A proton is released from rest at x = -2.0 cm in a constant electric field with magnitude 1.50 x10^3 N/C, pointing in the positive x-direction. a) Calculate the change in the electric potential energy associated with the proton when it reaches x = 5.0 cm. b) An electron is now fired in the same direction from the same position. What is the change in the electric potential energy associated with the electron if it reaches x = 12.0 cm? c) If the direction of the electric field is reversed and an electron is released from rest at x = 3.0 cm, by how much has the electric potential energy changed when the electron reaches x = 7.0 cm?

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Q: 1) A proton is released from rest at x = -2.0 cm in a constant electric field with magnitude 1.50…

A: Since you have posted a question with a multiple sub parts, we will solve first three sub - parts…

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Q: In the figure, the charge q=3.11×10^−9C. A)Find the electric potential at x=0.650m Express your…

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Q: A particle with a charge of q = 11.0 µC travels from the origin to the point (x, y) = (20.0 cm, 50.0…

A: Given, q=11 μC Points, x= 20 cm= 0.2 m and, y= 50cm= 0.5 m Electric field, E⇀=220i^ V/m So, there is…

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.