the placebo group.Medication Groupn=16; standard deviation=3.68; mean depression score%=19.54Placebo Groupn=17; standard deviation= 4.93; mean depression score%-D23.39Which statement best describes the conclusion that can be drawn from this study?There is no statistically significant difference in depressive symptoms between the placebo group and the medicationgroup (P>0.15)There is a statistically significant difference in depressive symptoms between the placebo group and the medicationgroup (P<0.05)There is no statistically sigracant difference in depressive symptoms between the placebo group and the medicationgroup (P<.05)There is a statistically significant difference in depressive symptoms between the placebo group and the medicationgroup (P>0.15)QUESTION 13A doctor believes that the fruit and vegetable intake of Northern adolescents is different from the fruit and vegetable intakeof Southern adolescents. To study this, she gathers data on the number of fruits and vegetables eaten per week from arandom sample of Northern adolescents and a random sample of Southern adolescents.which is an appropriate nul hypothesis for the study?Save All AnswvaClick Save and Submit to save and subrit. Click Save All Answers to save all answers.40°F Cloud1Onere to search

Hypothesis tests are performed to test a claim about population parameter.

Answered: A randomized trial was conducted to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a test of effectiveness of garlic for lowering cholesterol, 44 subjects were treated with garli in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (inmg/dL) have a mean of 3.9 and a standard deviation of 15.6. What is the best point estimate of the population mean net change in LDL cholesterol after the garlic treatment? The best point estimate is mg/dl? Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean u?
You were told that the mean daily cost of a hotel room in downtown St. Louis is $120. You will be needing to rent a hotel room there in the near future and you want to find the best rate. You randomly select a sample of 18 hotel rooms and find that the average cost is $121.33 with a standard deviation of $18.046. At the α = 0.05 significance level, determine if there is enough evidence to reject the claim. What is the decision for this hypothesis test? You were told that the mean daily cost of a hotel room in downtown St. Louis is $120. You will be needing to rent a hotel room there in the near future and you want to find the best rate. You randomly select a sample of 18 hotel rooms and find that the average cost is $121.33 with a standard deviation of $18.046. At the α = 0.05 significance level, determine if there is enough evidence to reject the claim. What is the decision for this hypothesis test? Reject the null because the test statistic is in the critical region and the…
An educator has developed a program to improve math scores on the Texas STAAR test. The average STAAR Mathematics test for the third graders in the district was a mean= 1472. A sample of n= 30 third graders took the new math training prgram before taking the STAAR Math test. The average score for the students was M= 1497. with a standard deviation of s= 145 (note, this is standard deviation, not variance). Was there a significant change in test scores ( use stard devistion of 0.05, two tail test). Calculate the effect size using Cohen's d.
In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.9 and a standard deviation of 20.8. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. .... What are the null and alternative hypotheses? O B. Ho: H= 0 mg/dL O A. Ho: u= 0 mg/dL H,: µ0 mg/dL H1: µ> 0 mg/dL H,: µ<0 mg/dL Determine the test statistic. 0.39 (Round to two decimal places as needed.) Determine the P-value (Round to three decimal places as needed.)
Big babies: The National Health Statistics Reports described a study in which a sample of 96 one-year-old baby boys were weighed. Their mean weight was 25.6 pounds with standard deviation 5.3 pounds. A pediatrician claims that the mean weight of one-year-old boys is greater than 25 pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the =α0.05 level of significance and the P -value method and Excel. Part: 0 / 5 0 of 5 Parts Complete Part 1 of 5 (a)State the appropriate null and alternate hypotheses. H0 : =μ25 H1 : >μ25 This hypothesis test is a ▼two-tailed test. Part: 1 / 5 1 of 5 Parts Complete Part 2 of 5 (b)Compute the value of the test statistic. Round the answer to at least three decimal places.…
In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.8 and a standard deviation of 2.04. Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
purses Researchers conducted an experiment to test the effects of alcohol. Erors were recorded in a test of visual and motor skills for a treatment group of 21 people who drank ethanol and another group of 21 people given a placebo. The errors for the treatment group have a standard deviation of 2.10, and the errors for the placebo group have a standard deviation of 0.71. Use a 0.05 significance level to test the claim that the treatment group has errors that vary significantly more than the errors of the placebo group. Assume that the two populations are normally distributed. se Hom bus What are the null and alternative hypotheses? ndar O A. Ho: o =0 O B. Ho: of +o? ntation OC. Ho o =0 OD. Hoi o? =o} book puncem Identify the test statistic. (Round to two decimal places as needed.) gnments Use technology to identify the P-value. dy Plan (Round to three decimal places as needed.) debook What is the conclusion for this hypothesis test? O A. Reject Ho. There is sufficient evidence to…
In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.3 and a standard deviation of 16.4. Use a 0.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Researchers examined the bill color (in hue degree) of male and female zebra finches. Here are the summary statistics from the study. Sex N Mean Standard deviation Males 59 2.91 1.46 Females 60 7.42 2.48 How different are male and female zebra finches in bill color? The margin of error for a 95% confidence interval for the difference in mean bill color μF – μM (in hue degree) is
in a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol have a mean of 5.7 and a standard deviation of 17.7. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic and reducing LDL cholesterol?
Do shoppers at the mall spend more money on average the day after Thanksgiving compared to the day after Christmas? The 52 randomly surveyed shoppers on the day after Thanksgiving spent an average of $122. Their standard deviation was $29. The 59 randomly surveyed shoppers on the day after Christmas spent an average of $117. Their standard deviation was $35. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis.
Low-fat or low-carb? Are low-fat diets more effective for weight loss? A sample of 46 subjects went on a low carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 4.6 kilograms with a sample standard deviation of 6.28 kilograms. A second sample of 49 subjects went on a low-fat diet. Their sample mean weight loss was 2.3 kilograms with a standard deviation of 4.66 kilograms. Can you conclude that the mean weight loss differs between the two diets? Let μ1 denote the mean weight lost on the low-carb diet and μ2 denote the mean weight lost on the low-fat diet. Use the =α0.01level and the P-value method. Compute the test statistic. Round the answer to three decimal places. t =

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