A random sample of 100 voters in a community produced 59 voters in favor of Candidate A. The observed value of the test statistic for testing the null hypothesis alternative hypothesis H.:p>0.5 H₁: p=0.5 versus the is ==[(0.59-0.5)/√(0.59)(0.41)/100 =[(0.59-0.5)/√(0.59)(0.41)/100] (a) (e) (e) None of these (b)-[(0.59-0.5)/√(0.5X0.5)/100 -[(0.59-0.5)/√(0.5X0.5)/100

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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'eriod:
1. A random sample of 100 voters in a community produced 59 voters in favor of Candidate A.
The observed value of the test statistic for testing the null hypothesis : p=0.5
versus the
H.:p>0.5 is
alternative hypothesis
(a)
Date:
z = [(0.59-0.5)/√(0.59)(0.41)/100
t=[(0.59-0.5)/√(0.59)(0.41)/100]
(b)
z=[(0.59-0.5)/√(0.5)(0.5)/100
=[(0.59-0.5)/√(0.5)(0.5)/100]
(c)
(e) None of these
2. In a test of H: p = 0.7 against H: p* 0.7, a sample of size 80 produces z = 0.8 for the value
Transcribed Image Text:'eriod: 1. A random sample of 100 voters in a community produced 59 voters in favor of Candidate A. The observed value of the test statistic for testing the null hypothesis : p=0.5 versus the H.:p>0.5 is alternative hypothesis (a) Date: z = [(0.59-0.5)/√(0.59)(0.41)/100 t=[(0.59-0.5)/√(0.59)(0.41)/100] (b) z=[(0.59-0.5)/√(0.5)(0.5)/100 =[(0.59-0.5)/√(0.5)(0.5)/100] (c) (e) None of these 2. In a test of H: p = 0.7 against H: p* 0.7, a sample of size 80 produces z = 0.8 for the value
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