A positive charge + q is located at the point x = 0, y = -a, and a negative charge -q is at the point x = 0, y = + a. a) Obtain an expression for the potential V at the points on the x-axis as a function of the y coordinate. Consider V equal to zero at a infinite distance from charges. b) Create the graph of V in points on the y-axis as a function of y in the interval from y = -4a to y = + 4a. c) Show that for y 7 a, the potential at a point on the positive axis y is given by V = - (1 4pP0) 2qa y2 . d) What are the answers to parts (a) and (c) if the two charges are exchanged that + q is in y = + a and -q is in y = -a?
A positive charge + q is located at the point x = 0, y = -a, and a negative charge -q is at the point x = 0, y = + a. a) Obtain an expression for the potential V at the points on the x-axis as a function of the y coordinate. Consider V equal to zero at a infinite distance from charges. b) Create the graph of V in points on the y-axis as a function of y in the interval from y = -4a to y = + 4a. c) Show that for y 7 a, the potential at a point on the positive axis y is given by V = - (1 4pP0) 2qa y2 . d) What are the answers to parts (a) and (c) if the two charges are exchanged that + q is in y = + a and -q is in y = -a?
Related questions
Question
A positive charge + q is located at the point x = 0, y = -a,
and a negative charge -q is at the point x = 0, y = + a.
a) Obtain an expression for the potential V at the points on the
x-axis as a function of the y coordinate. Consider V equal to zero at a
infinite distance from charges. b) Create the graph of V in points
on the y-axis as a function of y in the interval from y = -4a to y = + 4a.
c) Show that for y 7 a, the potential at a point on the positive axis y is given by V = - (1 4pP0) 2qa y2
. d) What are the answers to parts (a) and (c) if the two charges are exchanged
that + q is in y = + a and -q is in y = -a?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 8 steps with 2 images