This time the charge is 1.30 x 10^-6 C, the magnetic field strength is 2.80 T and the electric field strength is 8.33 x 10^5 N/C. The charge experiences a total force of magnitude 18.20 N as it enters the region. What is its speed as it enters the region?

Q: A proton moves through a magnetic field at 25.7% of the speed of light. At one location, the field…

A: FB=3.918x10-14NExplanation:Step 1: Step 2: Step 3: Step 4:

Q: A charge Q = 6.2 x 10^-6 C, moves with a speed V = 4x10^6 i - 3x10^6 k and enters a Magnetic Field B…

A:

Q: negative charge q = −3.60 × 10^−6 C is located at the origin and has a velocity ⃗v = (7.50 × 10^4…

A:

Q: X X X Fm X X X X X X X X X X X X X X X X X X X X X B X Fe X X X X X

A:

Q: A charged particle (q = 1.6 x 10-1⁹ C) enters a mass spectrometer with a speed of 2.5 x 10 m/s. The…

A: Charge on particle is q=1.6×10-19 C Speed is v=2.5×106 m/s Magnetic field is B=0.25 T Particle moves…

Q: A beam of particles with charge –4e sent into a mass spectrometer travels undeflected through a…

A: a) Since the particle passes undeflected, the electric and magnetic fields are equal. We have…

Q: Once more, please refer to the figure. This time the charge is 3.77 x 10^-6 C, the magnetic field…

A: The total force on the charge is the sum of electric and magnetic field.  electric filed force is…

Q: A single ionized atom, that is deficient one electron, is traveling at in a straight line when it…

A: GivenB=0.75 Tm=6.58×10-27 kgqe=1.602×10-19 C

Q: The magnetic field in a region is given by B = (0.7501 + 0.230ĵ) T. At some instant, a particle with…

A:

Q: In the figure, an electron moves at speed v-51.2 m/s along an x axis through uniform electric and…

A: From the condition,  v = E / B we have, E→ = vB→ E→ = 51.2 x 4.51 E→ = 230.912 V/m

Q: See the attached figure for this problem. A charge of 9.93 x 10^6 C moves to the right as shown…

A: Since the charge is moving at a constant velocity, the net force on the charge will be zero.Write…

Q: 3.5 x 10° m/s enters a uniform magnetic field of B = 1.5 T. The velocity of the particle makes an…

A: The magnetic field B =1.5T  To find the pitch of the helical path

Q: A 1.724 x 10-6 kg particle with a charge of 5.61 x 10-6 C moves at 22.2 m/s through a 1.31-T…

A:

Q: Problem 4: A proton moves in a circular path of the same radius as a cosmic ray electron moving at…

A: Given a proton moving in a circular path of the same radius as the cosmic ray electron let  the mass…

Q: See the attached figure for this problem. A charge of 1.69 x 10^6 C moves to the right as shown…

A: When the charged particle enters the magnetic field, the electric force will be equal to the…

Q: A proton moves through a region containing a uniform electric field given by E = 44.0 j V/m and a…

A: Given information: Here, m and q are the proton’s mass and proton’s charge respectively.

Q: A proton moves through a uniform magnetic field. The magnetic field is given by B = (0.00 - 13.9…

A:

Q: A 5.47 C point charge is moving with a speed of 6.98 m/s. It is moving perpendicular to a magnetic…

A: Charge (q) = 5.47 C  Speed (v) = 6.98 m/s  Magnetic field (B) = 6.28 T

Q: A long electricity distribution line is running current due east from the power plant to one of its…

A: Ampere's force law, The force experienced by current-carrying conductor placed in a magnetic field…

Q: One long wire carries a current of 30 A along the entire x axis. A second long wire carries a…

A: Current along x-axis Ix = 30A Current along axis parallel to z-axis(perpendicular to xy plane) Iz =…

Q: A charged particle with a velocity of 5 m/s enters a magnetic field of 0.2 Tesla at an angle of 30…

A: Charge (q) = Velocity (v) = 5 m/sMagnetic field (B) = 0.2 TAngle ()= 30 degrees

Q: A proton moves through a region containing a uniform electric field given by E = 48.0 j V/m and a…

A:

Q: A+3 millicoulomb charge has a velocity to the right 3.33 kilometers per second as shown. The charge…

A: Solution:-Given thatcharge (q)=+3 mC=+3×10-3 CVelocity (V)=3.33 km/sElectric field (E)=3000…

Q: A coil of wire with an average length of 20 cm moves through a magnetic field.  The flux is cut with…

A:

Q: See the attached figure for this problem. There is a charge of 6.24 x 10^-6 C moving at velocity…

A: Calculate the magnetic field due to the charge. Fm=qvBFm=(6.24×10−6 C)(8.62×105 m/s)(3 T)Fm=16.1 N

Q: A proton moves at a constant velocity of +63.4m/s along an x axis, through crossed electric and…

A:

Q: A negatively charged ion with an excess electron moving with a velocity vx = 1.095 x103 m/s is…

A:

Q: 2. A charged particle enters the magnetic field of magnitude 0.35 T of a mass spectrometer at a…

A:

Q: A hydrogen ion moves at 6.35 ✕ 10^4 m/s perpendicular to the Earth's magnetic field at an altitude…

A:

Q: A magnetic field has a magnitude of 0.0011 T, and an electric field has a magnitude of 6.4 × 103…

A:

Q: A particle with mass 1.81 × 10-³ kg and a charge of 1.22 × 10-8 C has, at a given instant, a…

A: Given: The mass: m = 1.81×10-3 kg The charge: q = 1.22×10-8 C The velocity: v→ = (4.19×104)i^ +…

Q: See the attached figure for this problem.  There is a charge is 9.61 x 10^-6 C, the magnetic field…

A:

Q: A magnetic field has a magnitude of 0.00090 T, and an electric field has a magnitude of 4.1 × 103…

A:

Q: A proton moves through a region containing a uniform electric field given by E= 38.0 ĵ V/m and a…

A:

Q: A proton is moving in positive x-direction with the speed of 3.2x10^5 m/s. It enters in a uniform…

A: Given, Speed , v = 3.2×105 m/s uniform magnetic field , B = 8.0 mT =8×10-3T into the page. charge ,…

Q: A particle (mass = 0.002 g, charge = - 6 μC) moves in the negative direction along the x axis with a…

A:

Q: 5.03 × 10-6 C and mass m = 8.17 × 10¬10 kg and velocity |A particle has charge q = – components vỵ =…

A:

Q: An electric field of 1.50 kV/m and a magnetic field of 0.400 T act on a moving electron without…

A: The net force is zero. It implies that the electric force is equal to the magnetic force

Q: A magnetic field has a magnitude of 0.00090 T, and an electric field has a magnitude of 4.1 x 103…

A:

Q: = A proton moves through a region containing a uniform electric field given by E 48.0 ĵ V/m and a…

A:

Q: 1. A 25 cm rod moves at 5.6 m/s in a plane perpendicular to a magnetic field of strength 0.34 T. The…

A:

Q: n a photographic emulsion, the path of a proton moving perpendicular to a uniform 1.32-T magnetic…

A: r = mv/qB     = p/qB     = 2mk.E/qB r = 2mk.E/qB 3.0*10-2 = 2*1.61*10-27*kE/1.6*10-19*1.32

Q: Crossed electric and magnetic fields are established over a certain region. The magnetic field is…

A: Given value--- magnetic field = 0.59 T. electric field = 3.48 × 10⁶ V/m. We have to find--- What…

Q: Once more, please refer to the figure. This time the charge is 9.73 x 10^-6 C, the magnetic field…

A:

Q: proton travels with a speed of 3.91x106 m/s in a direction that makes an angle of 33 degrees with…

A: mass of proton m = 1.67 × 10-27 kg

Q: An electron is moving with an initial velocity of 7.09 x 10° m/s through a magnetic field. If the…

A:

Q: A long straight wire has a current of 0.581A travelling through it. The wire is placed so that the…

A: For the long straight the magnetic field is written as; B =μoI2πr ----(1) Here we have I is the…

Q: See the attached figure for this problem. A charge of 8.70 x 10^6 C moves to the right as shown…

A:

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.