Question 2 A projectile is fired in the air from a height of 125 feet. Its velocity (in feet per second) t seconds after launch is f(t), given in the following table.515215169a) How fast is the projectile traveling 15 seconds after launch?b) How far does the projectile move between 5 seconds and 25 seconds.?Estimate 3412.5 feet.c) How far does the projectile move between 0 seconds and 15 seconds?Estimate feet.d) How high is the projectile at 25 seconds? It is(If necessary, round to two decimal places.)feet.Xf(x)feet per second.023410196201502530120 109

As we know that the estimate distance covered by projectile between time a to time b is hL+R2 where h is the time gap given in the data, L is the left sum of the data starting from t=a to t=b-1 class and R is the right sum starting from t=a+1 to t=b values given. As per bertleby guideline I have to solve first three subparts of the question. For answer to others resubmit the question. see below the answer and explanation(a). As per the given infformation we have the projrctile traveling 15 seconds after launch is 169 feet per second.(b). The projectile move between 5 seconds and 25 seconds is 5L+R2=52(215+196+169+150+(196+169+150+120))=52(1365)=3412.5 feet(c). The projectile move between 0 seconds and 15 seconds is 5L+R2=52((234+215+196)+(215+196+169))=3062.5 feet