3. A 0.10 kg ball is launched with an initial velocity Vi,ball into a stationary cup with mass 0.15 kg. After the perfectly inelastic collision, the two objects travel with a velocity of 0.605 m/s. Determine the initial velocity of the ball. (Hint: use the Conservation of Momentum Equation). mball Vi ball 10 kg ball Pivot point ? V L m Vi,ball+cup=0.605. S

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**Problem Statement:**

A 0.10 kg ball is launched with an initial velocity \( v_{i, \text{ball}} \) into a stationary cup with a mass of 0.15 kg. After the perfectly inelastic collision, the two objects travel together with a velocity of 0.605 m/s. Determine the initial velocity of the ball. (Hint: use the Conservation of Momentum Equation).

**Diagram Explanation:**

- **Ball:** The mass of the ball (\( m_{\text{ball}} \)) is given as 0.10 kg.
- **Cup:** Depicted as a stationary object with mass 0.15 kg.
- **Combined System Velocity:** After the collision, both objects move together at a velocity of 0.605 m/s.
  
There is a graphical representation showing a cup and ball system suspended with a pivot point. The ball, initially moving horizontally, is represented with an arrow indicating its unknown initial velocity \( v_{i, \text{ball}} \). The resultant velocity of the ball and cup system is labeled as \( v_{i, \text{ball} + \text{cup}} = 0.605 \, \text{m/s} \). The masses are clearly labeled in the diagram, but there is a typographical error indicating \( m_{\text{ball}} = 10 \, \text{kg} \) instead of 0.10 kg.

Use the conservation of momentum to find the initial velocity of the ball:

\[
m_{\text{ball}} \times v_{i, \text{ball}} = (m_{\text{ball}} + m_{\text{cup}}) \times v_{i, \text{ball+cup}}
\]
Transcribed Image Text:**Problem Statement:** A 0.10 kg ball is launched with an initial velocity \( v_{i, \text{ball}} \) into a stationary cup with a mass of 0.15 kg. After the perfectly inelastic collision, the two objects travel together with a velocity of 0.605 m/s. Determine the initial velocity of the ball. (Hint: use the Conservation of Momentum Equation). **Diagram Explanation:** - **Ball:** The mass of the ball (\( m_{\text{ball}} \)) is given as 0.10 kg. - **Cup:** Depicted as a stationary object with mass 0.15 kg. - **Combined System Velocity:** After the collision, both objects move together at a velocity of 0.605 m/s. There is a graphical representation showing a cup and ball system suspended with a pivot point. The ball, initially moving horizontally, is represented with an arrow indicating its unknown initial velocity \( v_{i, \text{ball}} \). The resultant velocity of the ball and cup system is labeled as \( v_{i, \text{ball} + \text{cup}} = 0.605 \, \text{m/s} \). The masses are clearly labeled in the diagram, but there is a typographical error indicating \( m_{\text{ball}} = 10 \, \text{kg} \) instead of 0.10 kg. Use the conservation of momentum to find the initial velocity of the ball: \[ m_{\text{ball}} \times v_{i, \text{ball}} = (m_{\text{ball}} + m_{\text{cup}}) \times v_{i, \text{ball+cup}} \]
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