A random sample of size 60 is taken from a population with meanu - 55 and standard deviation a-18. Consider the sample mean from this random sample. Which of the following statements is (are) correct? This is a multiple-answer question. It may have more than one correct answers. Oi. Because we have a large sample, the Central Limit Theory tell us that the sample mean has a normal distribution. Oii. The sampling distribution of the sample mean has a mean of 55 and a standard deviation of 18. Diil. The probability that the sample mean is greater than 50 is P(x>50)=P(2> 50-55) = P(Z > -0.28) = 0.6103 Div. The probability that the sample mean is greater than 50 is P(50) = P(Z >=50)=P(2 > 2.15) = 0.0158 v. The probability that the sample mean is greater than 50 is P(x>50)=P 50-55 = P(z>-2.15) = 0.9842

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A random sample of size 60 is taken from a population with meanu - 55 and standard deviation a 18. Consider
the sample mean from this random sample.
Which of the following statements is (are) correct? This is a multiple-answer question. It may have more than one
correct answers.
Oi. Because we have a large sample, the Central Limit Theory tell us that the sample mean has a normal distribution.
Oil. The sampling distribution of the sample mean has a mean of 55 and a standard deviation of 18.
Oiii. The probability that the sample mean is greater than 50 is
P(x > 50) = P (z > 50-55) = P(Z > -0.28) = 0.6103
10
Div. The probability that the sample mean is greater than 50 is
P(x >50) = P(Z > 55150) = = P(z > 2.15) = 0.0158
Ov. The probability that the sample mean is greater than 50 is
P(x>50)=P
50-55
픔
= P(z>-2.15) = 0.9842
Transcribed Image Text:A random sample of size 60 is taken from a population with meanu - 55 and standard deviation a 18. Consider the sample mean from this random sample. Which of the following statements is (are) correct? This is a multiple-answer question. It may have more than one correct answers. Oi. Because we have a large sample, the Central Limit Theory tell us that the sample mean has a normal distribution. Oil. The sampling distribution of the sample mean has a mean of 55 and a standard deviation of 18. Oiii. The probability that the sample mean is greater than 50 is P(x > 50) = P (z > 50-55) = P(Z > -0.28) = 0.6103 10 Div. The probability that the sample mean is greater than 50 is P(x >50) = P(Z > 55150) = = P(z > 2.15) = 0.0158 Ov. The probability that the sample mean is greater than 50 is P(x>50)=P 50-55 픔 = P(z>-2.15) = 0.9842
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