A point P is selected at random from segment AG. What is the probability that P is on segment AD? A B D E F G + -3 -2 -1 0 1 2 3

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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### Probability Question on Segment Selection

#### Problem Statement:
A point \( P \) is selected at random from segment \( AG \). What is the probability that \( P \) is on segment \( AD \)?

#### Diagram Explanation:
The diagram is a number line with labeled points and their corresponding positions:
- \( A \) at \(-3\)
- \( B \) at \(-2\)
- \( C \) at \(-1\)
- \( D \) at \(0\)
- \( E \) at \(1\)
- \( F \) at \(2\)
- \( G \) at \(3\)

The diagram shows a straight line with these points marked. 

#### Answer Choices:
The possible probabilities are given as:
- a) \( 43\% \)
- b) \( 50\% \)
- c) \( 57\% \)
- d) \( 67\% \)

When working through this problem, note that:
- Segment \( AG \) spans from \( -3 \) to \( 3 \), giving a total segment length of \( 6 \).
- Segment \( AD \) spans from \( -3 \) to \( 0 \), giving a segment length of \( 3 \).

To find the probability that \( P \) is on segment \( AD \), we calculate:
\[ \text{Probability} = \frac{\text{Length of segment } AD}{\text{Length of segment } AG} = \frac{3}{6} = \frac{1}{2} = 50\% \]

#### Correct Answer:
- b) \( 50\% \)
Transcribed Image Text:### Probability Question on Segment Selection #### Problem Statement: A point \( P \) is selected at random from segment \( AG \). What is the probability that \( P \) is on segment \( AD \)? #### Diagram Explanation: The diagram is a number line with labeled points and their corresponding positions: - \( A \) at \(-3\) - \( B \) at \(-2\) - \( C \) at \(-1\) - \( D \) at \(0\) - \( E \) at \(1\) - \( F \) at \(2\) - \( G \) at \(3\) The diagram shows a straight line with these points marked. #### Answer Choices: The possible probabilities are given as: - a) \( 43\% \) - b) \( 50\% \) - c) \( 57\% \) - d) \( 67\% \) When working through this problem, note that: - Segment \( AG \) spans from \( -3 \) to \( 3 \), giving a total segment length of \( 6 \). - Segment \( AD \) spans from \( -3 \) to \( 0 \), giving a segment length of \( 3 \). To find the probability that \( P \) is on segment \( AD \), we calculate: \[ \text{Probability} = \frac{\text{Length of segment } AD}{\text{Length of segment } AG} = \frac{3}{6} = \frac{1}{2} = 50\% \] #### Correct Answer: - b) \( 50\% \)
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