**Problem Description:**Two magnetic toy train cars are pushed towards each other and stick together in an inelastic collision. The first train is 2 kg and moving at 4 m/s to the RIGHT, while the second train is 1 kg and moving at 2 m/s to the LEFT (towards each other). What is the final velocity of the combined train system?**Answer Options:**- 3.33 m/s to the LEFT- 2 m/s to the LEFT- 0- 2 m/s to the RIGHT- 3.33 m/s to the RIGHT**Explanation:**In an inelastic collision, the two objects stick together after colliding. To find the final velocity of the combined system, we use the principle of conservation of momentum. The initial momentum of the system is the sum of the momenta of the individual trains.The initial momentum of the first train (2 kg moving at 4 m/s to the right) is:\( p_1 = 2 \, \text{kg} \times 4 \, \text{m/s} = 8 \, \text{kg m/s (to the RIGHT)} \).The initial momentum of the second train (1 kg moving at 2 m/s to the left) is:\( p_2 = 1 \, \text{kg} \times (-2 \, \text{m/s}) = -2 \, \text{kg m/s (to the LEFT)} \).The total initial momentum of the system is:\( p_{\text{total}} = 8 \, \text{kg m/s} + (-2 \, \text{kg m/s}) = 6 \, \text{kg m/s (to the RIGHT)} \).Since the collision is inelastic and they stick together, the final momentum \( p_{\text{final}} \) must also be 6 kg m/s to the RIGHT.The total mass of the combined system after collision is \( 2 \, \text{kg} + 1 \, \text{kg} = 3 \, \text{kg} \).Let \( v_f \) be the final velocity. Then:\( p_{\text{final}} = m_{\text{total}} \cdot v_f = 3 \, \text{kg} \cdot v_f = 6 \

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Description: **Problem Description:**Two magnetic toy train cars are pushed towards each other and stick together in an inelastic collision. The first train is 2 kg and moving at 4 m/s to the RIGHT, while the second train is 1 kg and moving at 2 m/s to the LEFT

Given data: The mass of the first train is m1=2 kg. The velocity of the first train towards right…

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Two magnetic toy train cars are pushed towards each other and stick together in an inelastic collision. The first train is 2-kg and moving at 4 m/s to the RIGHT, the second train is 1-kg and moving at 2 m/s to the LEFT (towards each other). What is the final velocity of the combined train system?

Two magnetic toy train cars are pushed towards each other and stick together in an inelastic collision. The first train is 2-kg and moving at 4 m/s to the RIGHT, the second train is 1-kg and moving at 2 m/s to the LEFT (towards each other). What is the final velocity of the combined train system?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Problem Description:**

Two magnetic toy train cars are pushed towards each other and stick together in an inelastic collision. The first train is 2 kg and moving at 4 m/s to the RIGHT, while the second train is 1 kg and moving at 2 m/s to the LEFT (towards each other). What is the final velocity of the combined train system?

**Answer Options:**

- 3.33 m/s to the LEFT
- 2 m/s to the LEFT
- 0
- 2 m/s to the RIGHT
- 3.33 m/s to the RIGHT

**Explanation:**

In an inelastic collision, the two objects stick together after colliding. To find the final velocity of the combined system, we use the principle of conservation of momentum. The initial momentum of the system is the sum of the momenta of the individual trains.

The initial momentum of the first train (2 kg moving at 4 m/s to the right) is:
\( p_1 = 2 \, \text{kg} \times 4 \, \text{m/s} = 8 \, \text{kg m/s (to the RIGHT)} \).

The initial momentum of the second train (1 kg moving at 2 m/s to the left) is:
\( p_2 = 1 \, \text{kg} \times (-2 \, \text{m/s}) = -2 \, \text{kg m/s (to the LEFT)} \).

The total initial momentum of the system is:
\( p_{\text{total}} = 8 \, \text{kg m/s} + (-2 \, \text{kg m/s}) = 6 \, \text{kg m/s (to the RIGHT)} \).

Since the collision is inelastic and they stick together, the final momentum \( p_{\text{final}} \) must also be 6 kg m/s to the RIGHT.

The total mass of the combined system after collision is \( 2 \, \text{kg} + 1 \, \text{kg} = 3 \, \text{kg} \).

Let \( v_f \) be the final velocity. Then:
\( p_{\text{final}} = m_{\text{total}} \cdot v_f = 3 \, \text{kg} \cdot v_f = 6 \

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