Am I doing part A correctly? and can you help me explain part B! a. A positively charged rod of length L, and uniform line charge density A, is placed along they-axis as shown in the drawing. The origin of the coordinate system is located at the centerof the rod. Calculate the electric potential (voltage) at point P on the x axis.{Express your answer in terms of L, A, and x.)b. Now a point charge, q, is brought in from very, very far away, and then placed at point P,while the charged rod remains fixed in position.What is the change in electric potential energy of the system?{Express your answer in terms of L, λ, q, and x.)O EXCEPTIONS,y axis→→→x axis**X a) dQ = AdyVp= SudakdQrdEpK Ady = (FK Idy√x²+y²Yi √√ x² + y²= + ½/2/2(KX) In (y + √ √²+y²) | ₁ = = 2 2=-1/₂ √x² + y²= (K²) [In( ½ + ({√(4)³+x²) − \n(− ½ + (√(-3)*+x²))]=(K2) In[/=/= +1/2 + √√( ²2 ) ² + y ²- 2²/2/2 + √√√( ²2 ) ² + y ²]3y axis↑(0,4/2)>_r=√x² + y²Di D***4/2кадаг дуdyC0dep→→→x axisنیا

The calculation/derivation in the attached picture is completely correct.but in the last step you…

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