A plastic rod is bent into the quarter circle of radius R as shown below. A total positive ch y distributed along the rod. In terms of the given quantities, what is the linear charge density A?
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- Consider a charge disk with uniform surface charge density ?? as shown in the figure.The radius of the disk is R.A line of positive charge is formed into a semicircle of radius R. The charge per unit length along the semicircle is constant and denoted by η. Calculate the total force on a charge of Q placed at the curvature center of the half-ring?A charge of uniform linear density 3.41 nC/m is distributed along a long, thin, nonconducting rod. The rod is coaxial with a long conducting cylindrical shell with an inner radius of 5.43 cm and an outer radius of 12.4 cm. What is the surface charge density on the inner surface of the shell?
- A charged nonconducting rod, with a length L and a cross-sectional area A, lies along the positive side of an x axis with one end at the origin. The volume charge density p is charge per unit volume. Express your answer in terms of the given variables using e to represent the elementary charge. (a) How many excess electrons are on the rod if p is uniform? na = (b) How many excess electrons are on the rod if p is nonuniform, with a value given by p=bx^2, where b is a constant with the appropriate units? nb =A -198.7 mC charge is placed at the center of a hollow conducting sphere. Find the Charge density (in C/m²) on the outside of the sphere if its radius is 6.47 cm and if it Contains zero net charge.Please write you answers neatly and answer all parts.
- An arrangement of positive charge forms a semicircular structure with radius R, depicted in the illustration. The linear charge density along the semicircle is given by the equation A Xocose. The aggregate charge on the semicircle is Q. Determine the complete force exerted on a charge of q situated at the central point P. = R P xNeed this with explanationBelow is a solid sphere of insulating materials (meaning that once placed, charge will not move around even when it feels a force). This sphere has a changing charge density given by the equation below. This tells you that there is more charge near the outer edges (when r is larger) then near the center (when r is small) since the charge density is proportional to r^2. In the image R is the total radius of the sphere and r is the distance from the center you will be asked about. There values are below. You have to calculate the amount of charge enclosed with the radius of r to find the electric field. You'll need to integrate to do this - that's where the charge density equation below will be used. Use Gauss's Law to find the Electric Field magnitude at a distance r from the center of the sphere. Make sure to think about charge enclosed and how to find it. It is a little more complicated in this problem. Be careful with your 2 radial values (R and r).
- An irregular neutral conductor has a hollow cavity inside of it and is insulated from its surroundings. An excess charge of 22.0 nC is sprayed onto this conductor. a. Find the charge on the inner surface of the conductor. b. Find the charge on the outer surface of the conductor. c. Without touching the conductor, a charge of -15.0 nC is inserted into the cavity through a small hole in the conductor. Find the charge on the inner surface of the conductor in this case. d. Find the charge on the outer surface of the conductor in this case.PlzA -2.87 µC charge is placed at the center of a conducting spherical shell, and a total charge of +8.70 µC is placed on the shell itself. Calculate the total charge on the outer surface of the conductor.