Using historical records, a manufacturing firm has developed the following probability distributionfor the number of days required to get components from its suppliers. The distribution is shownhere, where the random variable x is the number of days.X45678P(x)0.170.380.310.1050.035 Using historical records, a manufacturing firm has developed the following probability distributionfor the number of days required to get components from its suppliers. The distribution is shownhere, where the random variable x is the number of days.X45678P(x)0.170.380.310.1050.035a. The average lead time is 5.455b. The coefficient of variation isnot round. Do not include % in your answer.)days. (Type the entire number, do not round.)%. (Round to two decimal places as needed. Do

From the provided information,The probability distribution table is as follow:xP…

Answered: Using historical records, a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A deck of four (4) cards has exactly one (1) color printed on each face – blue, yellow, red, or green. You have two (2) identical decks of this type. In this game, you randomly select a card from each of the two decks. Your score is the number of blue cards drawn – refer to this quantity as X. The probability distribution is below: X P(X) 0 0.5625 1 0.375 2 0.0625 What is the average number of blue cards drawn? What is the probability that at most one blue card is drawn?
Refer to this figure to answer number 8- 10. The table below show the probability distribution of number of face mask sold per day. 1 2 3 5 6. 7 8. 10 0.07 P(x) P/x) 0.16 0.07 0.1 0.09 0.1 0.07 0.08 0.1 0.17 0.56 1.4 1.96 5.76 11.56 0.16 0.40 0.16 0.14 0.3 0.36 0.5 0.42 0.56 0.9 1.7 X-U -4.6 -3.6 -2.6 -1.6 -0.6 0.4 2.4 3.4 4.4 (x-)A2 (x-u)A2 *P(x) 21.16 12.96 6.76 2.56 0.36 0.16 19.36 3.39 0.91 0.68 0.23 0.04 0.01 1.16 3.29 8. What is ExP(x) =? A. 5.6 B. 6.5 C.7 D. 8 9. What is a? = E[(x - 4) P(x)] A. 5.9 %3D В. 8.6 С. 10.25 D. 11.35 10. If the standard deviation of the variance of problem number 9 is 3.20156, then how do we get the value of standard deviation given the value of variance? A. Vo? B. Va C. uP(x) D. o ololo-
Answer 1&2 plz
Consider the population described by the probability distribution shown below. The random variable is observed twice with independent observations, as shown below. Complete parts a and b. Full data set X 3 4 5 6 p(x) 0.2 0.2 0.3 0.3 a. Complete the sampling distribution table. Type the medians in ascending order. Median 3 5 6 Probability || 0.08 0.24 (Simplify your answers. Type integers or decimals.) 4 0.18 (…) 0.04 Sample |3,3 3,4 3,5 Probability 0.04 0.06 Sample 5,3 5.4 Probability 0.06 0.06 3,6 4,3 0.06 0.04 4,4 4,5 4,6 0.04 0.06 0.06 5,5 5.6 6,3 6,4 0.09 0.09 0.06 0.06 6,5 6,6 0.09 0.09
Find the mean and variance of the following discrete random variable distribution.? ?(?)0 0.35 1 0.45 2 0.16 3 0.04
Below is a table of the estimated number of cell phones per household in a rural town. The number of cell phones, x, can be approximated by the following probability distribution.
A deck of four (4) cards has exactly one (1) color printed on each face – blue, yellow, red, or green. You have two (2) identical decks of this type. In this game, you randomly select a card from each of the two decks. Your score is the number of blue cards drawn – refer to this quantity as X. The probability distribution is below: X P(X) 0 0.5625 1 0.375 2 0.0625 1. If we replaced the yellow card in the first deck with another blue card, what would be the probability of drawing two blue cards? 2. If we replaced the yellow card in the first deck with another blue card, what distribution would the variable X follow?
What is the probability a student will take 2 or 3 classes in a semester?
A survey of almost 44,000 two-child families yielded the accompanying table. The probability distribution of x, the number of boys in a two-child family is given below. Find E(x) and give a practical interpretation of its value. Gender Configuration Proportion D Girl-girl (GG) Boy-girl (BG) Girl-Boy (GB) 0.215 0.267 0.256 P(x) 0.215 0.523 0.262 Boy-boy (BB) 0.262 Choose the correct answer below and fill in the answer box to complete your choice. (Round to three decimal places as needed.) O A. If a very large number of households were sampled, on average, there would be E(x) = boys. O B. If a very large number of two-child households were sampled, on average, there would be E(x) = boys. of getting a family with a boy. %3D O C. If a very large number of two-child households were sampled, there would be a probability of E(x) = O D. In the sample of 44,000 households, each household had E(x) = boys.
K The following data represent the number of drivers involved in a fatal crash in 2016 in various light and weather conditions. Complete parts (a) through (c) below. Click the icon to view the data for fatal crashes in 2016. (a) Among fatal crashes in unknown weather conditions, what is the probability that a randomly selected fatal crash occurs when it is dawn/dusk? The probability that a randomly selected fatal crash in unknown weather conditions occurs when it is dawn/dusk is approximately. (Round to three decimal places as needed.) Data table Weather Daylight Dark, but Lighted 5875 497 51 54 255 Normal Rain Snow/Sleet Other Unknown 14,307 875 219 125 810 (...) Dark 8151 681 156 220 548 Dawn/Dusk Other 1183 87 40 71 65 8 2 9 133 X
A car service centre studies the record that shows the number of cars serviced per day. They uses the data to calculate the relative frequencies and obtains the following probability distribution. Number of cars, x P(X = x) 1 3 4 5 0.1 0.1 0.2 0.3 0.2 0.1 Find the probability that two or less cars are serviced each day. O 0.6 O 0.3 О 02 O 0.4

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