À pyrotechnician releases a 3-kg firecracker from re At t = 0.4 s, the firecracker is moving downward wi speed 4 m/s. At this same instant, the firecracker be to explode into two pieces with masses mop = 1 kg a mbottom = 2 kg. At the end of the explosion (t = 0.8 s) top piece is moving upward with speed 4 m/s. %3D %3D The mass of the explosive substance is negligible in comparison to the mass of the two pieces.

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Initial
t= 0.4 s
Final
t= 0.8 s
4. A pyrotechnician releases a 3-kg firecracker from rest.
At t = 0.4 s, the firecracker is moving downward with
speed 4 m/s. At this same instant, the firecracker begins
to explode into two pieces with masses mop = 1 kg and
mpottom = 2 kg. At the end of the explosion (t = 0.8 s), the
top piece is moving upward with speed 4 m/s.
lū= 4 m/s
m = 3 kg
mop = 1 kg
The mass of the explosive substance is negligible in
comparison to the mass of the two pieces.
löl=4 m/s
Motom = 2 kg
The questions below can serve as a guide to completing
the diagram below right:
bottom
= ?
a. Determine the magnitude of the net force on the
firecracker system before the explosion.
(Use g = 10 m/s².) Explain.
Change
Final
130.8 s
Initial
t= 0.4 s
b. Determine the magnitude of the net force on the
firecracker system at an instant during the explosion.
(Hint: Does the net force on a system depend on forces
that are internal to that system?)
Pop
c. Determine the magnitude and direction of the net
impulse (Fret At) on the firecracker system during the
explosion (i.e., over the interval from t = 0.4 s until
t = 0.8 s). Explain.
Pottom
d. Use the impulse-momentum theorem (Fet At = Ap) to
determine the magnitude and direction of the change in
momentum of the firecracker system during the
explosion. Enter this vector in the table using the scale
set by the initial momentum of the system.
e. Determine the final momentum of the firecracker
system and enter it in the table. (Hint: Is it the same as
the initial momentum?)
system
f. Complete the vector diagram at right.
12 kg-m/s
Transcribed Image Text:Initial t= 0.4 s Final t= 0.8 s 4. A pyrotechnician releases a 3-kg firecracker from rest. At t = 0.4 s, the firecracker is moving downward with speed 4 m/s. At this same instant, the firecracker begins to explode into two pieces with masses mop = 1 kg and mpottom = 2 kg. At the end of the explosion (t = 0.8 s), the top piece is moving upward with speed 4 m/s. lū= 4 m/s m = 3 kg mop = 1 kg The mass of the explosive substance is negligible in comparison to the mass of the two pieces. löl=4 m/s Motom = 2 kg The questions below can serve as a guide to completing the diagram below right: bottom = ? a. Determine the magnitude of the net force on the firecracker system before the explosion. (Use g = 10 m/s².) Explain. Change Final 130.8 s Initial t= 0.4 s b. Determine the magnitude of the net force on the firecracker system at an instant during the explosion. (Hint: Does the net force on a system depend on forces that are internal to that system?) Pop c. Determine the magnitude and direction of the net impulse (Fret At) on the firecracker system during the explosion (i.e., over the interval from t = 0.4 s until t = 0.8 s). Explain. Pottom d. Use the impulse-momentum theorem (Fet At = Ap) to determine the magnitude and direction of the change in momentum of the firecracker system during the explosion. Enter this vector in the table using the scale set by the initial momentum of the system. e. Determine the final momentum of the firecracker system and enter it in the table. (Hint: Is it the same as the initial momentum?) system f. Complete the vector diagram at right. 12 kg-m/s
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