A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of3.22 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 2980 m/s. At that instant, what isthe magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 4.83 V/m,(b) in the negative z direction and has a magnitude of 4.83 V/m, and (c) in the positivex direction and has a magnitude of 4.83 V/m?(a) NumberiUnits(b) NumberiUnits(c) NumberiUnits

the force acting on a charged particle due to the magnetic field is given by FB=q(v×B) where q is…

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