A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 20 14 23 22 22 15 21 18 17 14 25 15 21 20 14 23 Click here for the Excel Data File Find a 90 percent confidence interval for u, assuming that the sample is from a normal population. (Round your standard deviation answer to 4 decimal places and t-value to 3 decimal places. Round your answers to 3 decimal places.) The 90% confidence interval to
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- USE 3 DECIMAL A researcher believes that reading habit of newspaper is decreasing every year. In order to see the true population proportion of people who are reading newspaper s/he collect a randomly selected people on the yearly basis . The following table gives the number of people who do not read newspaper with respect to the years . Construct a 90 % confidence interval for the true population proportion difference of people who are reading newspaper in 2005 and 2010 . 2010 2005 n 1200 1000 Number of people who do not read newspaper 300 400size Price 9 147 20 197 27 297 31 447 35 1177 40 2177 60 2497 32 1006.93 50 1992.61 Find and interpret a 90% confidence interval for the sales price when the corresponding TV size is 50-inchesPumpkins from a local farmer have a mean weight of 16 pounds with a standard deviation of 2.5 pounds. What is the z-score of an 21 pound pumpkin? z=-2 z=+2 z=-1 z=+1
- Solve it correctly please. I will rate accordingly.A 2016 study done in Germany was doing research on parents and wanted to determine the percent of parents that regret having children. To do so, they randomly selected 400 parents and found that 36 of them regret having children. Construct and interpret a 99% confidence interval for the proportion of parents that regret having children. Round your answers to two decimal places. Edit View Insert Format Tools Table 12pt v Paragraph v U AA study was conducted to measure the effectiveness of hypnotism in reducing pain. The measurements are centimete on a pain scale before and after hypnosis. Assume that the paired sample data are simple random samples and that th differences have a distribution that is approximately normal. Construct a 95% confidence interval for the mean of the "before - after" differences. Does hypnotism appear to be effective in reducing pain? Before After 4.8 6.3 2.4 2.6Please fill in the empty boxes to B & CYou do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each night. You measure hours of sleep for 12 subjects with the following results. Construct a 90% confidence interval for the mean number of hours slept for the population (assumed normal) from which you took the data. (Give your answer rounded to the nearest 4 decimal places if necessary.) {7.8, 8.9, 9.5, 11.2, 11.5, 8.3, 11.8, 8.4, 8, 8.4, 10.1, 10.3} (?,? )A study was conducted to measure the effectiveness of hypnotism in reducing pain. The measurements are centimeters on a pain scale before and after hypnosis. Assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal. Construct a 95% confidence interval for the mean of the "before-after" differences. Does hypnotism appear to be effective in reducing pain? Before After 6.3 6.8 2.4 7.3 11.8 8.3 7.5 3.4 5.4 2.3 7.9 8.6 8.1 6.3 3.3 2.7 Construct a 95% confidence interval for the mean of the "before-after" differences. -0.40You may need to use the appropriate appendix table or technology to answer this question. Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of 68 weekly reports showed a sample mean of 17.5 customer contacts per week. The sample standard deviation was 5.2. Provide a 90% confidence interval for the population mean number of weekly customer contacts for the sales personnel. (Round your answers to two decimal places.) X contacts/week to contacts/week Provide 95% confidence interval for the population mean number of weekly customer contacts for the sales personnel. (Round your answers to two decimal places.) X contacts/week X contacts/week toHelga is investigating IQ in certain monkey species. The measured the IQ of 15 monkeys with a special monkey IQ test and found it to be 120 points on average. The standard deviation was 12 points. The IQ grades can be assumed to be normally distributed. What are the upper limit of a 95 % confidence interval for the mean IQ of the monkey species? 1. 125.46. 2. 126.65. 3. 113.35. 4. 126.10. 5. R-command:A test of writing ability is given to a random sample of 11 students before and after they completed a formal writing course. The results are given below: Before: Mean = 80.27, standard deviation = 12.76 After: Mean = 78.27, standard deviation = 12.92 Before/After: Mean = 2, standard deviation = 2.65 Construct a 99% confidence interval for the mean differencebetween the before and after scores. 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