A polyethylene bar having rectangular cross section with a width 6.36 in. and depth 6 in. is centered inside a hollow steel square section with side dimension of 7 in. The polyethylene bar is then compressed by an axial force P. 0.3 in. 6 in. 7 in. 6.36 in 7 in. At what value of the force P will the gap between the polyethylene bar and the steel tube be closed for the first time in one dimension? For polyethylene, assume E = 200 ksi and v = 0.4. Assume that the material behaves linearly elastically. (Enter the magnitude in kips.) kips What is the remaining gap between the polyethylene bar and the steel tube in the other dimension? (Enter the distance in inches between the side of the polyethylene bar and the closest side of the steel section.)

A polyethylene bar having rectangular cross section with a width 6.36 in. and depth 6 in. is centered inside a hollow steel square section with side dimension of 7 in. The polyethylene bar is then compressed by an axial force P. 0.3 in. 6 in. 7 in. 6.36 in 7 in. At what value of the force P will the gap between the polyethylene bar and the steel tube be closed for the first time in one dimension? For polyethylene, assume E = 200 ksi and v = 0.4. Assume that the material behaves linearly elastically. (Enter the magnitude in kips.) kips What is the remaining gap between the polyethylene bar and the steel tube in the other dimension? (Enter the distance in inches between the side of the polyethylene bar and the closest side of the steel section.)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Compound axial member ABC has a uniform diameter of d = 2.9 in. Segment (1) is an aluminum [E₁ = 10,000 ksi] alloy and segment (2) is a copper [E₂ = 17,000 ksi] alloy. The lengths of segments (1) and (2) are L₁ = 90 in. and L₂ = 130 in., respectively. Determine the force P required to stretch compound member ABC by a total of 0.30 in. L₁ P L2 Aluminum B Copper CP A Answer: P= i kips
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