A random sample of 80 people was selected, and 22 of the selected people indicated that it would be a good idea to eliminate the penny from circulation. What is the 99 percent confidence interval constructed from the sample proportion p ? |(22)(58) A 0.275 ± 1.96- 80 (0.275)(0.725) B 0.22 ± 2.576/ 80 (0.275)(0.725) C 0.275 ± 2.576 v 80 (0.275)(0.725) 0.275 ± 1.96, 80 |(0.275)(0.725) 0.22 ± 2.323 / 80

A random sample of 80 people was selected, and 22 of the selected people indicated that it would be a good idea to eliminate the penny from circulation. What is the 99 percent confidence interval constructed from the sample proportion p ? |(22)(58) A 0.275 ± 1.96- 80 (0.275)(0.725) B 0.22 ± 2.576/ 80 (0.275)(0.725) C 0.275 ± 2.576 v 80 (0.275)(0.725) 0.275 ± 1.96, 80 |(0.275)(0.725) 0.22 ± 2.323 / 80

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

According to statistics published by CNBC, the amount they are insured is surprising. CNBC's sample results indicate that 57 out of 84 vehicles were uninsured. Give a 95% confidence interval for the population proportion of the form p ± E where p is the point estimator of the proportion and E is the margin of error. Select one: a. The interval is 0.321 ± 0.100. b. The interval is 0.321 ± 0.084. c. The interval is 0.679 ± 0.100. d. The interval is 0.679 ± 0.131. e. The interval is 0.679 ± 0.084.
In anticipation of an upcoming election, officials in Grand Ridge County are looking at the distance from each voter's horne to that voter's nearest polling station. Assume that the population of all such distances for voters in Grand Ridge County is approximately normally distributed. An artide for the newspaper Politically Sound claimed that the mean of this population is 5.19 km. You want to test this claim, so you select a random sample of 25 Grand Ridge County voters, and for each you record the distance the voter lives from their nearest polling station. Follow the steps below to construct a 95% confidence interval for the population mean of all the distances voters in Grand Ridge County live from their nearest polling station. Then state whether the confidence interval you construct contradidcts the reporter's daim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Sample standard deviation Number of people Sample…
Based on data from a survey of 1,300 randomly selected Facebook users, a 95% confidence interval for the proportion of all Facebook users who say it is not OK to "friend" someone who reports to you at work is (0.60, 0.64). What is the meaning of the 95% confidence level associated with this interval? If a large number of random samples of size 1,300 were to be taken, % of the resulting confidence intervals would contain the true proportion of all Facebook users who would say it is to "friend" someone who reports to you at work.
#2
During the 2009 holiday season, 436 randomly sampled American adults were surveyed regarding their average spending on Black Friday. A 95% confidence interval based on this sample is ($80.31,$89.11). (c) Determine the sample mean x and the sample standard deviation s of the sample. (d) Which would be the confidence level corresponding to an interval ($81.27,$88.15) for the data found in (c)? (e) If the values of the sample mean and sample standard deviation found in (c) do not change, find the sample size N for which a 99% confidence interval would have a margin of error smaller than 5.
Harper's Index reported that 80% of all supermarket prices end in the digit 9 or 5. Suppose you check a random sample of 112 items in a supermarket and find that 87 have prices that end in 9 or 5. Does this indicate that fewer than 80% of the prices in the store end in the digits 9 or 5? Use α = 0.05. 1. What is the value of the sample test statistic? (Round your answer to two decimal places.) 2. Find the P-value of the test statistic. (Round your answer to four decimal places.)
A 98% confidence intervals for the proportion of first-year statistics students with brown hair is given to be (0.28, 0.42).(d) What is the standard error of the estimate?(Round to 3 decimal places, if needed.)(e) What was the sample size?(Round to the appropriate integer.)
A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 respondents, 13% chose chocolate pie, and the margin of error was given as ±4 percentage poits. Describe what is meant by the statement that "the margin of error was given as ±4 percentage points." (...) Choose the correct answer below. OA. The statement indicates that the study is only 4% confident that the true population percentage of people that prefer chocolate pie is exactly 13%. OB. The statement indicates that the study is 100% -4% = 96% confident that the true population percentage of people that prefer chocolate pie is 13%. OC. The statement indicates that the interval 13% ± 4% is likely to contain the true population percentage of people that prefer chocolate pie. D. The statement indicates that the true population percentage of people that prefer chocolate pie is in the interval 13% ± 4%.
(a) A random sample of n = 36 students who took an examination yields the confidence interval (73 , 74), for the population mean u. The standard deviation o = 1.875. Find the confidence coefficient 100(1 – a)% of this interval. (b) Assume o = 2. How many students should be selected in order to be 98% confident that the margin of error E = +0.6 ?
13
A researcher wishes to estimate the percentage of adults who support abolishing the penny . What size sample should be obtained if he wishes the estimate to be within 5 percentage points with 95 % confidence if ( a he uses a previous estimate of 24% ? (b ) he does not use any prior estimates ?
In a recent poll, 300 people were randomly sampled, and 90% said they liked dogs. Use the Theory-Based Inference applet to find a 95% confidence interval for the true population proportion of people who like dogs, T. (a) We are 95% confident that the proportion of all people who like dogs is between 9 % and % Give your percentage answers rounded to one decimal place. For example, if the applet gives (0.34218, 0.61352) then you would enter 34.2 and 61.4. (b) The sample statistic is 0.9 Give your answer as a dEnter an integer or decimal number [more.Jo not round. (c) The margin of error is 0.024 Give your answer as a decimal using your answers form parts (a) and (b). (d) The confidence interval from part (c) can be written as ± Give your answers as decimals (NOT percentages), and do not round.