A random sample of size 18 is drawn from a normal population. What will be the judgment at 5% level of significance about the stated claim, given that the sample m the sample standard deviation is 6.4? HO: u 2 30 O The claim is not rejected because the test statistic < +1.740 O The claim is rejected because the test statistic < -1.740 O The claim is not rejected because the test statistic > -1.740 O The claim is rejected because the test statistic > +1.740
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- One-Sample Z: Test of 35 vs not 35 %3D The assumed standard deviation 1.8 Variable N Мean StDev SE Mean 25 35.710 1.475 а. b. с. d. Is this a one-sided or a two-sided test? e. What would be the P-value if the alternative hypothesis is H1: µ > 35 v a. a. 0.00805 v b. b. 0.0243 v C. c. 2.4068 v d. d. 0.0486 е. 1.9722 е. f. Two-sided hypothesis test g. 0.295 h. One-sided test because alternative hypothesis, H : µ # 35 i. 0.360A statistics student randomly selected 45 packets of sugar and weighed the contents of each packet, getting a mean of 3.586 g and a standard deviation of 0.194 g. Test the claim that the weights of the sugar packets have a mean no longer equal to 3.5 g, as indicated on the label. Let "alpha" be 0.10 to test this claim. What is the decision/summary statement for this test?The mean SAT score in mathematics is 513. The standard deviation of these scores is 49. A special preparation course claims that the mean SAT score, μ, of its graduates is greater than 513. An independent researcher tests this by taking a random sample of 70 students who completed the course; the mean SAT score in mathematics for the sample was 517. At the 0.05 level of significance, can we conclude that the population mean SAT score for graduates of the course is greater than 513? Assume that the population standard deviation of the scores of course graduates is also 49. Perform a one-tailed test. 1. I just need to know what the test statistic is rounded to 3 or more decimal places.
- A discount airline allows staff 36.0 minutes between flights to clean the aircraft interior. The aircraft workers union claims that that average time that it takes to this cleaning is more than 36.0 minutes. They want to carry out a hypothesis test. They take a random sample n = 40 flights and time how long it takes to carry out the cleaning. They find that the sample mean is 36.66 minutes and the sample standard deviation is 5.56 minutes. Calculate the test statistic for this test and enter your answer below. Give your answer to 2 decimal places.Assume the height of a particular species of horse are normally distributed. A random sample of 7 horses has a mean height of 46.14 cm and a standard deviation of 1.19 cm. At a 0.05 level of significance, a test is undertaken to determine whether there is sufficient evidence to reject the claim of a mean height is higher than 45 cm. What statement can be made about the p-value?The mean SAT score in mathematics is 537. The standard deviation of these scores is 31. A special preparation course claims that the mean SAT score, μ, of its graduates is greater than 537. An independent researcher tests this by taking a random sample of 70 students who completed the course; the mean SAT score in mathematics for the sample was 547. At the 0.01 level of significance, can we conclude that the population mean SAT score for graduates of the course is greater than 537? Assume that the population standard deviation of the scores of course graduates is also 31. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) Español ? (a) State the null hypothesis H, and the alternative hypothesis H₁. μ σ р x❘ S H₁ : (b) Determine the type of test statistic to use. (Choose one)▼ (c) Find the value of the test statistic.…
- Assume the average amount of days a patient spends in hospital is believed to be 24 days and a hospital claims that their experience suggests that the average is actually lower. They randomly selected and followed 33 patients and found that the mean number of days was 21.5 with a standard deviation of 7.8. What is the test statistic and your conclusion for a=0.05? O A. Test statistic: -1.841 Conclusion: Not enough evidence to reject the null hypothesis O B. Test statistic: 1.841 Conclusion: Not enough evidence to reject the null hypothesis O C. Test statistic: 1.841 Conclusion: Reject the null hypothesis D. Test statistic: -1.841 Conclusion: Reject the null hypothesisThe mean SAT score in mathematics is 554. The standard deviation of these scores is 39. A special preparation course claims that the mean SAT score, µ, of its graduates is greater than 554. An independent researcher tests this by taking a random sample of 60 students who completed the course; the mean SAT score in mathematics for the sample was 567. At the 0.01 level of significance, can we conclude that the population mean SAT score for graduates of the course is greater than 554? Assume that the population standard deviation of the scores of course graduates is also 39. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H. and the alternative hypothesis H,. Ho : H, :0 (b) Determine the type of test statistic to use. D=0 OSO (Choose one) (c) Find the value of the test statistic. (Round to…The weights of pre-1983 pennies have standard deviation greater than 0.0231 g. A simple random sample of 38 pennies shows a standard deviation of 0.0278 g. Test the claim that the weights of pre-1983 pennies have a standard deviation greater than 0.0231 g at the 5% significance level. Assume that the sample is from a normally distributed population. What are the correct hypotheses? (Select the correct symbols and values.)H0: Select an answer p̂ x̄ p s² s σ² μ σ ? > ≤ ≥ ≠ < = g Original claim = Select an answer H₁ H₀ H1: Select an answer σ² s μ p̂ s² σ x̄ p ? ≥ > ≤ < = ≠ g Enter the critical values, along with the significance level and degrees of freedom χ2χ2(αα,df) below the graph. (Graph is for illustration only. No need to shade.) Test Statistic = (Round to three decimal places.) Decision: Select an answer Accept the alternative hypothesis Fail to reject the null hypothesis Accept the null hypothesis Reject the null hypothesis . Conclusion: Select an…
- The mean SAT score in mathematics is 228. The standard deviation of these scores is 30. A special preparation course claims that the mean SAT score, H, of its graduates is greater than 258. An independent researcher tests this by taking a random sample of 20 students who completed the course; the mean SAT Score in mathematics for the sample was 209. At the 0.05 level of significance, can we conclude that the population mean SAT score for graduates of the course is greater than 2587 Assume that the population standard deviation of the scores of course graduates is also 30. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) state the null hypothesis H, and the alternative hypothesis H. H :0 H :0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more…Also need margin of error.A scientist wants to know if the average weight of a particular species of fish is different from 500 grams. He collects a sample of 15 fish and finds that their average weight is 490 grams with a standard deviation of 20 grams. Can he reject the null hypothesis that the true average weight of the fish is 500 grams, using a one sample t-test with a significance level of 0.05?