A poll was conducted in a very small community in country X to see if residents are for or against a new policy that requires them to wear a mask. A total of 500 persons were surveyed. Of the 500 surveyed 200 are against wearing a mask. Compute a 90% confidence interval for the true percent of residents who are against the new policy and interpret the confidence interval.

Q: A poll of 827 students at Alpha State College found that 61% of those polled preferred a quarter…

A: Given that Sample size n = 827 Sample proportion of students who prefer a quarter system = 0.61 The…

Q: Suppose a consumer advocacy group wants to conduct a survey to find if the proportion of consumers…

A:

Q: In a survey of 1250 U.S. adults, 363 said that their favorite sport to watch is football. The 95%…

A:

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: In a study, 110 children of a certain race in a certain city were randomly assigned to one of two…

A: From the table contingency table we can see that there are 17+39 = 56 children who did not go to…

Q: researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 520…

A:

Q: A sample of 500 nursing applicants included 80 men.  Determine the 95% confidence interval for the…

A:

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: Item 3 (Large-sample test about the proportion) Use Critical Value Method by showing the steps and…

A: Given : P(popu. prop.)=68.6%=0.686 x(respondents who owned their homes)=92 n(sample size)=150…

Q: The 90% confidence interval is from to. (Round to three decimal places as needed.)

A: A poll of 1030 adults in a country was conducted by telephone. Of those surveyed, 139 had…

Q: In a random sample of 500 adults, 410 described themselves as vegetarians. Construct a 95%…

A: We have been provided with the following information about the adults who describe themselves as…

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: The following table shows the results of a survey in which 1017 adults from the United States, 1060…

A: (1)

Q: (c) Find or estimate the P-value of the sample test statistic. O P-value > 0.100 O 0.050 a, we fail…

A:

Q: A poll of 5000 residents in Brazil, Canada, China, France, Malaysia, South Africa, and the United…

A: From the provided information, Sample size (n) = 5000 805 of the responses, was doctors, nurses, and…

Q: Leana is interested in the proportion of people who live in her area who own a dog. She randomly…

A: Suppose p is the population proportion of people who live within one mile of Person L’s home who own…

Q: Of the 1,000 people, 550 people used company s's smartphone and 460 people used company a's…

A: Given: n= 1000 ,x= 550.0 At 95.0 % confidence level , z score= 1.96 Need to find confidence…

Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: In a study, 110 children of a certain race in a certain city were randomly assigned to one of two…

A: There are two independent samples which are Preschool and No Preschool. We have to construct 95%…

Q: Assume a nationwide random survey of 800 adults asked about attitudes toward “alternative medicine”…

A: We have given that,  Sample size (n) = 800 and Favorable cases (X) =448 Then,  We will find the 99%…

Q: According to a recent Government survey, 6% of all merchandise sold in the U.S. gets returned.  A…

A: It is given that sample size (n) is 80 and x is 12.

Q: The ability to find a job after graduation is very important to GSU students as it is students at…

A: Sample size n=3878Favorable cases x=3241

Q: Calculate a 95% confidence interval for the proportion of clients that would recommend the company

A: Concept: The sample proportion of the sample of size n can be defined as:  Here, X = Total number…

Q: A survey of 95 families showed that 40 of the families owned at least one tv. a. Find the 90%…

A: Number of families in a sample n =95 Let X be the number of families owned at least one tv = 40 p =…

Q: In a survey of 32 students at a local high school, 17 support changing the schools mascot. Find the…

A:

Q: CNN is conducting a poll, and wants to produce a 90% confidence interval for the proportion of all…

A: a) Given that 602 randomly selected Ne Yorkers surveyed, 394 were in favor of the initiative.…

Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: In a survey of 952 respondents, 620 of them voted in a recent election. Find a 95% confidence…

A: From the provided information, Number of respondents (n) = 952 Number of respondents who voted in a…

Q: study of 30 college students showed that 25 are binge watching series. Find a 95% confidence…

A: given data  n = 30  x = 25 95% ci for p  = ?

Q: A recent survey of 1,000 people found that 90% of Americans support background checks for purchasing…

A:

Q: The 99% confidence interval for the proportion of college students that prefer to work for a large…

A: We have given that that prefer to work for a large company is Sample size n =1500 Sample proportion…

Q: A surprising fact indicates that a small proportion of teens use a password on their mobile device.…

A: Given data,n=120x=56p=x/n =0.47z-value at 90% confidence interval is Zc=1.645

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.