A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtain the results below. From past studies, the publisher assu;mes standard deviation is 1.9 minutes and that the population of times is normally distributed. 10 6 7 7 12 9 12 11 11 11 11 8 9 9 8 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is _________ , ____________. (Round to one decimal place as needed) The 99% confidence interval is __________, ____________ (round to one decimal place as needed) Which interval is wider? The 99% confidence interval or The 90% confidence interval
Section 6.1 (please help with TI-84 calculator commands)
A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtain the results below. From past studies, the publisher assu;mes standard deviation is 1.9 minutes and that the population of times is
10 6 7 7 12 9 12 11 11 11 11 8 9 9 8
Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.
The 90% confidence interval is _________ , ____________. (Round to one decimal place as needed)
The 99% confidence interval is __________, ____________ (round to one decimal place as needed)
Which interval is wider?
The 99% confidence interval
or
The 90% confidence interval
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