In anticipation of an upcoming election, officials in Grand Ridge County are looking at the distance from each voter's horne to that voter's nearest polling station.Assume that the population of all such distances for voters in Grand Ridge County is approximately normally distributed. An artide for the newspaper PoliticallySound claimed that the mean of this population is 5.19 km. You want to test this claim, so you select a random sample of 25 Grand Ridge County voters, andfor each you record the distance the voter lives from their nearest polling station.Follow the steps below to construct a 95% confidence interval for the population mean of all the distances voters in Grand Ridge County live from their nearestpolling station. Then state whether the confidence interval you construct contradidcts the reporter's daim. (If necessary, consult a list of formulas.)(a) Click on "Take Sample" to see the results for your random sample.Sample standarddeviationNumber of peopleSample meanTake Sample254.8132.306Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 95%confidence interval. (Choose the correct critical value from the tablecritical values provided.) When you are done, select "Compute".Sample size:Standard error:Point estimate:Critical valuesSample standard deviation:Margin of error:0.00s -2.7976.010 =2.492Critical value:0.025 -2.06495% confidence interval:heso-1.711ExplanationCheck2021 McGraw H Education. All Rights Reserved Terms of UseMacBook Air888 .esc%232$%&456.93QERFKCValaltcommandoptoptioncommandin (b) Basea on your sample, graph the 95% confidence interval for the population mean of all the distances the voters in Grand Ridge County live from theirnearest polling station.• Enter the values for the lower and upper limits on the graph to show your confidence interval.• For the point (), enter the claim 5.19 from the article.95% confidence interval:0.00010.0005.0000.0002.0004.0006.0008.00010.000(c) Does the 95% confidence interval you constructed contradict the claim made in the article?Choose the best answer from the choices below.O No, the confidence interval does not contradict the claim. The mean of 5.19 km from the article is inside the 95%confidence interval.O No, the confidence interval does not contradict the claim. The mean of 5.19 km from the article is outside the 95%confidence interval.O Yes, the confidence interval contradicts the claim. The mean of 5.19 km from the articleinside the 95% confidenceinterval.O Yes, the confidence interval contradicts the claim. The mean of 5.19 km from the articleinterval.outside the 95% confidenceExplanationCheck2021 McGraw-Hill Education. All Rights Reserved Terms of UseMacBook Air888FアF2F32324&23478YUPQWEGH.KCVcommandoncommandしのR

Given : Point Estimate , Xˉ\bar X = 4.8134.813 Sample Standard Deviation (s)(s) = 2.3062.306…

(b) Baseo on your sample, graph the 95% confidence interval for the population mean of all the distances the voters in Grand Ridge County live from the nearest polling station. • Enter the values for the lower and upper limits on the graph to show your confidence interval. • For the point (•), enter the claim 5.19 from the article. 95% confidence interval: 0.000 10.000 5.000 0.000 2.000 4.000 6.000 8.000 10.000 5 ? (c) Choose the best answer from the choices below. Does the 95% confidence interval you constructed contradict the claim made in the article? O No, the confidence interval does not contradict the claim. The mean of 5.19 km from the artide is inside the 95% confidence interval. O No, the confidence interval does not contradict the claim. The mean of 5.19 km from the article is outside the 95% confidence interval. O Yes, the confidence interval contradicts the claim. The mean of 5.19 km from the article is inside the 95% confidence interval. O Yes, the confidence interval contradicts the claim. The mean of 5.19 km from the article is outside the 95% confidence

(b) Baseo on your sample, graph the 95% confidence interval for the population mean of all the distances the voters in Grand Ridge County live from the nearest polling station. • Enter the values for the lower and upper limits on the graph to show your confidence interval. • For the point (•), enter the claim 5.19 from the article. 95% confidence interval: 0.000 10.000 5.000 0.000 2.000 4.000 6.000 8.000 10.000 5 ? (c) Choose the best answer from the choices below. Does the 95% confidence interval you constructed contradict the claim made in the article? O No, the confidence interval does not contradict the claim. The mean of 5.19 km from the artide is inside the 95% confidence interval. O No, the confidence interval does not contradict the claim. The mean of 5.19 km from the article is outside the 95% confidence interval. O Yes, the confidence interval contradicts the claim. The mean of 5.19 km from the article is inside the 95% confidence interval. O Yes, the confidence interval contradicts the claim. The mean of 5.19 km from the article is outside the 95% confidence

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Find the test statistics, p-value and confidence interval using statcrunch or excel. thank you
What is the multiplier for an interval that estimates the proportion with a. 88% confidence? b. 98% confidence?
Get an education: In 2012 the General Social Survey asked 844 adults how many years of education they had. The sample mean was 8.54 years with a standard deviation of 8.58 years.
Use the confidence interval to find the margin of error and the sample mean. (1.77, 2.01) The margin of error is
You must estimate the mean. 60, 59.3, 49.7, 23.9, 44, 39.4, 85.2, 46 mean = 50.9375Find the 98% confidence interval. Enter your answer as an open interval (i.e. parentheses) accurate to two decimal places.
Kindly answer the following questions: (Use 5% level of significance if needed)
Determine the margin of error for the confidence interval for the mean: 23 +1.7 The margin of error is
Prob & Stats Unable to solve 90% confidence interval of the differences in the nurses.
Please write neat and visible
1. Explain how to find a confidence interval for a population proportion using StatCrunch. 2. Explain how to find the margin of error given a confidence interval for a population proportion.
Explain the difference between a point estimate and confidence interval. Provide an example.
Use the confidence interval to find the margin of error and the sample mean. (1.57,1.95) The margin of error is enter your response here.