A population of values has a normal distribution with urandom sample of size n = 11.200 and o = 31.9. You intend to draw aFind the probability that a single randomly selected value is less than 226.9.P(X < 226.9) =|Find the probability that a sample of size n = 11 is randomly selected with a mean less than 226.9.P(M < 226.9) =Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scoresor z-scores rounded to 3 decimal places are accepted.

Answered: A population of values has a normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Question

A population of values has a normal distribution with u
random sample of size n = 11.
200 and o = 31.9. You intend to draw a
Find the probability that a single randomly selected value is less than 226.9.
P(X < 226.9) =|
Find the probability that a sample of size n = 11 is randomly selected with a mean less than 226.9.
P(M < 226.9) =
Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores
or z-scores rounded to 3 decimal places are accepted.

Expert Solution

Step 1

The probability that a single randomly selected value is less than 226.9 is,

$\begin{array}{rcl} P (X < 226.9) & = & P (\frac{X - μ}{σ} < \frac{226.9 - 200}{31.9}) \\ = & P (z < \frac{26.9}{31.9}) \\ = & P (z < 0.843) \end{array}$

The probability of z less than 0.843 can be obtained using the excel formula “=NORM.S.DIST(0.843,TRUE)”. The probability value is 0.8004.

The required probability value is,

$\begin{array}{rcl} P (X < 226.9) & = & P (z < 0.843) \\ = & 0.8004 \end{array}$

Thus, the probability that a single randomly selected value is less than 226.9 is 0.8004.

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions