2. (R2) Certain fish, such as the Nile fish (Gr thereby producing the electric field in the water around them. This field creates a pot of a few V between the head and tail, which in turn causes current to flow into the ca seawater. As the fish swims it passes near objects that have resistivities different from seawater, which in turn causes the current to very cells in the skin of the fish are sens current and can detect changes in it. The changes in the current allow the fish to navi electric field is weak far from the fish, we shall consider the only the field running dire head to the tail. We can model the seawater through which the field passes as a cond area 1.0 cm? and having a potential difference of 3.0 V across its ends. The length of t 20 cm, and the resistivity of seawater is 0.13 Q-m. a. How large is the current through the tube of seawater? b. Suppose the fish swims next to an object that is 10 cm long and 1.0 cm2 in cros and has a half the resistivity of seawater. This object replaces seawater for half the tube what is the current through the tube now? How long large is the chan that the fish must detect? (Hint: how are this object and the remaining water in connected in series or in parallel?)
2. (R2) Certain fish, such as the Nile fish (Gr thereby producing the electric field in the water around them. This field creates a pot of a few V between the head and tail, which in turn causes current to flow into the ca seawater. As the fish swims it passes near objects that have resistivities different from seawater, which in turn causes the current to very cells in the skin of the fish are sens current and can detect changes in it. The changes in the current allow the fish to navi electric field is weak far from the fish, we shall consider the only the field running dire head to the tail. We can model the seawater through which the field passes as a cond area 1.0 cm? and having a potential difference of 3.0 V across its ends. The length of t 20 cm, and the resistivity of seawater is 0.13 Q-m. a. How large is the current through the tube of seawater? b. Suppose the fish swims next to an object that is 10 cm long and 1.0 cm2 in cros and has a half the resistivity of seawater. This object replaces seawater for half the tube what is the current through the tube now? How long large is the chan that the fish must detect? (Hint: how are this object and the remaining water in connected in series or in parallel?)
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Transcribed Image Text:2. (R2) Certain fish, such as the Nile fish (Gnathonemus), concentrate their charges in their head and tail
thereby producing the electric field in the water around them. This field creates a potential difference
of a few V between the head and tail, which in turn causes current to flow into the conducting
seawater. As the fish swims it passes near objects that have resistivities different from that of the
seawater, which in turn causes the current to very cells in the skin of the fish are sensitive to this
current and can detect changes in it. The changes in the current allow the fish to navigate. Since the
electric field is weak far from the fish, we shall consider the only the field running directly from the
head to the tail. We can model the seawater through which the field passes as a conducting tube of
area 1.0 cm? and having a potential difference of 3.0 V across its ends. The length of the fish is about
20 cm, and the resistivity of seawater is 0.13 Q-m.
a. How large is the current through the tube of seawater?
b. Suppose the fish swims next to an object that is 10 cm long and 1.0 cm² in cross sectional area
and has a half the resistivity of seawater. This object replaces seawater for half the length of
the tube what is the current through the tube now? How long large is the change in current
that the fish must detect? (Hint: how are this object and the remaining water in the tube
connected in series or in parallel?)
20cm
AV= 3.ØV
resistenc
seqpectt =
E3 S21 - 2
Transcribed Image Text:2. (R2) Certain fish, such as the Nile fish (Gnathonemus), concentrate their charges in their head and tail
thereby producing the electric field in the water around them. This field creates a potential difference
of a few V between the head and tail, which in turn causes current to flow into the conducting
seawater. AS the fish swims it passes near objects that have resistivities different from that of the
seawater, which in turn causes the current to very cells in the skin of the fish are sensitive to this
current and can detect changes in it. The changes in the current allow the fish to navigate. Since the
electric field is weak far from the fish, we shall consider the only the field running directly from the
head to the tail. We can model the seawater through which the field passes as a conducting tube of
area 1.0 cm2 and having a potential difference of 3.0 V across its ends. The length of the fish is about
20 cm, and the resistivity of seawater is 0.13 Q-m.
a. How large is the current through the tube of seawater?
b. Suppose the fish swims next to an object that is 10 cm long and 1.0 cm² in cross sectional area
and has a half the resistivity of seawater. This object replaces seawater for half the length of
the tube what is the current through the tube now? How long large is the change in current
that the fish must detect? (Hint: how are this object and the remaining water in the tube
connected in series or in parallel?)
20cm
:0cm2
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