A railroad cart with a mass of m₁ = 12.6 t is at rest at the top of an h = 10.3 m high hump yard hill. m m₂ h After it is pushed very slowly over the edge, it starts to roll down. At the bottom it hits another cart originally at rest with a mass of m₂ = 18.6 t. The bumper mechanism locks the two carts together. What is the final common speed of the two carts? (Neglect losses due to rolling friction of the carts. The letter t stands for metric ton in the SI system.)
A railroad cart with a mass of m₁ = 12.6 t is at rest at the top of an h = 10.3 m high hump yard hill. m m₂ h After it is pushed very slowly over the edge, it starts to roll down. At the bottom it hits another cart originally at rest with a mass of m₂ = 18.6 t. The bumper mechanism locks the two carts together. What is the final common speed of the two carts? (Neglect losses due to rolling friction of the carts. The letter t stands for metric ton in the SI system.)
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
Transcribed Image Text:**Problem Description:**
A railroad cart with a mass of \( m_1 = 12.6 \, \text{t} \) is at rest at the top of an \( h = 10.3 \, \text{m} \) high hump yard hill.
**Diagram Explanation:**
The diagram shows two railroad carts:
- **Cart 1 (\( m_1 \))**: Positioned at the top of the hill with height \( h \), indicating potential energy due to its elevated position.
- **Cart 2 (\( m_2 \))**: Positioned at the bottom of the hill, initially at rest.
A line descending from \( m_1 \) indicates the path it will travel down the hill. After cart 1 is pushed over the edge, it rolls down and collides with cart 2.
**Problem Details:**
- **Mass of Cart 2 (\( m_2 \))**: \( 18.6 \, \text{t} \)
- The collision locks the two carts together.
**Objective:**
Determine the final common speed of the two locked carts after the collision. Assume no rolling friction losses for the carts.
**Note**: The letter \( \text{t} \) stands for metric ton in the SI system.
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