A random sample of 92 observations produced a mean x= 25.9 and a standard deviation s = 2.5.a. Find a 95% confidence interval for µ.b. Find a 90% confidence interval for µ.c. Find a 99% confidence interval for u.a. The 95% confidence interval is ( D(Use integers or decimals for any numbers in the expression. Round to two decimal places as needed.)

Name: A random sample of 92 observations produced a mean x= 25.9 and a stan
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: A random sample of 92 observations produced a mean x= 25.9 and a standard deviation s = 2.5.a. Find a 95% confidence interval for µ.b. Find a 90% confidence interval for µ.c. Find a 99% confidence interval for u.a. The 95% confidence interval is ( D

Answered: Image /qna-images/answer/01a3aa39-6788-4248-ae16-7fa5da6a262e.jpg

Math

Statistics

A random sample of 92 observations produced a mean x =25.9 and a standard deviations=2.5. a. Find a 95% confidence interval for u. b. Find a 90% confidence interval for u. c. Find a 99% confidence interval for u. a. The 95% confidence interval is (|| D. (Use integers or decimals for any numbers in the expression. Round to two decimal places as needed.)

A random sample of 92 observations produced a mean x =25.9 and a standard deviations=2.5. a. Find a 95% confidence interval for u. b. Find a 90% confidence interval for u. c. Find a 99% confidence interval for u. a. The 95% confidence interval is (|| D. (Use integers or decimals for any numbers in the expression. Round to two decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

In a survey, 11 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $30 and standard deviation of $7. Construct a confidence interval at a 99% confidence level. Write in format ¯x ± M.O.E.Give your answers to one decimal place.(¯x) (M.O.E.)____________ ± __________
Suppose the standard deviation of the losses had been $3600 instead of $1800. What would the larger standard deviation do to the width of the confidence interval assuming the same level of confidence.
The 85.7% confidence interval estimate for p was (0.14, 0.16). Find ?′ and ME.
Give a 95% confidence interval for the true mean time students spent practicing for the play. x-bar=45.6 s=13.3 n=120
The mean and the standard deviation of a population are 11795 and 14054 respectively. If n = 50, find 95% confidence interval for the mean. a. 7899.43 and 15690.57 b. 7989.34 and 16590.75 c. 7998.43 and 16509.75 d. 7843.99 and 15657.90 e. NONE OF THE ABOVE
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
If [0.64, 0.82] is a confidence interval for the population proportion. Find the value of the point estimator of the population proportion. Select one: O a. 0.73 O b. 0.70 O c. 0.74 O d. 0.72
If [1740, 1850 is a confidence interval for a population mean. Find the margin of error. Select one: a. 60 O b. 80 C. 55 O d. 40
A statistics class is estimating the mean height of all female students at their college. They collect a random sample of 42 female students and measure their heights. The mean of the sample is 65.3 inches and the sample standard deviation is 5.4 inches. Find the 90% confidence interval for the mean height of all female students in their school? Assume that the distribution of individual female heights at this school is approximately normal. 1. The t value is 1.3025 2. The standard error has a value of -- 3. The margin of error has a value of 4. Find the 90% confidence interval for the mean height of all female students in their school
There are several sections of Statistics; some in the morning and some in the afternoon. We randomly select n1 40 from the morning section and 44 from the afternoon section. The averages n2 of their scores are X1 76.3 for the morning section and X, = 71.9 for the afternoon section. The known standard deviations of their scores are 01 12.05 for the morning section and 02 13.06 for the afternoon section. Test the claim that the average for all students in the morning and afternoon section is the same. Use a a = 0.05 significance level. a. What is the negative critical region? Give your answer to two decimal places. z c. What is the test statistic? Give your answer to two decimal places. z = d. Do we reject or fail to reject the null hypothesis? OReject Ho OFail to reject Họ
Given that the confidence level is x %, give an expression in terms of x for a.
tion. Use this information to construct the 90% and 95% confidence intervals fc of the confidence intervals. ce of a certain stock was $123.13. Assume the population standard deviation is