A random sample of 100 voters in a community produced 59 voters in favor of Candidate A. The observed value of the test statistic for testing the null hypothesis alternative hypothesis H.:p>0.5 H₁: p=0.5 versus the is ==[(0.59-0.5)/√(0.59)(0.41)/100 =[(0.59-0.5)/√(0.59)(0.41)/100] (a) (e) (e) None of these (b)-[(0.59-0.5)/√(0.5X0.5)/100 -[(0.59-0.5)/√(0.5X0.5)/100
A random sample of 100 voters in a community produced 59 voters in favor of Candidate A. The observed value of the test statistic for testing the null hypothesis alternative hypothesis H.:p>0.5 H₁: p=0.5 versus the is ==[(0.59-0.5)/√(0.59)(0.41)/100 =[(0.59-0.5)/√(0.59)(0.41)/100] (a) (e) (e) None of these (b)-[(0.59-0.5)/√(0.5X0.5)/100 -[(0.59-0.5)/√(0.5X0.5)/100
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
!['eriod:
1. A random sample of 100 voters in a community produced 59 voters in favor of Candidate A.
The observed value of the test statistic for testing the null hypothesis : p=0.5
versus the
H.:p>0.5 is
alternative hypothesis
(a)
Date:
z = [(0.59-0.5)/√(0.59)(0.41)/100
t=[(0.59-0.5)/√(0.59)(0.41)/100]
(b)
z=[(0.59-0.5)/√(0.5)(0.5)/100
=[(0.59-0.5)/√(0.5)(0.5)/100]
(c)
(e) None of these
2. In a test of H: p = 0.7 against H: p* 0.7, a sample of size 80 produces z = 0.8 for the value](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fccd31d51-5547-432f-9e2c-ede411255c83%2Fd3b2d1ea-b421-493f-b1b7-74d5246bd4b8%2Fynknh7l.jpeg&w=3840&q=75)
Transcribed Image Text:'eriod:
1. A random sample of 100 voters in a community produced 59 voters in favor of Candidate A.
The observed value of the test statistic for testing the null hypothesis : p=0.5
versus the
H.:p>0.5 is
alternative hypothesis
(a)
Date:
z = [(0.59-0.5)/√(0.59)(0.41)/100
t=[(0.59-0.5)/√(0.59)(0.41)/100]
(b)
z=[(0.59-0.5)/√(0.5)(0.5)/100
=[(0.59-0.5)/√(0.5)(0.5)/100]
(c)
(e) None of these
2. In a test of H: p = 0.7 against H: p* 0.7, a sample of size 80 produces z = 0.8 for the value
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