A pulley is keyed to a shaft midway between two anti-friction bearings. The bending moment at the pulley varies from - 170 N-m to 510 N-m and the torsional moment in the shaft varies from 55 N-m to 165 N-m. The frequency of the variation of the loads is the same as the shaft speed. The shaft is made of cold drawn steel having an ultimate strength of 540 MPa and a yield strength of 400 MPa. Determine the required diameter for an indefinite life. The stress concentration factor for the keyway in bending and torsion may be taken as 1.6 and 1.3 respectively. The factor of safety is 1.5. Take size factor = 0.85 and surface finish factor = 0.88. %3D %3D [Ans. 36.5 mm] [Hint. Assume oe = 0.5 ou; ty = 0.5 oy ; te = 0.55 oe e 2:47

A pulley is keyed to a shaft midway between two anti-friction bearings. The bending moment at the pulley varies from - 170 N-m to 510 N-m and the torsional moment in the shaft varies from 55 N-m to 165 N-m. The frequency of the variation of the loads is the same as the shaft speed. The shaft is made of cold drawn steel having an ultimate strength of 540 MPa and a yield strength of 400 MPa. Determine the required diameter for an indefinite life. The stress concentration factor for the keyway in bending and torsion may be taken as 1.6 and 1.3 respectively. The factor of safety is 1.5. Take size factor = 0.85 and surface finish factor = 0.88. %3D %3D [Ans. 36.5 mm] [Hint. Assume oe = 0.5 ou; ty = 0.5 oy ; te = 0.55 oe e 2:47

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: a) Calculate the internal forces/moments at point J? b) Bar DE is made of aluminum with Young…

Q: A prismatic shaft consists of a solid brass rod of diameter 32 mm, which is inside a steel tube of…

Q: P1.020 For the clevis connection shown in the figure, determine the maximum applied load P that can…

A: d = 15 mm = 75 MPa

Q: The uniform rod is subjected to the axial loads as shown. Which segment has the absolute maximum…

A: Given Loads To find out Which segment has Maximum normal stress

Q: Part A A solid steel shaft is 14 ft. long, has a diameter of 6 inches over 9 ft. of its length and a…

A: Given :

Q: The compound shaft consists of a solid aluminum segment (1) and a hollow brass segment (2) that are…

A: J1 = π32×0.554 J2 = π32×0.354-0.234

Q: s to be made of steel having an ultimate shearing stress of 400 MPa, determine: (a.)The diameter of…

Q: Ends A and D of the two solid steel shafts AB and CD are fixed, while ends B and C are connected to…

A: Hi! Thank you for the question As per the honor code, We’ll answer the questiononly in typed…

Q: Q1// The compound wooden beam is connected together by a bolt at B. Assuming that the connections at…

Concept explainers

Alloys

An alloy is an admixture of two or more metals or a metal and a non-metal. Since ancient times, man has been using alloys. Alloying helps to retain the properties of the parent matter, such as hardness, strength, toughness, ductility and is corrosion-resistant. Copper alloys such as brass have antimicrobial properties that help to fight against (Coronavirus disease 2019) COVID-19 and other hospital-acquired infections. Some common alloys are brass, bronze, solder steel, etc. Most alloys have a lower melting point than their constituents. This is due to the presence of a nonmetal as one of the constituents that behaves as an impurity and restricts the raise of melting point.

Question

A pulley is keyed to a shaft midway between
two anti-friction bearings. The bending
moment at the
pulley varies from - 170 N-m to 510 N-m and
the torsional moment in the shaft varies from
55 N-m
to 165 N-m. The frequency of the variation of
the loads is the same as the shaft speed. The
shaft is
made of cold drawn steel having an ultimate
strength of 540 MPa and a yield strength of
400 MPa.
Determine the required diameter for an
indefinite life. The stress concentration factor
for the keyway
in bending and torsion may be taken as 1.6
and 1.3 respectively. The factor of safety is
1.5. Take size
factor = 0.85 and surface finish factor = 0.88.
%3D
%3D
[Ans. 36.5 mm]
[Hint. Assume oe
= 0.5 ou; ty
= 0.5 oy
; te
= 0.55 oe
e 2:47 V

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 Given Data

VIEW

Step 2 Page 1 of Solution

VIEW

Step 3 Page 2 of Solution

VIEW

Step 4 Page 3 of Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A prismatic shaft consists of a solid brass rod of diameter 32 mm, which is inside a steel tube of diameter 50 mm. 2GB) Both shafts are firmly (Gs jointed. The combined assembly is subjected to a torque of 1000 Nm. calculate maximum shear stress = developed in steel in N/mm2 (up to 2 decimals)
Q2: The pin-coected structure shown in figure below consists of a rigid member BED and three steel rods (E- 200 GPa). Each of the rods AB and CD has a 200 mm cross-sectional area and rod EF has a 625 mm2 cross-sectional area. If a load of P- 36 KN is applied at E, determine: (a) the change in length of rod EF. (b) the stress in each rod. 300 mm P-36 kN 300 mm 400 mm * 500 mm
The shaft is made of A992 steel. It has a diameter of 0.7 in. and is supported by bearings at A and D, which allow free rotation. The shear modulus of elasticity for the material is 11 × 10³ ksi. 2 ft < 5 of 7 Part A B 2.5 ft > 60 lb-ft C 3 ft O 60 lb-ft
etermine the elongation of a 0.5-in, dianeter sterl bar The elastic modulus of the steel bar is 27000 kar. 2000 Ib 10 ft
The compound shaft consists of a solid aluminum segment (1) and a hollow brass segment (2) that are connected at flange B and securely attached to rigid supports at A and C. Aluminum segment (1) has a diameter of 0.55 in., a length of L₁ = 40 in., a shear modulus of 3800 ksi, and an allowable shear stress of 5.8 ksi. Brass segment (2) has an outside diameter of 0.45 in., a wall thickness of 0.15 in., a length of L₂ = 30 in., a shear modulus of 6400 ksi, and an allowable shear stress of 8.2 ksi. Determine: (a) the allowable torque Te that can be applied to the compound shaft at flange B. (b) the magnitudes of the internal torques in segments (1) and (2). (c) the rotation angle of flange B (relative to support A) that is produced by the allowable torque TB. L₁ L2 TB (1) Answer: (a) TB= (b) T₁ = T2= (c) OB= B lb-ft lb-ft lb-ft rad (2) C
Determine the number of main bars, spacing, and determine the spacing for stirrups.
Read the question carefully and give me right solution with clear calculations
A rigid bar ABCD is supported by two bars as shown in the figure. There is no strain in the vertical bars before load P is applied. After load P is applied, the normal strain in rod (1) is -1350 µm/m. Determine the normal strain in rod (2) if there is a 1-mm gap in the connection at pin C before the load is applied. A 240 mm B (1) O 1281 um/m O 1877 µm/m O 1141 µm/m O 1358 µm/m O 999 µm/m 360 mm (2) Rigid bar 900 mm C 140 mm, 1,500 mm
A stress developed if the applied force is parallel to the resisting area refers to: O tangential O bearing O normal. O simple
The steel shaft has a diameter of 3.5 in .It is supported on smooth journal bearings A and B which exert only vertical reactions on the shaft. Determine the absolute maximum bending stress in the shaft if it is subjected to the pulley loading shown.
When the temperature is at 30°C, the steel pipe fits snugly between the two fuel tanks. When fuel flows through the pipe, it causes the temperature to vary along the pipe as T = (3x² 20x + 120)°C. Calculate the normal stress developed in the pipe. Assume each tank provides a rigid support at A and B. a=12X10-6/°C - 150 mm 10 mm- Section a - a -6 m a a B