A program was created to randomly choose customers at a sporting goods store to receive a discount. The program claims 25% of the receipts will get a discount in the long run. The manager of the sporting goods store is skeptical andbelieves the program's calculations are incorrect. She selects a random sample and finds that 22% received the discount. The confidence interval is 0.22 ± 0.04 with all conditions for inference met.Part A: Using the given confidence interval, is it statistically evident that the program is not working? Explain.Part B: Is it statistically evident from the confidence interval that the program creates the discount with a 0.25 probability? Explain.Part C: Another random sample of receipts is taken. This sample is four times the size of the original. Twenty-two percent of the receipts in the second sample received the discount. What is the value of margin of error based on the secondsample with the same confidence level as the original interval?Part D: Using the margin of error from the second sample in part C, is the program working as planned? Explain.

The program was created for a random selection of customers to receive discount in the store.The…

Answered: A program was created to randomly…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose a data set of 4,000 observations (n - 4,000) was analyzed using OLS to examine the factors influencing students' college grade point averages. The regression results are as follows, with standard errors in parentheses: colgpa-1.550 +0.0010 sat-0.03 hspere-0.05 hsize +-0.007 haize (0.00) (0.00006) (0.0007) (0.01) (0.000) where colgpa- GPA in college sat score on the SAT exam hspere -percentile in high school graduating class haize size of graduating class, in hundreds 11-4,000 R-0.254 R²-0.253 -0.45 The predicted college GPA for someone who scored 1,120 on the SAT and graduated in the 27th percentile of his or her 700-person high school graduating class, is Suppose you would like to construct a 95% confidence interval around the expected college GPA for someone with aat 1,120, hapere 27, and haize 7. colga 1853+0.0010 sat (0,01) (0.0000) where colgpa-GPA in college sat0 sat-1,120 0.03 Asperc0-0.05 haize0+ 0.007 haize (0) (0000)
A pharmaceutical company is running tests to see how well its new drug lowers cholesterol. Fourteen adults volunteer to participate in the study. The total cholesterol level of each participant (in mg/dL) is recorded once at the start of the study and then again after three months of taking the drug. The results are given in the following table. Construct a 90% confidence interval for the true mean difference between the cholesterol levels for people who take the new drug. Let Population 1 be the initial cholesterol level and Population 2 be the cholesterol level after three months. Round the endpoints of the interval to one decimal place, if necessary. Total Cholesterol Levels (in mg/dL) Initial Level Level after Three Months 190 192 230 207 206 182 229 199 224 181 195 209 226 214 190 189 224 196 219 206 185 195 208 204 194 198 225 216 Please highlight the answer
A sample of freshman takes a reading comprehension test and their scores are summarized below. Sample scores: 16, 8, 8, 6, 9, 11, 13, 9, 10 a. if the mean for the general population on this test is m=12, can you conclude that this sample is significantly different from the population. Test with a=.05 b. Calculate a 90% confidence interval around your mean.
In a statistics activity, students are asked to determine the proportion of times that a spinning penny will land with tails up. The students are instructed to spin the penny 10 times and record the number of times the penny lands tails up. For one student, it lands tails side up six times. The student will construct a 90% confidence interval for the true proportion of tails up. Are the conditions for inference met? Yes, the conditions for inference are met. No, the 10% condition is not met. No, the randomness condition is not met. No, the Large Counts Condition is not met.
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The dean of students at a large college is interested in learning about their opinions regarding the percentage of first-year students who should be given parking privileges in the main lot. He sends out an email survey to all students about this issue. A large number of first-year students reply but very few sophomores, juniors, and seniors reply. Based on the responses he receives, he constructs a 90% confidence interval for the true proportion of students who believe first-year students should be given parking privileges in the main lot to be (0.71, 0.79). Which of the following may have an impact on the confidence interval, but is not accounted for by the margin of error? response bias O nonresponse bias O sampling variation O undercoverage bias
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I'm having trouble trying to figure out how to work the problem below out. Let’s say that 44 percent of the 1,300 U.S. adults who responded to a poll about marijuana legalization said they support legalization. Let’s also say the margin of error for the results is +/- 3 percentage points. The margin of error tells us there’s a high probability that nationwide support for marijuana legalization falls: The correct interpretation of this confidence interval is:
A sociologist is comparing the proportion of teenage boys who receive a text message at least once an hour to the percentage of teenage girls who do. She has collected data from 150 men and 150 women. Which of the following is not a condition that the sociologist should check before creating a confidence interval for the difference in population proportions?
A random sample of 318 students from a large college were asked if they are planning to visit family during Thanksgiving break. Based on this random sample, a 99% confidence interval for the proportion of all students at this college who plan to visit family during Thanksgiving break is 0.78 to 0.98. Which of the following is the correct interpretation of the confidence interval? options: We are 95% confident that the interval from 0.78 to 0.98 captures the true proportion of all students at this college who plan to visit family during Thanksgiving break. We are 95% confident that the interval from 0.78 to 0.98 captures the true proportion of all students in this sample who plan to visit family during Thanksgiving break. We are 95% confident that the interval from 0.78 to 0.98 captures the true proportion of all students at this college who said they plan to visit family during Thanksgiving break. None of these is correct.

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