A probability distribution for the given experiment is as follows. 0. 1 3 4. P(x) 16 4 8. 4. 16
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![For the experiment described below, let x determine a random variable, and
use your knowledge of probability to prepare a probability distribution.
Four cards are drawn (with replacement) and the number of black cards
is noted.
A probability distribution for the given experiment is as follows.
1
2.
4.
1.
P(x)
16
8.
4
16](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe596597a-c7d6-4d70-9076-bfa8a12feb26%2F16de0a8b-4ad5-43a6-92d8-6df6acbf76d4%2Fdxcfbfk_processed.jpeg&w=3840&q=75)
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- Below is the distribution for a data set. x P(x) 5 0.11 6 0.25 7 0.39 9 0.08 12 0.17 Calculate the mean of the data set from this probability distribution. μ = [two decimal accuracy]Here is a probability distribution: X 2 4 7 10 P(X) 0.3 0.05 0.3 0.35 Find the mean of this distribution. Enter your answer rounded to 2 decimal places. 6.40 Find the standard deviation of this distribution. Enter your answer rounded to 2 decimal places. 2.48 xFind the mean, variance and standard deviation for the probability distribution given below: X -3 3 8 10 P(X) 0.597 0.13 0.215 0.058 A. Mean = B. Variance = C. Standard Deviation =
- Choose an American household at random and let the random variable ?X be the number of cars (including SUVs and light trucks) they own. Given is the probability distribution if we ignore the few households that own more than 5 cars. Number of cars 0 1 2 3 4 5 Probability 0.09 0.36 0.35 0.13 0.05 0.02 About what percentage of households have a number of cars within 2 standard deviations of the mean?You have a uniform distribution whose lowest value is 7 and whose highest value is 15. Find the probability that a randomly selected number from this distribution will be between 9.3 and 10.6.In an experiment on children’'s behavior, children are placed in an area with 3 toys. The chart below gives the probability distribution of the number X of toys the children play with. 4. Toys 1 Probability .06 .35 .28 .31 What are the mean value, variance, and standard deviation for this distribution?
- A customer service center is tracking number of complaints in each week. Let X be the number of complaints in each week. The probability distribution of X is summarized as below. X 0 1 2 3 Probability 0.4 ? 0.15 0.05 Can we be certain that the standard deviation of X is less than 3?..... Sketch the graph of the normal distribution with the indicated probability shaded. O A. B. Oc. OD. u=27 A=27 The normal distribution cannot be used 27 to approximate the binomial distribution. 10 33 44 ent (b) Find the probability that the number of people who say auto racing is their favorite sport is more than 37. asou (Round to four decimal places as needed.) ccess Sketch the graph of the normal distribution with the indicated probability shaded,The probability of a given score range is 0.4821. The bottom of the score range is the average (z=0). What is the z-score for the upper end of the distribution?
- Find the mean, variance and standard deviation for the probability distribution given below. Give your answers to at least 4 decimal places. -4 12 10 P(X) 0.565 0.103 0.212 0.12 A. Mean = B. Variance = C. Standard Deviation = %3D .. 東A fitness center bought a new exercisemachine called the Mountain Climber. Theydecided to keep track of how many people used themachine over a 3-hour period. Find the mean, variance,and standard deviation for the probability distribution.Here X is the number of people who usedthe machine. X 0 1 2 3 4 P(X) 0.1 0.2 0.4 0.2 0.1A survey of almost 44,000 two-child families yielded the accompanying table. The probability distribution of x, the number of boys in a two-child family is given below. Find E(x) and give a practical interpretation of its value. Gender Configuration Proportion D Girl-girl (GG) Boy-girl (BG) Girl-Boy (GB) 0.215 0.267 0.256 P(x) 0.215 0.523 0.262 Boy-boy (BB) 0.262 Choose the correct answer below and fill in the answer box to complete your choice. (Round to three decimal places as needed.) O A. If a very large number of households were sampled, on average, there would be E(x) = boys. O B. If a very large number of two-child households were sampled, on average, there would be E(x) = boys. of getting a family with a boy. %3D O C. If a very large number of two-child households were sampled, there would be a probability of E(x) = O D. In the sample of 44,000 households, each household had E(x) = boys.
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