A proton is released from rest in a uniform electric field of magnitude 50000 V/m di- rected along the positive x axis and under- goes a displacement of 0.3 m in the direction of the electric field as shown. 50000 V/m 0.3 m B Find the amount of the kinetic energy gained after it has moved 0.3 m. Answer in units of J. ++++++++++++-
Q: = Find the potential difference V(11.0 m) - V(-1.0 m) given the electric field E(x) = 24.0x^2 +0.0x…
A:
Q: Two 2.2-cm-diameter-disks spaced 1.7 mm apart form a parallel-plate capacitor. The electric field…
A:
Q: e•25 In Fig. 25-40, two parallel-plate ca- pacitors (with air between the plates) are connected to a…
A:
Q: A uniform electric field E = 3250 V/m exists within a certain region. What volume of space contains…
A: Given data: The electric field is, E=3250 V/m. The energy is, U=1.15×10-7 J. Write the expression…
Q: A uniform electric field E = 2650 V/m exists within a certain region. What volume of space contains…
A: Energy density is the total energy per unit volume. That is uE=UEV,where UEis the potential energy…
Q: A parallel plate has a capacitance of 18µF and a plate separation of 0.025mm. The charge on the…
A:
Q: The charge of a parallel plate capacitor is 450 x 10 ^ -6 C. If connected to a source of V = 110 V,…
A:
Q: In (Figure 1), the charge q = 3.09 x 10-9 C. Part A Find the electric potential at x = 0.450 m.…
A:
Q: Two 2.0-cm-diameter disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field…
A: Givendiameter, d=2 cmradius, r=1 cmseparation , t=1.5 mmE=5×105 V/mcapacitance, C=Aεotwhere A is…
Q: An electric field does 1.05 ✕ 103 eV of work on a carbon nucleus of charge 9.61 ✕ 10−19 C. Find the…
A:
Q: Two parallel rectangular plates of with dimensions 8cm by 10 cm are given charges of equal…
A:
Q: A spherical capacitor of inner radius 1.00 mm and outer radius 2.00 mm has the electric energy…
A: Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: 1. The diagram shows two parallel, horizontal plates separated by a vertical distance of 3.0 cm. The…
A:
Q: Two 1.60-cm-diameter disks spaced 1.80 mm apart form a parallel-plate capacitor. The electric field…
A: A) The separation between the plate disks spaced 1.80 mm = 1.80-3m Electric field between these…
Q: In (Figure 1), each capacitor has C = 4.80 µF and Vab = 30.0 V Part A Calculate the charge on…
A:
Q: A charge of 40 pC is distributed on an isolated spherical conductor that has a 4.0-cm radius. Point…
A: Given: The charge that is distributed on the isolated spherical conductor: q = 40 pC; The radius of…
Q: An electron is to be accelerated in a uniform electric field having a strength of 1.12x What energy…
A: Given data: An electron is accelerated in uniform electric field Electric field (E) = 1.12×106 V/m…
Q: A 2.0-cm-diameter circular parallel plate capacitor with a spacing of 0.5 mm is charged to 200 V.…
A:
Q: A uniform electric field is created by two parallel plates separated by a distance of 0.04 m. What…
A:
Q: 1. Suppose an electron is released from rest in a uniform electric field whose magnitude is 5900…
A: Given,Electron is released from rest in a uniform electroc field E = 5900 V/M.
Q: Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential…
A: 1) Distance between the plates d=2cm=0.02m V=195V Electric field between plates is E=V…
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
- The separation distance between the two plates of a parallel plate capacitor is 2.06 cm. An electron is at rest near the negative plate. When it is released, it accelerates and reaches the positive plate with a kinetic energy of 6.00 × 10¬15 J. What is the magnitude of the electric field in the region between the plates of the capacitor? V/mAn ion accelerated through 180.00 V has its potential energy decreased by potential energy of 5.76 10-17 J. Calculate the (magnitude of the) charge on the ion. CAn electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 2.0 cm, and the electric field within the capacitor has a magnitude of 2.4 x 106 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? KE positive = i -Electric field Electron F
- What is the electric field inside a 3.5 microF parallel plate capacitor when it is connected to a 12.0 V battery? The two plates are both 11.0 cm in diameter and 2.0 mm apart. SI base units.A proton is released from rest at the surface of a 1.0 cm diameter sphere that has been charged to +1000 V. What is the proton's speed at 1.0 cm from the sphere?Physics Review Question #5
- An electric field E=10 V/m permeates a region in outer space. What is the electric energy stored in a cube of space with side length L=1 km? a. 445 nJ O b. 443 mJ c. 0.443 mJ O d. 100 Je 2. What is the magnitude of the electric field at the point (7.40 -9.00 +8.20 k) m if the electric potential is given by V = 9.90xyz2, where V is in volts and x, y, and z are in meters? Number UnitsA charged particle that has a mass of 2.8 x 10 16 kg accelerates upward at 3.6 m/s? in the electric field between the two horizontal plates below. The plates are separated by 0.10 m and the potential difference is 2. 4.00 x 10 V across the plates. Assume the top plate is positive and the bottom plate is negative. The diagram is not to scale. OV Charged Particle 0.10 m 4.00 x 102 V a) Calculate the electric force exerted on the charged particle as it travels through the parallel plates. b) Determine the magnitude of the charge on the particle. c) Assume that the voltage applied to the parallel plates can be varied. Calculate the minimum voltage needed to move the charged particle to the upper plate.
- Two protons approach one another from very far away with an initial speed of 1100 m/s. a) Draw a sketch of the scenario, then b) Determine how close do they come to one another before turning around? Hint, the protons will continue to move toward each other until the KE of the protons is equal to the PE(electric).An electron is fired in the positive y-direction from x= -3.00 cm in a constant electric field with magnitude 1.88 x 103N/C pointing in the positive y-direction. The moment the electron is at the position x = 2.00 cm 1. how far has the electron travelled in meters? 2. The electron has __________ electric potential energy at the new position. 3. Calculate the magnitude of the potential energy at the new position. The charge of an electron is 1.60 x 10-19 C. 4. Determine the initial velocity of the electron given that its speed is two-third of its initial velocity when it reaches its new position. The mass of an electron is 9.11 x 10-31 kg.An air-filled parallel-plate capacitor with a plate separation of 2.95 mm has a capacitance of 100 pF. What is the area of one of the capacitor's plates? Be careful about units. The plate area, A = = What is the magnitude of electric field in the capacitor if it is charged to Q = 6.2 nC? The electric field, E = Units Select an answer ✓ Units Select an answer ✓ What is the energy density that corresponds to this electric field? The energy density, U₁ = Units Select an answer ✓