A popular commercial solvent mixture is made up of several aliphatic and aromatic hydrocarbons. You are tasked with estimating its properties assuming toluene is the main component. You are expected to solve this problem in two ways, a) using the Lee-Kesler diagrams to estimate the following quantities. A) The molar volume at the critical point. B) The molar volume in the liquid phase at T = 110C and P = 10 bar. C) The molar volume in the vapor phase at T = 310C and P = 20 bar. D) The change in molar enthalpy when toluene is heated and compressed from T = 110C and P = 10 bar to T = 310 C and P = 20 bar. Note: you may use PREOS and other Excel spreadsheets, but only as a calculator

Introduction to Chemical Engineering Thermodynamics
8th Edition
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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A popular commercial solvent mixture is made up of several aliphatic and aromatic hydrocarbons.
You are tasked with estimating its properties assuming toluene is the main component.
You are expected to solve this problem in two ways,

a) using the Lee-Kesler diagrams to estimate the following quantities.

A) The molar volume at the critical point.
B) The molar volume in the liquid phase at T = 110C and P = 10 bar.
C) The molar volume in the vapor phase at T = 310C and P = 20 bar.
D) The change in molar enthalpy when toluene is heated and compressed from T = 110C and
P = 10 bar to T = 310 C and P = 20 bar.
Note: you may use PREOS and other Excel spreadsheets, but only as a calculator

Expert Solution
Step 1: Critical Point of Toluene

Since you have posted multiple sub-parts, I can only solve the first three subparts according to the guidelines of Bartleby.


F o r space T o u l e n e
c r i t i c a l space t e m p space left parenthesis T subscript C right parenthesis space equals space 591.8 space K
c r i t i c a l space p r e s s u r e space left parenthesis P subscript c right parenthesis space equals space 41.06 space b a r
a c c e n t r i c space f a c t o r space space left parenthesis omega right parenthesis space equals space 0.262

Using the Lee-Kesler diagram, The molar volume at the critical point is

M o l a r space v o l u m e space left parenthesis V subscript C right parenthesis space equals space 316 space fraction numerator c m cubed over denominator m o l end fraction


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