A proton traveling at 25.6° with respect to the direction of a magnetic field of strength 3.35 mT experiences a magnetic force of 8.02 x 1017 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts. (a) Number 346289.75 Units m/s (b) Number 625.8 Units ev
Q: A magnetic field is used to bend a beam of electrons. What uniform magnetic field is required to…
A:
Q: An ion with a charge of 1.6 x 10^-19 C moves at speed 1.0 x 10^6 m/s into and perpendicular to the…
A:
Q: J. find An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T.…
A:
Q: A proton traveling at 28.7° with respect to the direction of a magnetic field of strength 3.23 mT…
A: The answers are below
Q: A proton traveling at 34.2° with respect to the direction of a magnetic field of strength 3.38 mT…
A: Given value--- angle = 34.2 degree. magnetic field = 3.38 mR. magnetic force = 6.40 × 10-17 N. We…
Q: A proton traveling at 21.8° with respect to the direction of a magnetic field of strength 3.43 mT…
A:
Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.29 T. If the…
A: Given: The magnitude of the magnetic field, B = 0.29 T The kinetic energy of the electron, K.E. =…
Q: A particle with a positive charge of 35.8 x 10-6 C is traveling at a constant rate of 85,198 m/s. It…
A: The force exerted on a charge q moving with a velocity v in a magnetic field B is given…
Q: A proton moves through an electric field of magnitude 3.80 103 V/m and a magnetic field of magnitude…
A: Given that : Electric Field ( E ) = 3.80 * 103 V/m Magnetic Field ( B ) = 9.72 * 10-3 T Velocity of…
Q: An electron moves with a speed of 5.0 × 104 m/s perpendicular to a uniform magnetic field of…
A: Given: Speed of the electron =5.0×104 m/s Magnitude of the uniform magnetic field =0.20 T Charge of…
Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.38 T. If the…
A: (a) speed of the electron
Q: A proton moves with an unknown velocity through a magnetic field of 3.45 x 10-3 T that points…
A: Given: The magnetic field is 3.45x10-3 T due north. The magnetic force on the proton is 2.4x10-15 N…
Q: A magnet produces a 0.50-T uniform field between its poles, directed to the east. A dust particle…
A: Magnetic field (B→) = 0.5 T i^Charge on dust particle (q) = -4×10-18 C Velocity of dust particle…
Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.265 T. If the…
A: Given: B= 0.265 T E= 3.80×10-19 J R=? m= 9.1×10-31 kg a) E= 12mv2 Rearrange it for V V=…
Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.29 T. If the…
A: a. the kinetic energy of the electron is
Q: A proton traveling at 24.0° with respect to the direction of a magnetic field of strength 2.72 mT…
A: Angle made by the proton with respect to the direction of magnetic field (θ) = 24omagnetic field…
Q: A 5.47 C point charge is moving with a speed of 6.98 m/s. It is moving perpendicular to a magnetic…
A: Charge (q) = 5.47 C Speed (v) = 6.98 m/s Magnetic field (B) = 6.28 T
Q: In the figure provided, an electron with speed v = 3.98×107 m/s travels between two parallel charged…
A:
Q: A proton traveling at 21.1° with respect to the direction of a magnetic field of strength 3.78 mT…
A: Write the given values with the suitable variables. θ=21.1°B=3.78 mT=3.78×10-3 TF=6.87×10-17 N Here,…
Q: A proton traveling at 31.5° with respect to the direction of a magnetic field of strength 3.43 mT…
A: Given,B=3.43 mTF=9.69×10-17Nθ=31.5°
Q: A proton traveling at 28.7° with respect to the direction of a magnetic field of strength 3.23 mT…
A:
Q: See the attached figure for this problem. There is a charge of 6.24 x 10^-6 C moving at velocity…
A: Calculate the magnetic field due to the charge. Fm=qvBFm=(6.24×10−6 C)(8.62×105 m/s)(3 T)Fm=16.1 N
Q: The diagram shows a beam of ions of charge, 61 x 10-19 c that are traveling at an unknown speed. The…
A: Given, Mass=5.5×10^5kg Charge=1.61×10^-19c Magnetic field=2.20T Radius=9cm
Q: A proton traveling at 28.3° with respect to the direction of a magnetic field of strength 2.48 mT…
A: We use F = qvBsinθ to get, v=FqBsinθ and, E = 12mv2
Q: An electron traveling with a velocity of 6.0 x 105 m/s along the y direction enters a uniform…
A: Given Velocity of electron = v = 6.0 × 105 m/s in y Strength of magnetic field = B = 0.60 T in x We…
Q: A negatively charged ion with an excess electron moving with a velocity vx = 1.095 x103 m/s is…
A:
Q: An electron experiences a magnetic force of magnitude 4.6 x 10 15. N when moving at an angle of 60°…
A: When a charge passes through a magnetic field a magnetic force is realised by the charge due to its…
Q: A proton traveling at 27.7° with respect to the direction of a magnetic field of strength 3.00 mT…
A: This is a problem of Moving charged particle inside magnetic field. Please have a good look
Q: An electron with a speed of 1.2 x 102 m/s enters a magnetic field of 0.0020 T at 90 degrees to the…
A: The objective of the question is to determine the instantaneous acceleration of an electron as it…
Q: What is the radius of the path of an electron that travels through a 0.257 T uniform magnetic field…
A: The radius r of an electron in a magnetic field B moving with velocity v is given by r= mv/eB…
Q: What is the magnitude and direction of the magnetic force acting on a 7.5 x 10^-15 C charged proton…
A: Given:q=7.5*10-15 Cv=5.9*104 m/s (downwards)B=4.8 T (left) we have to find magnitude and direction…
Q: A proton traveling at 20.8° with respect to the direction of a magnetic field of strength 3.12 mT…
A:
Q: What is the kinetic energy of a 0.050 kg particle with a charge of 3.0 C moving with a radius of…
A: It is given that,
Q: A proton traveling at 21.1° with respect to the direction of a magnetic field of strength 3.78 mT…
A:
Q: A proton traveling at 26.6° with respect to the direction of a magnetic field of strength 3.62 mT…
A:
Q: been struggling with this question: please show steps A beam of charged particles moves undeflected…
A: Given Data:The magnitude of the magnetic field is The distance between the plates is The potential…
Q: An electron (me by a potential difference of V. Then it passes through a region of transverse…
A:
Q: roton traveling at 31.6° with respect to the direction of a magnetic field of strength 3.49 mT…
A:
Q: A proton traveling at 33.3° with respect to the direction of a magnetic field of strength 3.14 mT…
A: θ = 33.3oB = 3.14 mT F = 6.73×10-17 N
Q: A proton traveling at 19.2° with respect to the direction of a magnetic field of strength 3.00 mT…
A: Given data: Angle between velocity and magnetic field (θ) = 19.2° Magnetic field (B) = 3.00 mT =…
Q: A proton traveling at 27.4° with respect to the direction of a magnetic field of strength 3.78 mT…
A:
Q: A proton traveling at 25.5° with respect to the direction of a magnetic field of strength 3.48 mT…
A:
Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.295 T. If the…
A: The magnetic field is The electron moves in a circular path perpendicular to the magnetic field.The…
Step by step
Solved in 2 steps with 2 images