You are interested in finding a 98% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute milesfor 11 randomly selected non-residential college students. Round answers to 3 decimal placeswhere possible.21 19 24 21 24 7 28 27 7 10 18a. To compute the confidence interval use a tdistribution.b. With 98% confidence the population mean commute for non-residential college students isbetweenandmiles.percent ofc. If many groups of 11 randomly selected non-residential college students are surveyed, then adifferent confidence interval would be produced from each group. Aboutthese confidence intervals will contain the true population mean number of commute miles andaboutpercent will not contain the true population mean number of commute miles.

Given 21 ,19 ,24 ,21 ,24 ,7 ,28 ,27 ,7 ,10 , 18 N=11

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which one of the following statements about confidence intervals is false? Given the same sample of data, a 99% confidence interval will be wider than a 95% confidence interval. The size of the population affects the width of a confidence interval. The sample statistic determines the center of the confidence interval. The value of z* affects the width of a confidence interval. The general format of a confidence interval is “sample statistic ± margin of error.”
Solve the following. Show your complete solution The incoming freshman students of a particular college are required to take a mathematics placement examination. As an experiment, 8 randomly selected students were given the exam and then made to join a 4-hour refresher class. These students were given a re-test after the refresher class. Assuming the distribution of scores was approximately normal, construct a 90% confidence interval for the mean difference of the exam scores.
do fast ..with explanation both require..
You are interested in finding a 99% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 12 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 18 20 20 24 5 28 10 13 5 24 11 11 b. With 99% confidence the population mean commute for non-residential college students is between ? and ? miles. c. If many groups of 12 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population mean number of commute miles and about ? percent will not contain the true population mean number of commute miles.
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suppose a random sample of 50 basketball players have an average height of 78 inches. Also assume that the population standard deviation is 1.5 inches. I need to Calculate the 99% 95% 90% 80% and 70% confidence interval. The thing is my answers using the formula from class isn't giving me the answers my professor posted.
Use the given confidence interval to find the margin of error and the sample mean. (15.3,23.7) The sample mean is . (Type an integer or a decimal.) The margin of error is. (Type an integer or a decimal.)
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Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
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