Researchers are interested in the effect of pet companionship on depression in elderly adults. They randomly select 25 participants from the target population and record depression scores before and after spending a month with a dog (a higher score indicates a higher level of depression). The researchers then compute the difference sco for each participant (difference after - before). The mean of differences is -1 and the standard deviation of differences is 2. Can the researchers conclude that there is a effect of pet companionship on depression in elderly adults? Conduct the appropriate statistical test (two-tailed) with a = .05. Should you reject or fail to reject the null hypothesis? Reject
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- In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.7 and a standard deviation of 18.8. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 39 participants in the treatment group lowered their cholesterol levels by a mean of 19.8 points with a standard deviation of 2.1 points. The 46 participants in the control group lowered their cholesterol levels by a mean of 18.4 points with a standard deviation of 2.8 points. Assume that the population variances are not equal and test the company’s claim at the 0.05 level. Let the treatment group be Population 1 and let the control group be Population 2. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. what sign goes there H0:μ1=μ2 Ha: μ1⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯μ2 Step 2 of 3: Compute the value of the test statistic. Round any…In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.6 and a standard deviation of 2.43. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? Ο Α. Ho : μ=0 mg/dL B. Ho: µ= 0 mg/dL H1: µ#0 mg/dL H1: µ 0 mg/dL O D. Ho: µ= 0 mg/dL H1: µ >0 mg/dL H1:µ<0 mg/dL Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.)…
- Researchers are interested in the effect of pet companionship on depression in elderly adults. They randomly select 25 participants from the target population and record their depression scores before and after spending a month with a dog (a higher score indicates a higher level of depression). The researchers then compute the difference scores for each participant (difference = after before). The mean of differences is -1 and the standard deviation of differences is 2. Can the researchers conclude that there is an effect of pet companionship on depression in elderly adults? Conduct the appropriate statistical test (two-tailed) with a = .05. The 95% Confidence Interval for the population parameter is: [-6.16, 4.16] [-3.50, 1.50] [-1.83,-.17] [-3.06, 1.06]A professor has two Engineering Mathematics classes, X and Y. Class X has 13 students and class Y has 25 students. On the same test, although there was no significant difference in mean grades, class X had a standard deviation of 9 while class Y had a standard deviation of 12. Can we conclude at 1% level of significance, that the variability of class Y is greater than that of X?Suppose Ava, an education researcher, wants to understand the relationship between foreign language skills and English verbal aptitude for middle school students in her school district. In order to draw an inference about the population linear correlation coefficient, p, for foreign language skills and English verbal aptitude, she conducts a hypothesis test at a significance level of a = 0.01 to determine if there is a significant linear correlation between the two variables. Ava selects a simple random sample of 33 Verbal aptitude test score vs. foreign language grade eighth grade students within her school district. She gathers the students' final seventh 80- grade foreign language course grades and their test scores from an English verbal 60 - aptitude test. 40- Ava produces a scatter plot with the foreign language course grades on the horizontal axis and the verbal aptitude test scores on the 20 - vertical axis. The Pearson product-moment correlation coefficient, r, for her sample…
- In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.1 and a standard deviation of 21.2. Use a 0.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? B. Ho: μ=0 mg/dL ⒸA. Ho: μ = 0 mg/dL H₁: μ#0 mg/dL H₁: μ 0 mg/dL H₁: μ> 0 mg/dL H₁: <0 mg/dL Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.)Researchers are interested in the effect of pet companionship on depression in elderly adults. They randomly select 25 participants from the target population and record their depression scores before and after spending a month with a dog (a higher score indicates a higher level of depression). The researchers then compute the difference scores for each participant (difference after before). The mean of differences is - 1 and the standard deviation of differences is 2. Can the researchers conclude that there is an effect of pet companionship on depression in elderly adults? Conduct the appropriate statistical test (two-tailed) with a = .05. Based on the information provided above, which statistical test seems most appropriate? one sample t test O z test independent samples t test O dependent samples t testA researcher is interested in whether North Americans are able to identify emotions correctly in people from other cultures. It is known that, using a particular method of measurement, the accuracy ratings of adult North Americans in general are normally distributed with a mean of 82 and a variance of 20. This distribution is based on ratings made of emotions expressed by other North Americans. In the present study, however, the researcher arranges to test 50 adult North Americans rating emotions of individuals from Vulcan. The mean accuracy for these 50 individuals was 78. What should the researcher conclude?
- After post-graduate study, Mike found a job as HR analyst in London. The company is currently recruiting Chief Marketing Officer. The HR department recently sent out a knowledge test to the applicants after the initial CV screening. At this stage of selection, the company does not invite the lowest scoring 30% back for the next face-to-face interview. According to the historical data, the test scores on this test are normally distributed and has a mean of 70 with standard deviation of 10. What mark (to the nearest whole number) must a candidate achieve in order to secure an interview? 2. How much is the 95% confidence interval for the test scores?In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.6 and a standard deviation of 1.54. Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.Medical researchers are interested in determining the relative effectiveness of two drug treatments on patients with a chronic mental illness. Treatment 1 has been around for many years, while treatment 2 has recently been developed based on the latest research. The researchers chose two independent test groups. The first group had 9 patients, all of whom received treatment and had a mean time until remission of 166 days, with a standard deviation of 8 days. The second group had 15 patients, all of whom received treatment 2 and had a mean time until remission of 161 days, with a standard deviation of 9 days. Assume that the populations of times until remission for each of the two treatments are normally distributed with equal variance. Can we conclude, at the 0.05 level of significance, that u, the mean number of days until remission after treatment 1, is greater than u,, the mean number of days until remission after treatment 2? Perform a one-tailed test. Then complete the parts…