A professor at a large university believes that students take an average of 15 credit hours per term. A random sample of 22 students in her class of 250 students reported the following number of credit hours that they were taking:12121213131414141415151516161616161717181921aWhich distribution will you use here? If you use t distribution, give the degree of freedom. If you use z or normal, give the mean and standard deviation. Give the null and alternative hypothesis: bGive the test statistic:Find the p-value: c Decision and Conclusion:

Name: A professor at a large university believes that students take an avera
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Description: A professor at a large university believes that students take an average of 15 credit hours per term. A random sample of 22 students in her class of 250 students reported the following number of credit hours that they were taking:12121213131414141415

(a) Determine the type of distribution used. The type of distribution used is t-distribution since because the population standard deviation is unknown. State the hypotheses. That is, the average credit hours per term equals 15. That is, the average credit hours per term do not equals 15.(b) Obtain the value of the test statistic. Use EXCEL Procedure to obtain values for the given samples. Follow the instruction to obtain the value of mean and SD: Open EXCEL Go to Data>Data Analysis. Choose Descriptive Statistics. Enter the input range as $A$1:$A$23. Check the Labels in the first row. Check the option Summary statistics Click OK. EXCEL output: From the EXCEL output, the value of mean is 15.2273 and the standard deviation is 2.3080. The required value is, Thus, the value of the test statistic is 0.46. Obtain the P-value. Obtain the degrees of freedom: Use Excel to obtain the probability value. Follow the instruction to obtain the P-value: Open EXCEL Go to Formula bar. In formula bar enter the function as“=TDIST” Enter the test statistic 0.46. Enter the degrees of freedom as 21. Enter the tails as 2. Click enter EXCEL output: From the Excel output, the P-value is 0.6502. Thus, the P-value is 0.6502. (c ) The conclusion is obtained as follows: Use the level of significance as 0.05. The P-value is greater than the level of significance. By the rejection rule, do not reject the null hypothesis. That is, do not reject the null hypothesis. Final conclusion: That is, the average credit hours per term do not equals 15.

Answered: A professor at a large university…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A professor at a large university believes that students take an average of 15 credit hours per term. A random sample of 22 students in her class of 250 students reported the following number of credit hours that they were taking:

12	12	12	13	13	14	14	14	14	15	15
15	16	16	16	16	16	17	17	18	19	21

aWhich distribution will you use here? If you use t distribution, give the degree of freedom. If you use z or normal, give the mean and standard deviation. Give the null and alternative hypothesis:

bGive the test statistic:Find the p-value:

c Decision and Conclusion:

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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