The mean amount of time it takes a kidney stone to pass is 16 days and the standard deviation is 6 days.Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to4 decimal places where possible.a. What is the distribution of X? X - N(b. Find the probability that a randomly selected person with a kidney stone will take longer than 12 days topass it.c. Find the minimum number for the upper quarter of the time to pass a kidney stone.days.

Given that the mean amount of time it takes a kidney stone to pass is 16 days and the standard…

Answered: The mean amount of time it takes a…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Susan jogs to the park each day and the trip takes an average of µ = 22 minutes. The distribution of jog times is approximately normal with a standard deviation of σ = 10 minutes. For a randomly selected day, what is the probability that Susan’s jog to the park will take less than 16 minutes? Select one: a. 0.2743 b. 0.8957 c. 0.3236 d. 0.7554
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1463 and the standard deviation was 314. The test scores of four students selected at random are 1870, 1220, 2190, and 1340. Find the z-scores ← that correspond to each value and determine whether any of the values are unusual. F1 The z-score for 1870 is (Round to two decimal places as needed.) The z-score for 1220 is. (Round to two decimal places as needed.) The z-score for 2190 is (Round to two decimal places as needed.) The z-score for 1340 is. (Round to two decimal places as needed.) Which values, if any, are unusual? Select the correct choice below and, if necessary, fill in the answer box within your choice. OA. The unusual value(s) is/are. (Use a comma to separate answers as needed.) OB. None of the values are unusual. F2 80 F3 000 000 F4 F5 ^ MacBook Air F6 & A D F7 * DII F8 DD F9 ) J 운 F10 I a F11 + Next F12 delete
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P, the 11th percentile. This is the bone density score separating the bottom 11% from the top 89%. Which graph represents P ? Choose the correct graph below. O A. O B. OD. P11 P11 P11 P11 The bone density score corresponding to P1 is (Round to two decimal places as needed.) Click to select your answer(s). APR tv MacBook Air F9 F10 LLA 20 F3 F6 F8 F4 F5 F1 F2 & #3 7 8. %24
Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 240 feet and a standard deviation of 48 feet. Let X = distance in feet for a fly ball. If one fly ball is randomly chosen from this distribution, what is the probability that this ball traveled fewer than 186 feet? (Round your answer to four decimal places.) ch6#4
Round answers to 4 decimal places. Draw graphs and include functions 2. The scores on a standardized exam are normally distributed with a mean of 74 and standard deviation of 7.32. Let X = one exam score. a. Write the distribution of X b. Find the probability a randomly selected exam has a score higher than 80. c. Find P97
K Assume that adults have IQ scores that are normally distributed with a mean of μ = 105 and a standard deviation o=20. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.)
Suppose baby kittens' weights are normally distributed with a mean of 11.4 and a standard deviation of 2.1. The Z-score tells you how many units above the average (if Z-score is positive) or below the average (if Z- Score is negative) any particular baby kitten's weight is. Find the baby kitten weight that corresponds to the following Z-scores. Use the formula Z where u is the mean, o is the standard deviation, and X is the baby kitten weight. a. Z = = 0.07, X = b. Z = 1.63, X =
Round answers to 4 decimal places. Draw graphs and include functions where appropriate.2. The scores on a standardized exam are normally distributed with a mean of 74 and standard deviation of 7.32. Let X = one exam score.a. Write the distribution of Xb. Find the probability a randomly selected exam has a score higher than 80.c. Find P97
Round answers to 4 decimal places. Draw graphs and include functions where appropriate.1. According to a study, the height for Asian adult males is normally distributed with an average of 66 inches and a standard deviation of 2.5 inches. Suppose one Asian adult male is randomly chosen. Let X = height of the individual.a.Write the distribution of Xb. Find the probability that the person is between 65 and 69 inches.c. The middle 40% of heights fall between what two values?
SubPArt. Pls answer the rest
Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 2) The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 5478 .5517 .5557 .5596 ,5636 ,5675 .5714 .5753 0.2 .5793 .5832 5871 5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.5 .6915 6950 .6985 7019 .7054 .7088 7123 7157 .7190 .7224 0.6 .7257 .7291 7324 7357 7389 7422 7454 7486…
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)

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