A study was conducted to measure the effectiveness of hypnotism in reducing pain. Themeasurements are centimeters on a pain scale before and after hypnosis. Assume that the pairedsample data are simple random samples and that the differences have a distribution that isapproximately normal. Construct a 95% confidence interval for the mean of the "before - after"differences. Does hypnotism appear to be effective in reducing pain?BeforeAfter5.06.86.32.5

The formula for the Confidence interval for paired differences between the mean is:

Answered: A study was conducted to measure the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

9% of US employees who are late for work blame Oversleeping. You randomly select 4 US employees who are late and ask if they blame oversleeping. The random variable represents the number of US employees who are late and blame over sleeping. the mean ? the variance? the standard deviation? The avg # of adults that blame over sleeping would differ from the mean no more than ?
Low-fat or low-carb? Are low-fat diets or low-carb diets more effective for weight loss? A sample of 77 subjects went on a low-carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 4.4 kilograms with a sample standard deviation of 7.3 kilograms. A second sample of 81 subjects went on a low-fat diet. Their sample mean weight loss was 2.7 kilograms with a standard deviation of 5.8 kilograms
What is the effect on a confidence interval if one decreases both sample size and the level of confidence?
In a study on running and happiness, runners indicated the number of miles they ran in a day and their subsequent score on a Happiness Survey (higher score = greater happiness). Runner # of miles (x) Happiness Score (y) 1 16 12 2 4 3 12 14 4 2 8 For these data: The mean of miles run is: 8.50 The mean of the Happiness scores is: 10.00 The standard deviation of the Miles scores is: 5.72 The standard deviation of the Happiness scores is: 3.16 In your submission, please include a copy of the SPSS or Excel output and answer the following: A. What is the r and r? value? B. Based on Pearson's r and r2 value, describe the relationship (direction/strength) that exists between # of miles run and Happiness scores. C. Create a scatterplot for the data using Excel or SPSS (include output in your submission). D. Insert the prediction line from Excel/SPSS on your scatterplot.
The incomes of math tutors in a tutoring center of a university are normally distributed with a mean of $1100 and a standard deviation of $150 what percentage of tutors earn less than $900 a month
Advanced Math
When a t-test is used to compare pre- and post-treatment data. What does the t-test reveal about the difference between baseline and treatment?
Low-fat or low-carb? Are low-fat diets or low-carb diets more effective for weight loss? A sample of 77 subjects went on a low-carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 4.7 kilograms with a sample standard deviation of 7.16 kilograms. A second sample of 79 subjects went on a low-fat diet. Their sample mean weight loss was 2.6 kilograms with a standard deviation of 5.90 kilograms. Can you conclude that the mean weight loss differs between the two diets? Let 4, denote the mean weight lost on the low-carb diet and u, denote the mean weight lost on the low-fat diet. Use the a = 0.01 level and the TI-84 Plus calculator. Compute the -value. Round the answer to four decimal places. Determine whether to reject H0 State a conclusion
When solving a problem related to one sample and the confidence interval of variance. Suppose the sample size is n. What is the degree of freedom we will use?
Find z given a 94% confidence interval and a= 0.06. z = ?
Fear of heights - A psychologist has developed a new treatment for acrophobia (the extreme fear of heights) and wants to compare the results of this new treatment to the results of the standard treatment. A study is conducted where a random sample of 16 patients undergo the new treatment and their improvement scores on a diagnostic test are compared to a control sample of 13 patients who received the standard treatment. Summary scores for both groups are shown in the table below. Treatment Sample Mean Sample Standard Deviation New 50.9 12 Standard 47.2 11.4 The degrees of freedom for this problem is d f 26.287709. 1. Select the hypotheses that should be used to assess if the new treatment results in higher average improvement scores than the standard treatment. А. Но : И1 = µ2 vs. Ha : H1 # µ2 OB. Ho : µ1 = µ2 vS. Ha : H1 H2 2. Calculate the test statistic. ? V = 3. Calculate the p-value. p-value =
A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?

SEE MORE QUESTIONS

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS