Two objects (m, = 4.85 kg and m, = 3.35 kg) are connected by a light string passing over a light, frictionless pulley as in the figure below. The 4.85-kg object is released from rest at a point h = 4.00 m abovethe table.(a) Determine the speed of each object when the two pass each other.m/s(b) Determine the speed of each object at the moment the 4.85-kg object hits the table.m/s(c) How much higher does the 3.35-kg object travel after the 4.85-kg object hits the table?

Name: Two objects (m, = 4.85 kg and m, = 3.35 kg) are connected by a light
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: Two objects (m, = 4.85 kg and m, = 3.35 kg) are connected by a light string passing over a light, frictionless pulley as in the figure below. The 4.85-kg object is released from rest at a point h = 4.00 m abovethe table.(a) Determine the speed of ea

Answered: Image /qna-images/answer/5a7d6539-e333-408b-89c1-bae52ea4abe4.jpg

Science

Physics

Two objects (m, = 4.85 kg and m, = 3.35 kg) are connected by a light string passing over a light, frictionless pulley as in th the table. m2 (a) Determine the speed of each object when the two pass each other. m/s (b) Determine the speed of each object at the moment the 4.85-kg object hits the table. m/s (c) How much higher does the 3.35-kg object travel after the 4.85-kg object hits the table? m

Two objects (m, = 4.85 kg and m, = 3.35 kg) are connected by a light string passing over a light, frictionless pulley as in th the table. m2 (a) Determine the speed of each object when the two pass each other. m/s (b) Determine the speed of each object at the moment the 4.85-kg object hits the table. m/s (c) How much higher does the 3.35-kg object travel after the 4.85-kg object hits the table? m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A child of mass 30.0 kg begins from rest and slides down a waterslide without friction, then launches into a pool. What is her speed at pt. 2 assuming the height of this point is 0.9 above the ground? pt. 1 2.0 m pt. 2 pt. 5 h pt. 3 0.8 m pt. 4 0.4 m Apt. 6
A car of mass 1670kg initially at a speed of 80 km/m crushes into a wall, if the accident lasted for 0.2 sec. what is the amount of force exerted in the car during the crash
..
In the potential energy experiment. If the kinetic energy of the system composed of masses m, and m2 is 0.648 J. Given that the masses are moving at a speed of 1.23 m/s find the mass of the cart m, ( in units of kg) when m2= 110 g. т, m2 Select one: O A. 1.054 O B. 1.071 O C. 0.747 O D. 0.857 O E. 0.318
An Atwood’s machine is set up by suspending two blocks connected by a string of negligible mass over a pulley, as shown above. The blocks are initially held at rest and then released at time t0=0 s. The speed of the 3 kg block at time t1=2.0 s is most nearly: A) 2.0 m/s B) 4.0 m/s C) 7.0 m/s D) 10.0 m/s
6. Two blocks are connected by a light string passing over a light, frictionless pulley as shown in the figure. Block m1, initially at rest, is released from height h above the table. Block m,, which is the heavier block, begins to fall, while block m2 rises. a) Calculate the speed of m2 just as m¡ hits the table. b) Suppose block m, continues to rise without obstruction even after block m, hits the table. Calculate the maximum height above the table to which m2 rises. h
The racer of a 740 kg Formula One car travelling in track at a speed 40 m/s applies the car's brakes when he sees a red light. The frictional force of car's brakes is 20 000 N. Calculate the stopping distance of the car.
A student releases a 3.9kg cart from the top of ramp and starts a stopwatch. The length from the front of the cart to the end of the ramp and the distance from the end of the ramp to the stopper are shown. Neglect backwards friction and drag and assume the cart does not lose speed transitioning from the ramp to the floor. What is the cart's acceleration on the ramp? unit | (magnitude) What is the cart's acceleration on the floor? 130cm unit (magnitude) How long does the cart take to reach the end of the ramp? 5° 200cm unit (timed from the release) How fast is the cart traveling as it hits the stopper? unit How long does the cart take to reach the stopper? unit (timed from the release) cannot be detern check answers challenge ne Calculator ound = 343m/s cant figures Rain to stop e here to search ACC t;320
F, (N) 3 1 x (m) 6 8 10 12 14 16 2 4 Question 2 / 13 A force -shown in the figure- acts on a 5kg object moves in a straight line and starts its motion from the origin with speed of 5m/s. What is the speed (in m/s) of the object at x=10 m? 1. O 15.9 2. O11.7 3. 06.0 4. 07.4 5. 05.8
Substituting, for the coefficient of kinetic friction, we find Xn = 0.25 3 6 m m +); 2 10 (2 451 N/m) ( 0.36 9 ) (25/ 06-6) (CM (ત્ર m m X ney Pi1991 fan of ap by ne anen f S OX
vo t = 0 t = 3.5 s vo = (2.5i + 3.5j) m/s i = (-2.51) m/s The velocity of a 3.0-kg object is shown at two times. What was the magnitude of the average force exerted on the object between t= 0 and t = 3.5s? O 1.74 N O 6.26 N O 14.7 N O 3.23 N O 0.845 N
A 61.0-kg athlete leaps straight up into the air from a trampoline with an initial speed of 9.7 m/s. The goal of this problem is to find the maximum height she attains and her speed at half maximum height. (a) What are the.interacting.objects and how.do.they.interact? This answer has not been graded yet (b) Select the height at which the athlete's speed is 9.7 m/s as y = 0. What is her kinetic energy at this point? What is the gravitational potential energy associated with the athlete? (c) What is her kinetic energy at maximum height? What is the gravitational potential energy associated with the athlete? (d) Write a general equation for energy conservation in this case and solve for the maximum height. Substitute and obtain a numerical answer. m (e) Write the general equation for energy conservation and solve for the velocity at half the maximum height. Substitute and obtain a numerical answer. m/s